Tính nhanh
254x399-145 / 254+399 x 255
5932+6001x5931 / 5932x6001-69
Bài 6: Tính nhanh:
a) \(\dfrac{254x399-145}{254+399x253}\) ( x ở trong bài này là nhân ạ)
b) \(\dfrac{5932+6001x5931}{5932x6001-69}\)
c) \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\)
a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)
\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)
b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)
\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)
c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)
\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)
\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)
tính nhanh
254x399-145 / 254+399x253 5932+6001x5931 / 5932x6001-69
\(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}\)
\(=\frac{253.399+1.399-145}{254+399.253}\)
\(=\frac{253.399+254}{254+399.253}\)
\(=1.\)
\(\frac{5932+6001.5931}{5932.6001-69}=\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)
\(=\frac{5932+6001.5931}{5931.6001+1.6001-69}\)
\(=\frac{5932+6001.5931}{5931.6001+5932}\)
\(=1.\)
Câu thứ nhất là: 202292,4291. ; Câu thứ hai là: 36011793,2.
254x399-145/254+399x235 và 5932+6001x5931/5932x6001-69
PHÂN SỐ NÀO LỚN HƠN ? Tại sao?
Tính Nhanh
a) 254x399–145 / 254+399 x 253=
b) 5932+6001x5931 / 5932+6001-69
c) C=(1 – 1/2) x ( 1 - 1/3) x (1 – 1/4) x (1 – 1/5) x (1 – 1/6) x ………..
x ( 1 - 1/2015 ) x ( 1- 1/2016)
\(\frac{5932+6001x5931}{5932x6001-69}=\frac{6001x5931+5932}{5931x6001+6001-69}=\frac{6001x5931+5932}{6001x5931+5932}=1\)
Mấy bố tính nhanh đi
5932+6001x5931/5932x6001-69
\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)
\(=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5932\times6001+5932}=1\)
5932 + 6001 × 5931 / 5932 × 6001 - 69
= 5932 + 6001 × 5931 / 5931 × 6001 + 6001 - 69
= 5932 + 6001 × 5931 / 5931 × 6001 + (6001 - 69)
= 5932 + 6001 × 5931 / 5931 × 6001 + 5932
= 1
Hic, ở đây có cả bố lẫn bà, sao bn bỉu mỗi bố z, bố + bà = các bn
Ủng hộ mk nha ☆_☆^_-
các bạn tính nhanh giúp mình bài này nhé
5932+6001x5931/5932x6001-69
\(\frac{5932+6001x5931}{5932x6001-69}\)
\(=\frac{6001+6001x5931-69}{5932x6001-69}\)
\(=\frac{6001x\left(1+5931\right)-69}{5932x6001-69}\)
\(=\frac{6001x5932-69}{5932x6001-69}\)
\(=1\)
\(\frac{5932+6001\times5931}{5932\times6001-69}\)
\(=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)
\(=\frac{5932+6001\times5931}{5931\times6001+6001-69}\)
\(=\frac{5932+6001\times5931}{5931\times6001+5932}\)
\(=1\)
~ Study Well ~
Tính nhanh
a,254 x 399 - 145/ 254 + 399 x 253
b,5932 + 6001 x 5931 / 5932 x 6001 - 69
Tính nhanh:
a) \(\frac{254.399-145}{254+399.253}\)
\(=\)\(\frac{\left(253+1\right).399-145}{254+399.253}\)
\(=\)\(\frac{253.399+399-145}{254+399.253}\)
\(=\)\(\frac{253.399+254}{254+399.253}\)
\(=\)\(1\)
b) \(\frac{5932+6001.5931}{5932.6001-69}\)
\(=\)\(\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)
\(=\)\(\frac{5932+6001.5931}{5931.6001+6001-69}\)
\(=\)\(\frac{5932+6001.5931}{5932.6001+5932}\)
\(=\)\(1\)
a, 254 x 399 - 145/254 + 399 x 253
b, 5932 + 6001 x 5931/5932 x 6001 - 69
B=5932+6001x5931/5932x6001-69
B = 5932 + 6001 × 5931 / 5932 × 6001 - 69
B = 5932 + 6001 × 5931 / (5931 + 1) × 6001 - 69
B = 5932 + 6001 × 5931 / 5931 × 6001 + (6001 - 69)
B = 5932 + 6001 × 5931 / 5931 × 6001 + 5932
B = 1