a) \(\frac{7^3.5^8}{49.25^4}=\frac{7^3.5^8}{7^2.\left(5^2\right)^4}=7.\frac{5^8}{5^8}=7\)

b) \(\frac{3^9.25.5^3}{15.625.3^8}=\frac{3.3^8.5^2.5^3}{3.5.5^4.3^8}=\frac{5^5}{5^5}=1\)

c) Đề hơi sai roi bạn oi

d) \(\left(\frac{2}{5}-\frac{1}{2}\right)^2+\left(\frac{1}{2}+\frac{3}{5}\right)^2=\left(\frac{-1}{10}\right)^2+\left(\frac{11}{10}\right)^2=\frac{1}{100}+\frac{121}{100}=\frac{61}{50}\)

Khanh Nguyễn Ngọc  :câu d ko sai bạn nha dấu "/" là trên nhó

\(4^2\cdot120-4^3\cdot17+4^2\cdot34\)

\(=4^2\left(120-4\cdot17+34\right)\)

\(=16\left(120-68+34\right)\)

\(=16\cdot86=1088\)

\(7^3\cdot9+3^2\cdot7^4-45\cdot539\)

\(=7^3\cdot9+9\cdot7^4-45\cdot7^2\cdot11\)

\(=7^2\left(7\cdot9+9\cdot7^2-45\cdot11\right)\)

\(=49\left(63+9\cdot49-495\right)\)

\(=49\left(63+441-495\right)\)

\(=49\cdot9=441\)

\(5\cdot10^4+4\cdot10^3+6\cdot10^2+5\cdot10+9\)

\(=10\left(5\cdot10^3+4\cdot10^2+10\cdot6\right)+9\)

\(=10\left(5\cdot1000+4\cdot100+60\right)+9\)

\(=10\left(5000+400+60\right)+9\)

\(=10\cdot5460+9=54600+9=54609\)

a) \(\frac{75^3.3^7}{81^4.5^6}=\frac{5^3.3^3.5^3.3^7}{\left(3^4\right)^4.5^6}=\frac{5^6.3^3.3^7}{3^{16}.5^6}=\frac{3^{10}}{3^{16}}=\frac{1}{3^6}=\frac{1}{729}\)
b) \(\frac{6^6.4^2}{3^{12}.2^8}=\frac{2^6.3^6.\left(2^2\right)^2}{3^{12}.2^8}=\frac{2^6.3^6.2^4}{3^{12}.2^8}=\frac{2^{10}.3^6}{3^{12}.2^8}=\frac{2^2.1}{3^6}=\frac{4}{729}\)
c) \(\frac{34^5.2^5}{2^{14}.17^5}=\frac{2^5.17^5.2^5}{2^{14}.17^5}=\frac{2^{10}}{2^{14}}=\frac{1}{2^4}=\frac{1}{16}\)

 1/2 x 2 mũ n cộng 4 x 2 mũ n = 9 x 2 mũ n

A=5^10 .9+5^10.7 / 5^9.2^4

A=5^10.(9+7) / 5^9.16

A=5^10.16 /5^9.16

A=5^9.5.16/5^9.16

=>A=5/1

=>A=1

B=2^10.55+2^10. 26 / 2^8 . 27

B=2^10.(55+26) / 2^8 .27

B=2^10.81 / 2^8 .27

B=2^8.2^2.81 / 2^8.27

=>B=2^2.81 / 27

=>B=4.81 / 27

=>B=4.3^3.3 / 3^3

=>B=4.3

=>B=12

Cn phần C thì....mik chưa rõ lém nhưng mak nếu ai cko mik là dzui lém òy......ủng hộ nhoa mina

6 nhaan3 băng2

a/ 26176

b/ 8

c/472392

d/ Ko tính dc

Thấy mình đẳng cấp ko

Cho mình 10 k nhé

1)1/9 x 3^x = 2187:81=27

            3^x=27:1/9=243=3⁵

            =>x=5

\(\frac{1}{9}.3^4.3^x=3^7\)

\(\Leftrightarrow3^x=3^7:\frac{1}{9}:3^4=243\)

\(\Leftrightarrow3^x=3^5\)

\(\Leftrightarrow x=5\)

a) \(2^3\cdot4^5=2^3\cdot2^{10}=2^{13}\)

b) \(3^4\cdot27^2=3^4\cdot3^6=3^{10}\)

c) \(16^{10}:8^2=2^{40}:2^6=2^{34}\)

d) \(12^3:3^3=\left(12:3\right)^3=4^3\)

e) \(3^4\cdot2^4=\left(3\cdot2\right)^4=6^4\)

g) \(9^{13}\cdot5^{26}=9^{13}\cdot25^{13}=\left(9\cdot25\right)^{13}=225^{13}\)

=))

\(a=4^5.9^4-2.\dfrac{6^9}{2^{10}}.3^8+6^8.20\)

Đề là như vầy đúng ko bn?

\(a,\)\(\frac{2^5\times3^{12}\times7^8}{2^7\times3^{10}\times7^9}=\frac{3^2\times\left(2^5\times3^{10}\times7^8\right)}{2^2\times7\times\left(2^5\times3^{10}\times7^8\right)}\)\(=\frac{3^2}{2^2\times7}=\frac{9}{28}\)

\(b,\)Tương tự