a)7x² + 6x - 13

= 7x² - 7x + 13x - 13

= (7x² - 7x) + (13x - 13)

= 7x(x - 1) + 13(x - 1)

= (7x + 13)(x - 1)

b) 15(x - y) - 25x + 25y

= 15(x - y) - (25x - 25y)

= 15(x - y) - 25(x - y)

= (15 - 25)(x - y)

= -10(x - y)

c) 36 - 4a² + 20ab - 25b²

= 36 - (4a² - 20ab + 25b²)

= 6² - (2a - 5b)²

= (6 - 2a + 5b)(6 + 2a - 5b)

= (5b - 2a + 6)(2a - 5b + 6)

nhớ tik mik nha. Ak có j ko hiểu thì cứ bình luận ở dưới mik giải cho

a, \(7x^2+6x-13\)

=\(7x^2-7x+13x-13\)

=\(\left(7x^2-7x\right)+\left(13x-13\right)\)

=\(7x\left(x-1\right)+13\left(x-1\right)\)

=\(\left(x-1\right)\left(7x+13\right)\)

b, \(15\left(x-y\right)-25x+25y=15\left(x-y\right)-\left(25x-25y\right)\)

=\(15\left(x-y\right)-25\left(x-y\right)=\left(x-y\right)\left(15-25\right)\)

=(x-y).-10

A.25x^2 -40xy +4y^2 (sai đầu đề  đãng lẽ là 40xy phải là 20xy mới tính đc)

=(5x)^2-2.5x.2y+(2y)^2

=(5x-2y)^2

B. x^2 +40x+400

=x^2+2.x.20 +(20)^2

=(x+20)^2

C.25x^2 +100xy +100y^2

=(5x)^2 +2.5x.10y+(10y)^2

= (5x+10y)^2

1)\(64x^2+144x+81=\left(8x+9\right)^2\)

2)\(16y^2+\frac{1}{64}+y=\left(4y+\frac{1}{8}\right)^2\)

3)\(9z^2+6z+1=\left(3z+1\right)^2\)

4)\(4y^2+12y+9=\left(2y+3\right)^2\)

5)\(y^2+10xy+25x^2=\left(y+5x\right)^2\)

6)\(x^2+6x+9=\left(x+3\right)^2\)

Trả lời:

a, ( 4xy )² + 8xy + 1 = ( 4xy + 1 )²

b, 25x² - 36 = ( 5x + 6 ) ( 5x - 6 )

c, ( 1/2 - x )² = 1/4 - x + x²

=_= ......bt chết liền (hoa mắt,chóng mặt,ù tai)

a,x²-8x+16=(x-4)²

b,(x-5y)(x+5y)=x²-25y²

c,4x⁴-16=4(x²-2)(x²+2)

d,x²+4xy+4y²=(x+2y)²

1.(__3x_____+___1____) (9x^2-__3x____+1) = (__3x__)^3 + (__1____)^3

2.(x+__4_____) (__x\(^2\)____-___4x_____+16) = (_x___)^3 + (__4____)^3

hai câu cuối bạn có gõ sai chỗ 10x với 6x ko??? vì như thế thì ko ra đc HĐT

\(\dfrac{\text{(2x-6)}}{(x+3)}\)

1. \(\frac{2}{3}x^3y^4\left(-3x^4y^5\right)=-2x^7y^9\)

2. \(\left(-2x^5\right)\left(7xy^3\right)=-14x^6y^3\)

Kb nha