y x 15 + y x 85 = 1000
tìm y biết a y x 27 y x 30 y x 43 210500b 15 x y 85 x y 300
tui không biết nha
a)1000 +x+x nhân 2=1996
b)(x-85)nhân 15=22500
a) \(1000+x+2x=1996\)
\(\Rightarrow1000+3x=1996\)
\(\Rightarrow3x=996\)
\(\Rightarrow x=332\)
b) \(\left(x-85\right)\times15=22500\)
\(\Rightarrow x-85=1500\)
\(\Rightarrow x=1585\)
Study well
Tìm x ; y thuộc Z :
a) x . y = -15
b) x . y = -13
c) x . y = 85
tìm y biết :
a) y x 27 + y x 30 + y x 43 = 210500
b) 15 x y + 85 x y = 300
a) \(y\times27+y\times30+y\times43=210500\)
\(y\times\left(27+30+43\right)=210500\)
\(y\times100=210500\)
\(y=210500\div100\)
\(y=2105\)
b) \(15\times y+85\times y=300\)
\(y\times\left(15+85\right)=300\)
\(y\times100=300\)
\(y=300\div100\)
\(y=3\)
\(a,y\times27+y\times30+y\times43=210500\)
\(\Rightarrow y\times\left(27+30+43\right)=210500\)
\(\Rightarrow y\times100=210500\)
\(\Rightarrow y=210500:100=2105\)
\(b,15\times y+85\times y=300\)
\(\Rightarrow y\times\left(15+85\right)=300\)
\(\Rightarrow y\times100=300\)
\(\Rightarrow y=300:100=3\)
a) y x 27 + y x 30 + y x 43 = 210500
y x ( 27+30+43 ) = 210500
y x 100 = 210500
y = 210500 : 100
y = 2150
b) 15 x y + 85 x y = 300
y x ( 15+85)=300
y x 100 =300
y = 300 : 100
y = 3
1 tim y
a)85 x y + 15 x y=4000
b)18 +y + y + y=48 x 25
c)64 x y - y x 13 - y=43
a, (85 + 15) x y = 4000 c,
100 x y = 4000
y = 4000 : 10
y = 40
b; 18 + y + y + y = 48 x 25
18 + (y + y + y) = 1200
18 + 3y = 1200
3y = 1200 - 18
3y = 1182
y = 1182 : 3
y = 394
c; 64 x y - y x 13 - y = 43
y x (64 - 13 - 1) = 43
y x (51 - 1) = 43
y x 50 = 43
y = \(\dfrac{43}{50}\)
Giai pt: \(\left\{{}\begin{matrix}\left(\dfrac{x}{y}+\dfrac{y}{x}\right)\left(x+y\right)=15\\\left(\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}\right)\left(x^2+y^2\right)=85\end{matrix}\right.\)
b1:tính
M=1000-|x+11|-|y-8|
B=-|10-x|-|y+5|-100
D=|X-15|+|X-8|+|100-Z|-15
lập bảng xét dấu (lớp 7)
lớp 6 chưa học bảng xét dấu
\(\hept{\begin{cases}\left(\frac{x}{y}+\frac{y}{x}\right)\left(x+y\right)=15\\\left(\frac{x^2}{y^2}+\frac{y^2}{x^2}\right)\left(x^2+y^2\right)=85\end{cases}}\)
Đật \(a=\frac{x}{y}+\frac{y}{x};b=x+y\Rightarrow\hept{\begin{cases}ab=15\\\frac{x^2}{y^2}+\frac{y^2}{x^2}=a^2-2\end{cases}}\)
=>\(\frac{b^2}{a+2}=\frac{\left(x+y\right)^2}{\frac{x}{y}+\frac{y}{x}+2}=xy\)
=>\(\left(x+y\right)^2-2xy=b^2-\frac{2b^2}{a+2}\Rightarrow x^2+y^2=b^2-\frac{2b^2}{a+2}\)
Nên ta có pt (2)
<=>\(\left(a^2-2\right)\left(b^2-\frac{2b^2}{a+2}\right)=85\Leftrightarrow\left(a^2-2\right)ab^2=85\left(a+2\right)\)
<=>\(\left(a^2-2\right)a^2b^2=85a\left(a+2\right)\Leftrightarrow15^2\left(a^2-2\right)=85a\left(a+2\right)\)
<=>\(140a^2-17a-45=0\Leftrightarrow\left(a-\frac{5}{2}\right)\left(a+\frac{9}{7}\right)=0\)
Đến đây tìm a rồi tìm b và tính được x,y thôi
^_^
mình chưa được hiểu chỗ \(\frac{b^2}{a+2}=xy\)
\(\hept{\begin{cases}\left(\frac{x}{y}+\frac{y}{x}\right)\left(x+y\right)=15\\\left(\frac{x^2}{y^2}+\frac{y^2}{x^2}\right)\end{cases}\left(x^2+y^2\right)=85}\)