tính nhanh
1/2+1/4+1/8+1/16+.......+1/256+1/512
Kết quả của dãy tính:
1/2 + 1/4 + 1/8 + 1/16 + … 1/256 + 1/512 bằng…
Vậy dãy số đó là:
1/2 + 1/4 + 1/8 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 =
256/512 + 128/512 + 64/512 + 32/512 + 16/512 + 8/512 + 4/512 + 2/512 + 1/512 511/512
Đáp số: 511/512
Tính nhanh : 1+1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512
Tính nhanh tổng A biết :A =1/2+1/4+1/8+1/16+....+1/256+1/512
Ta có: A =1/2+1/4+1/8+1/16+....+1/256+1/512
=> 2A = 1 + 1/2 + 1/4 + 1/8 + ...+ 1/128 + 1/256
=> 2A - A = (1 + 1/2 + 1/4 + 1/8 + ...+ 1/128 + 1/256 -(1/2+1/4+1/8+1/16+....+1/256+1/512 )
A = 1 - 1/512 = 511/512
kết quả của dãy tính 1/2+1/4+1/8+1/16+...1/256+1/512 bằng..,
1/2 + 1/4 =3/4
1/2+1/4 +1/8=7/8
1/2+1/4+1/8+1/16=15/16
....tương tự ta có
1/2 +1/4+1/8+1/16+...+1/256+1/512=511/512
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}+\frac{1}{512}\)
\(=\frac{256}{512}+\frac{128}{512}+\frac{64}{512}+\frac{32}{512}+\frac{16}{512}+\frac{8}{512}+\frac{4}{512}+\frac{2}{512}\)
\(=\frac{511}{512}\)
Đặt \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}+\frac{1}{512}\)
\(Ax2=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}\)
\(Ax2-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}+\frac{1}{512}\right)\)
\(A=1-\frac{1}{512}\)
\(A=\frac{511}{512}\)
Kết quả của dãy tính: 1/2+1/4+1/8+1/16+...+1/256+1/512=?
\(=1-\frac{1}{2}\)\(+\frac{1}{2}\)\(-\frac{1}{4}\)\(+\frac{1}{4}\)\(+\)...\(+\)\(\frac{1}{256}\)\(-\frac{1}{512}\)
\(=1-\frac{1}{512}\)
\(=\frac{511}{512}\)
kết quả của dãy tính:
1/2+1/4+1/8+1/16+....+1/128+1/256+1/512=.......?
1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 + 1 / 128 + 1 / 256 + 1 / 512 = 511 / 512 .
dãy số đó là:
1/2+1/4+1/8+1/32+1/64+1/128+1/128+1/256+1/512=511/512
1/2+1/4+1/8+1/16+...+1/256+1/512
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}+\frac{1}{512}\)
\(A\cdot2=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\)
\(A\cdot2-A=1-\frac{1}{512}\)
\(A=\frac{511}{512}\)
1/2+1/4+1/8+1/16+...+1/256+1/512(gọi A là tổng các PS trên)
A*2=(1+1/2+1/4+1/8+...+1/128+1/256)/2
A*2-A=1+1/2+1/4+1/8+...+1/128+1/256-1/2-1/4-1/8-1/16-...-1/256-1/512.
A=1-1/512
A=511/512.
Kết bạn với mình nha!
1/2 + 1/4 + 1/8 + 1/16 +...+ 1/256 + 1/512
1/2+1/4+1/8+1/16+........+1/256+1/512
Giúp mình chút nha!
Ta có :1/2+1/4=1-1/4=3/4
1/2+1/4+1/8=1-1/8=7/8
Tương tự
Vậy 1/2+1/4+1/8+1/16+....+1/256+1/512
=1-1/512
=511/512
K cho nha đảm bảo đúng 100% vì cô mk dạy rồi !