\(\frac{x}{125}\)=\(\frac{69}{115}\)
Tìm x là :.......
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Tìm x biết:x/125=69/115. Tìm x ?
x:125=\(\frac{69}{115}\)
x=\(\frac{69}{115}\times125\)
x=75
x/125=69/115
X = 75
cho mik nhiều
Tim x, biet:
x/125 = 69/115
Ban nao nhanh tay minh se ket ban voi.
Thank you nguyen hai anh nhe!^-^
2.CMR C=\(220^{119^{69}}+119^{69^{220}}+69^{220^{119}}\)chia hết cho 102
Tìm x:
\(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\frac{x+44}{82}\)
\(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\frac{x+44}{82}\)
\(\Leftrightarrow\frac{1+\left(x+11\right)}{115}+\frac{1+\left(x+22\right)}{104}=\frac{1+\left(x+33\right)}{93}+\frac{1+\left(x+44\right)}{82}\)
\(\Leftrightarrow\frac{x+126}{115}+\frac{x+126}{104}=\frac{x+126}{93}+\frac{x+126}{82}\)
\(\Leftrightarrow\left(x+126\right).\left(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\right)=0\)
\(\Leftrightarrow x+126=6\Leftrightarrow x=-126\)vì\(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\ne0\)
vậy x=-126
Tìm x , biết :
a) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
c) \(\frac{-5}{6}.\frac{125}{25}< x< \frac{-7}{15}.\frac{9}{14}\) (\(x\) thuộc Z)
d) \(\left(\frac{-5}{3}^3\right)< x< \frac{-24}{35}.\frac{-5}{6}\) ( \(x\) thuộc Z ) \(\)ththu
\(\frac{69}{91}=\frac{x-5}{133}\)tìm x
=> 133 x 69 = ( x - 5 ) x 91
=> 9177 = 91 x ( x - 5 )
=> x - 5 = 1311/13
=> x = 1376/13
Tìm x biết :
\(\frac{x}{15}+\frac{x-19}{17}+\frac{x+69}{18}=0\)
<=> 17.6x+90(x-19)+17.5(x+69)=0
<=> 102x+90x-1710+85x+5865=0
<=> 277x=-4155 => x=-4155/277=-15
ĐS: x=-15
Tìm x : \(\frac{x-39}{19}+\frac{x-49}{29}=\frac{x-59}{39}+\frac{x-69}{49}\)
Lí do = 0 nè:
\(\frac{x-39}{19}+\frac{x-49}{29}=\frac{x-5}{39}+\frac{x-69}{49}\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}=0+\left(\frac{x-5}{39}+\frac{x-69}{49}\right)\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}-\left(\frac{x-5}{39}+\frac{x-69}{49}\right)=0\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}-\frac{x-5}{39}-\frac{x-69}{49}=0\)