a, 249 - 25 × 8 + 3² ×  4

= 249 - 200 + 9 × 4

= 49 + 36

= 85

b,27 : { 480 :  [(513 : 9 + 19 ) + 84 ]}

= 27 : { 480 : [(57 + 19) + 84 ]}

= 27 : { 480 : [76 + 84]}

= 27 : { 480 : 160}

= 27 : 3

= 9

c. 73 × 25 + 28 × 25 - 25 

= 73 × 25 + 28 × 25 - 25 × 1

= 25 × (73 + 28 - 1)

= 25 × 100

= 2500

d. 2× 9 × 50 - 89⁰

= (2 × 50) × 9 - 1

= 100 × 9 - 1

= 900 - 1

= 899

a)\(249-25\cdot8+3^2\cdot4\)

\(=249-200+9\cdot4\)

\(=49+36=85\)

b)\(27:\left\{480:\left[\left(513:9+19\right)+84\right]\right\}\)

\(=27:\left\{480:\left[\left(57+19\right)+84\right]\right\}\)

\(=27:\left\{480:\left[76+84\right]\right\}\)

\(=27:\left\{480:160\right\}\)

\(=27:3=9\)

c)\(73\cdot25+28\cdot25-25\)

\(=73\cdot25+28\cdot25-25\cdot1\)

\(=\left(73+28-1\right)\cdot25\)

\(=100\cdot25=2500\)

d)\(2\cdot9\cdot50-89^0\)

\(=2\cdot9\cdot50-1\)

\(=900-1=899\)

a)249 - 25 . 8 + 3².4

= 249 - 200 + 36

=        49      +36

=               85

b)27 : { 480 : [(513:9 + 19 ) +84 ]}

= 27 : { 480 : [76+84]}

= 27: { 480 : 160 }

= 27 : 3

= 9

c) 73.25 +28.25 -25

= 25 . ( 73 +28 - 1)

= 25. 100

= 2500

d)2.9.50 - 89⁰

= 2.9.50 - 1

= 900 - 1 

= 899 

\(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{36}\\{36}\end{array}}\\\hline{\,\,\,\,72}\end{array}\)                                       \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{73}\\{17}\end{array}}\\\hline{\,\,\,90}\end{array}\)

\(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{28}\\{53}\end{array}}\\\hline{\,\,\,81}\end{array}\)                                       \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{25}\\{35}\end{array}}\\\hline{\,\,\,60}\end{array}\)

\(10,\Rightarrow x-14=-8\Rightarrow x=6\\ 11,\Rightarrow7-x-32=-25\\ \Rightarrow-25-x=-25\Rightarrow x=0\\ 12,\Rightarrow3x-16=\dfrac{2\cdot7^4}{7^3}=2\cdot7=14\\ \Rightarrow3x=30\Rightarrow x=10\\ 13,\Rightarrow\left[{}\begin{matrix}x-4=5\\x-4=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=9\\x=-1\end{matrix}\right.\\ 14,\Rightarrow\left(2x+11\right)^2=2^4:2^4=1\\ \Rightarrow\left[{}\begin{matrix}2x+11=1\\2x+11=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-5\\x=-6\end{matrix}\right.\\ 15,\Rightarrow7^{3x-2}=7^3\cdot4+7^3\cdot3=7^3\cdot7=7^4\\ \Rightarrow3x-2=4\\ \Rightarrow3x=6\Rightarrow x=2\)

10) x - [42 + (-28)] = -8

x - 14 = -8

x = -8 + 14 = 6

11) (7-x) - (25 +7) = -25

(7 -x) - 32 = -25

7 -x = -25 + 32 = 7

x = 7 -7 = 0

12) (3x - 2⁴) . 7³ = 2 . 7⁴

(3x - 16) . 343 = 4802

3x - 16 = 4802 : 343= 14

3x = 14 + 16 = 30

x = 30 : 3 =10

13) (x - 4)² = 25

⇒ 5² = 25

⇒ x - 4 = 5

⇒ x = 5 + 4 =9

14) 2⁴(2x + 11)² = 4²

16(2x + 11)² = 16

(2x + 11)² = 16 : 16 = 1

⇒ 2x + 11 = 1

⇒ 2x = 11 + 1 = 12

⇒ x = 12 : 2 = 6

15) 7^3x-2 - 3.7³ = 7³ . 4

7^3x-2 - 1029 = 1372

7^3x-2 = 1372 + 1029 = 2401

⇒ 7⁴ = 2401

⇒ 3x - 2 = 4

⇒ 3x = 4 + 2 = 6

⇒ x = 6 : 3 =2

a ) 126 - 2x = 12 - ( -28 )

     126 - 2x = 40

     2x = 126 - 40

     2x = 86 

     x = 86 : 2

     x = 43

b ) 25 - 5( x + 1 ) = 30 - 125

     25 - ( 5x + 5 ) = -95

     25 - 5x - 5 = -95

     20 - 5x = -95

     5x = 20 - ( - 95 )

     5x = 115

     x = 115 : 5

     x = 23

c ) I 3x - 1 I - 25 = 73 

     I 3x - 1 I = 73 + 25

     I 3x - 1 I = 98

=> 3x - 1 = 98 hoặc 3x - 1 = -98

=> 3x = 98 + 1 hoặc 3x = -98 + 1

=> 3x = 99 hoặc 3x = -97

=> x = 99 : 3 hoặc x = -97 : 3 

=> x = 33 hoặc x = -93/3

d ) 2( x + 2 ) - 6 = 120 - 4x 

     2x + 4 - 6 = 120 - 4x 

     2x - 2 = 120 - 4x

     2x + 4x = 120 + 2

     6x = 122

     x = 122 : 6

     x = 61/3

a) x = 43

b) x = 23

c) x = 33 hoac x= -97/3

nêu cách làm đi

|25 - 24 -10| - (28 - 30 + 4)
= |1 - 10| - (-2 + 4)
= |-9| - 2
= 9 - 2
= 7
-(-73) + (44 - 94 + 27) + 94
= 73 + (-50 + 27) + 94
= 73 + (-23) + 94
= 73 - 23 + 94
= 50 + 94
= 144
(-33 + 108 - 75) - (108 + 25)
= (75 - 75) - 133
= 0 - 133
= -133
120 - (-2 + 120 - 18) - 92
= 120 - (118 - 18) - 92
= 120 - 100 - 92
= 20 - 92
= -72

Lời giải:

Xét tử số:

$\text{TS}=1+25^4+25^8+...+25^{28}$

$25^4.\text{TS}=25^4+25^8+...+25^{32}$

$\Rightarrow \text{TS}(25^4-1)=25^{32}-1$

$\text{TS}=\frac{25^{32}-1}{25^4-1}$

Xét mẫu số:

$\text{MS}=1+25^2+..+25^{30}$

$25^2.\text{MS}=25^2+25^4+...+25^{32}$

$\Rightarrow \text{MS}(25^2-1)=25^{32}-1$

$\Rightarrow \text{MS}=\frac{25^{32}-1}{25^2-1}$

Do đó:
$A=\frac{25^{32}-1}{25^4-1}:\frac{25^{32}-1}{25^2-1}=\frac{25^2-1}{25^4-1}$

$=\frac{25^2-1}{(25^2-1)(25^2+1)}=\frac{1}{25^2+1}$