Ta có:\(\frac{2x-9}{240}=\frac{39}{40}\Rightarrow\frac{2x-9}{240}=\frac{234}{240}\)

=>2x-9=234

=>2x=234+9

=>2x=243

=>x=243:2

=>x=121,5

Mà x là số nguyên nên không có x thỏa mãn

\(\frac{2x-9}{240}=\frac{39}{80}\Leftrightarrow\left(2x-9\right).80=240.39\)

\(2x-9=\left(240.39\right):80\)

\(2x-9=117\)

\(2x=126\)

\(x=63\)

2x-9/240=39/80

hay 39.3/240=2x-9/240

nên 117=2x-9

      x=63

2x-9/240=39/80

=>2x-9/240=117/240

=>2x-9=117

=>2x=117+9

=>2x=126

=>x=126:2

=>x=63

2x-9 / 240 = 39 / 80 

2x-9 / 240 = 117 / 240 

2x - 9 = 117 

2x = 117 + 9 

2x = 126 

x = 126 : 2 

x = 63 

Vậy x = 63 

\(\frac{2x-9}{240}=\frac{39}{80}\)

\(\Rightarrow\frac{2x-9}{240}=\frac{117}{240}\)

\(\Rightarrow2x-9=117\)

\(\Rightarrow2x=117+9\)

\(\Rightarrow2x=126\)

\(\Rightarrow x=126:2\)

\(\Rightarrow x=63\)

Vậy \(x=63\)

Chúc bạn học tốt !!!

2x - 9 / 240 = 39/ 80

=> ( 2x - 9 )  ,. 80 = 240 . 39
=> ( 2x - 9 ) . 80 = 9360

=> ( 2x - 9 ) = 9360 : 80

=> ( 2x - 9 ) = 117

=> 2x = 117 + 9

=> 2x = 126

=> x= 126 : 2

=> x = 63

nó phải có = bao nhiêu thì mới ra kết quả bạn ạ 

\(\dfrac{2x-9}{240}\) \(=\) \(\dfrac{39}{80}\) \(\Leftrightarrow\) \(\left(2x-9\right)\) \(.80\) \(=\) \(240.39\)

\(2x\) \(-\) \(9\) \(=\) ( \(240\) \(.\) \(39\) ) \(:\) \(80\)

\(2x\) \(-\) \(9\) \(=\) \(117\)

\(2x\) \(=\) \(126\)

\(x\) \(=\) \(63\) 

$x$ $=$ $63$ 

Ta có: \(\frac{2x-9}{240}=\frac{39}{80}\)

=> \(\frac{2x-9}{240}=\frac{117}{240}\)

=> 2x-9 = 117

=> 2x = 117+9

=> 2x = 126

=> x = 126:2

=> x = 63

Ta có: \(\frac{2x-9}{240}=\frac{39}{80}\)

=> \(\frac{2x-9}{240}=\frac{156}{240}\)

=> 2x-9 = 156

=> 2x = 156+9

=> 2x = 165

=> x = 82,5

ủa cái này hình như bn lạc lõn gì đấy trả lời r mà ?

\(\Leftrightarrow80\left(2x-9\right)=240\times39\)

\(\Leftrightarrow160x-720=9360\)

\(\Leftrightarrow160x=9360+720\)

\(\Leftrightarrow160x=10080\)

\(\Leftrightarrow x=63\)

MSC (mẫu số chung): 240

Quy đồng mẫu 2 vế và khử mẫu ta được:

2x - 9 = 117

     2x = 117 + 9 = 126

       x = 126 : 2 = 63

\(\dfrac{2x-9}{240}=\dfrac{39.3}{240}\Leftrightarrow2x-9=117\Leftrightarrow x=\dfrac{117+9}{2}=\dfrac{126}{2}=63\)

\(\frac{2x-9}{240}=\frac{39}{80}\)

\(\Rightarrow\left(2x-9\right).80=240.39\)

       \(160x-720=9360\)

       \(160x=9360+720\)    

       \(160x=10080\)

               \(x=10080:160\)

               \(x=63\)

Vậy x=63

1. Ta có : \(C=\frac{1010}{1008\cdot8-994}=\frac{1010}{\left(1010-2\right)\cdot8-994}=\frac{1010}{1010\cdot8-16-994}\)

\(=\frac{1010}{1010\cdot8-1010}=\frac{1010}{1010\left(8-1\right)}=\frac{1}{7}\)

\(D=\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{1\cdot3\cdot6+2\cdot6\cdot12+3\cdot9\cdot18+5\cdot15\cdot30}\)

\(D=\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{1\cdot2\cdot3\cdot3+2\cdot4\cdot6\cdot3+3\cdot6\cdot9\cdot3+5\cdot10\cdot15\cdot3}\)

\(D=\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{3\left(1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15\right)}=\frac{1}{3}\)

2. \(\frac{2x-9}{240}=\frac{39}{80}\)

=> \(\frac{2x-9}{240}=\frac{39\cdot3}{80\cdot3}=\frac{117}{240}\)

=> 2x - 9 = 117

=> 2x = 117 + 9 = 126

=> x = 126 : 2 = 63

2x−92402x−9240=39803980⇒⇒2x−92x−9=240.3980240.3980=117117

2x−9=1172x−9=117⇒⇒2x=117+9=1262x=117+9=126⇒⇒x=126:2=63

Ta có 2x–9/240=39/80=117/240. suy ra 2x – 9 = 117

Từ đó tìm được x = 63 

\(2.x-\frac{9}{240}=\frac{39}{80}\)

\(\frac{39}{80}=\frac{117}{240}\)

\(\Rightarrow2.x-\frac{9}{240}=\frac{117}{240}\)

\(\Rightarrow2.x-9=117\)

\(\Rightarrow2x=126\)

\(\Rightarrow126:2=63\)

Vậy: x = 63