Ta có: (8y-1942).1947=(2400-1942).19470

\(\Rightarrow\)8y-1942=458.10

\(\Rightarrow\)8y=4580+1942

\(\Rightarrow\)8y=6522

\(\Rightarrow\)y=6522:8=815,25

\(\left(8.y-1942\right).1947=\left(2400-1942\right).19470\)

\(\Leftrightarrow\left(8.y-1942\right).1947=458.19470\)

\(\Leftrightarrow\left(8.y-1942\right).1947=8917260\)

\(\Leftrightarrow8.y-1942=8917260:1947\)

\(\Leftrightarrow8.y-1942=4580\)

\(\Leftrightarrow8.y=4580+1942\)

\(\Leftrightarrow8.y=6522\)

\(\Leftrightarrow y=6522:8\)

\(\Leftrightarrow y=\frac{3261}{4}\)

~ Rất vui vì giúp đc bn ~

a) \(\frac{y}{6}=\frac{2010}{15}\)                              c)  \(x-\frac{1}{3}=\frac{1}{4}\)             e)\(5y-1952=2500-1947\)

\(y=\frac{2010}{15}.6\)                                  \(x=\frac{1}{4}+\frac{1}{3}\)                  \(5y-1952=553\)                                         

\(y=804\)                                           \(x=\frac{7}{12}\)                             \(5y=553+1952\)

                                                                                                                      \(5y=2505\)

                                                                                                                         \(y=2505:5=501\)

b) \(x+\frac{1}{2}=\frac{3}{4}\)                                      c)   \(3x+\frac{3}{8}=\frac{1}{2}\)

\(x=\frac{3}{4}-\frac{1}{2}\)                                                \(3x=\frac{1}{2}-\frac{3}{8}\)

\(x=\frac{1}{4}\)                                                              \(3x=\frac{1}{8}\)

                                                                                    \(x=\frac{1}{8}:3\)

                                                                                   \(x=\frac{1}{24}\)

           f)\(\left(8y-1942\right).1947=\left(240-194,2\right).19470\)

              \(\left(8y-1942\right).1947=45,8.19470\)

               \(\left(8y-1942\right)=45,8.19470:1947\)

                 \(8y-1942=45,8.10\)

                 \(8y-1942=458\)

                                      \(8y=458+1942\)

                                        \(8y=2400\)

                                              \(y=2400:8\)

                   \(y=300\)

Vì 23 + X + 1947 = 1947 + 23 + X nên X = 1747

a , x = 501

b , x = 1999

a) 5 * x - 1952 = 2500 - 1947

    5 * x -1952 =553

    5 * x             = 553 + 1952

    5 * x             =2505

    x                   = 501

b)x * 1999 - x = 1999*1997 +1999

 x * ( 1999 -1) = 1999*(1997 +1)

 x * 1998          =1999 * 1998

x                        =1999

a) 7618 = 7000 + 600 + 10 + 8

9274 = 9000 + 200 + 70 + 4

4404 = 4000 + 400 + 4

1942 = 1000 + 900 + 40 + 2

5076 = 5000 + 70 + 6

2005 = 2000 + 5

b) 5000 + 700 + 20 + 4 = 5724

6000 + 800 + 90 + 5 = 6895

5000 + 500 + 50 + 5 = 5555

2000 + 400 = 2400

2000 + 20 = 2020

2000 + 7 = 2007

 7618 = 7000 + 600 + 10 + 8

9274 = 9000 + 200 + 70 + 4

4404 = 4000 + 400 + 4

1942 = 1000 + 900 + 40 + 2

5076 = 5000 + 70 + 6

2005 = 2000 + 5

b) 5000 + 700 + 20 + 4 = 5724

6000 + 800 + 90 + 5 = 6895

5000 + 500 + 50 + 5 = 5555

2000 + 400 = 2400

2000 + 20 = 2020

2000 + 7 = 2007

Lỗi hình (:? 

=2091078

2091078

a)15.x+15.2,7=105

15.(x+2,7)=105

x+2,7=7

x=7-2,7

x=4,3

Vậy x=4,3

b)x:7=920699:70

x:7=920699:10:7

x:7=92069,9:7

x=92069,9

Vậy x=92069,9

c)5.x-1952=2500-1947

  5.x-1952=553

 5.x=2505

 x=501

Vậy x=501

d)x.2016-x=2016.2017+2016

  x.(2016-1)=2016.(2017+1)

 x.2015=2016.2018

x=\(\frac{2016.2018}{2015}\)

Vậy x\(\frac{2016.2018}{2015}\)

15.x+15.2,7=105
<=> 15.( x + 2,7 ) = 105 
=> x + 2,7 = 7
=> x = 7 - 2,7 
=> x = 4,3

x:7=920699:70
<=> x . 70 = 920699 . 7 
=> x . 70 = 6444893
=> x = 6444893 : 70 
=> x = 92069,9

5.x-1952=2500-1947
=> 5x - 1952 = 553
=> 5x = 553 + 1952 
=> 5x = 2505 
=> x = 2505 : 5 
=> x = 501 

x.2016-x=2016.2017+2016
=> x ( 2016 - 1 ) = 2016 ( 2017 + 1) 
=> x . 2015 = 2016 . 2018 
=> x : 2018 = 2016 : 2015 
=> x : 2018 = \(\frac{2016}{2015}\)
=> x = \(\frac{2016}{2015}.2018\approx2019\)

ta có \(x-1=\sqrt[3]{2}\Rightarrow\left(x-1\right)^3=2\)

cậu tính ra rồi được một đa thức =0

ta tách B để có các hạng tử như trên rồi tinh tiếp

1942 > 998

1999 < 2000

6742 > 6722

900 + 9 < 9009

(vì 900 + 9 = 909 < 9009)

5 * x - 1952 = 553

5 * x           = 553 + 1952

5 * x           = 2505

     x           = 2505 : 5

     x           = 501

Nhớ k mk nha !!!!!!!!!!!!!!!!!!!!!!!!!!!! 

\(5\times x-1952=2500-1947\)

\(5\times x-1952=553\)

\(5\times x=553+1952\)

\(5\times x=2505\)

\(x=2505\div5\)

\(x=501\)

5 * x- 1952 = 2500 - 1947

5 * x - 1952 = 553

5 * x = 2505

x = 501