tim x,y biet
(x-5).(y+1) =6
(x-5) .(x2.9) =0
DN
Những câu hỏi liên quan
tim x,y,z biet(x-1/5)^2020+(y+0.4)^2000+(z-3)^6=0
Ta có: \(\left(x-\frac{1}{5}\right)^{2020}\ge0\forall x\)
\(\left(y+0.4\right)^{2000}\ge0\forall y\)
\(\left(z-3\right)^6\ge0\forall z\)
=> \(\left(x-\frac{1}{5}\right)^{2020}+\left(y+0.4\right)^{2000}+\left(z-3\right)^6\ge0\forall x,y,z\)
Dấu "=" xảy ra khi: \(\hept{\begin{cases}x-\frac{1}{5}=0\\y+0.4=0\\z-3=0\end{cases}}\) => \(\hept{\begin{cases}x=\frac{1}{5}\\y=0\\z=3\end{cases}}\)
vậy ...
Đúng 0
Bình luận (0)
tim x, y biet /x+2y+6/+/3x-y+5/=0
a, tim x€Z biet (x-6) chia het cho (x-5)
b, tim x€Z, y€Z biet (x-1).(xy-5)=5
tim x, y thuoc Z biet :
a. x/6=5y va x<y
b, -3/y= x/4 va x<0<y
c, x+3/ y+5= 3/5 va x+y=6
tim x,y thuoc Z biet
|y|.|2x+3|=8
|2x+4|+|y-3|=0
|x-1|+|2y+7|=3
|x+5|+|2y+6| nho hon hoac bang 0
tim cac so nguyen x,y biet
a)(x+5)2.(y-2)=8
b)(2x+4)10+(xy-y-6)=0
c)|x+y-5|+|x-y-3|=0
d)|(x-1)2-1|2015+4-(y-2)2017
Tim x,y,z biet:
\(x+1=y+2=z+3và\left(x-\frac{1}{5}\right)\left(y+\frac{1}{3}\right)\left(z-6\right)=0\)
tim x ,y biet 5/x-y/3=1/6
tim(x;y) biet -|2x+4| -|y+5| lon hon bang 0 .Tim cap (x;y)