tim UCLN va BCNN cua 60,50,100
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
tim a va b biet
A,a+b=128 va UCLN cua chung =16
B,UCLN cua a,b va BCNN cua chung =36
tim BCNN ; UCLN va BC;UC cua 46;54;112
46=2.23
54=2.33
112=24.7
UCLN(46,54.112)=2
UC(46,54,112)=U(2)=(1,2)
BCNN=24.33.23.7=68552
BC(46,54,112)=B(68552)=(0,68552,137104,....)
tim ucln va bcnn cua 14 82 124
ta có : 14=2.7
82=2.41
124=2^2.31 (^ là mũ nha)
ƯCLN(14,82,124) = 2
BCNN(14,82,124)=2^2.7.31.41= 35588
UCLN(14;82;124)={2}
con BCNN thi mik chua tim dc
Tim hai so a va b biet tong cua BCNN va UCLN cua chung la 15.
tim BCNN cua a,b =300
UCLN cua a va b =15
tim 2 so ava biet TONG CUA BCNN va UCLN CUA CHUNG LA 15
biet rang BCNN(a,b).UCLN(a,b)=a.b
a, tong cua hai so bang 60,tong giua UCLN va BCNN cua chung la 84 tim hai so do
ban trinh bay ra ho minh duoc khong thank ban
bn tra tren hoc mai do. Co day bn a
Tim UCLN , BCNN , UC , BC cua cac so 36 , 18 va 24
Bg :
-Tìm ƯCLN + ƯC :
36 = 22 . 32
18 = 2 . 32
24 = 23 . 3
\(\RightarrowƯCLN\left(36,18,24\right)=2.3=6\)
\(\RightarrowƯC\left(36,18,24\right)=Ư\left(6\right)=\left\{1,2,3,6\right\}\)
-Tìm BCNN và BC :
-Phân tích ra thừa số nguyên số như ở trên ((:
\(\Rightarrow BCNN\left(36,18,24\right)=2^3.3^2=72\)
\(\Rightarrow BC\left(36,18,24\right)=B\left(72\right)=\left\{0,72,...\right\}\)
P/s : Hok tốt a~