1 Tìm x
a (19.x.1.2.5^2).14=(13-8)^2-4^2
b 2.3^x=10.3^12+8.27^4
1 ) tìm x
a) (19.x +2.52):14=(13-8)2-42
b)2.3x-10.312+8.272
Please help me
a) (19.x + 2.52): 14 = 9
19.x +2.52 = 9.14 =126
19.x+ 50 =126
19.x =126-50 =76
x = 76 :19 = 4
Câu b sao ko có đáp án tìm x vậy bn
minh lam lun nha ko ghi lai de dau
a, (19x + 2.25): 14 = 5^2 - 4^2 (25-16)
( 19x + 50) = 9. 14
19x+50= 126
19x=126-50
x= 76:19
x= 4
muc b ko co kt qua lam sao ma lam
tìm x:
a. (19x+2.52):14=(13-8)2-42
b) 2.3x=10.312+8.274
1) tim x biết:
a) (19.x +2.5^2) : 14=(13-8)^2 - 4^2
b) 2.3^x=10.3^12+8.27^4
2) so sanh
a) 5^23 va 6.5^22
b)21^15 va 27^5.49^8
c)3^39 va 11^21
d) 7.2^13 va 2^16
Tim x
a) 10^x=1^x
B)X^10=x
c) x^10=1^x
d)2.3^x=10.3^12+8.27^4
e) (19x+2.5^2):14=(13-8)^2-4^2
10^X=1^X
Do 1^mấy cũng =1
=>10^x=1
=>x=0
tìm x biết
a) (19x+2.52):14=(13-8)2-42 b) 2.3x=10.312+8.274
a) ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
<=> ( 19x + 2 . 25 ) : 14 = 25 - 16
<=> ( 19x + 50 ) : 14 = 9
<=> 19x + 50 = 9 . 14
<=> 19x + 50 = 126
<=> 19x = 126 - 50
<=> 19x = 76
<=> x = 76 : 19
<=> x = 4
a) ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
<=> ( 19x + 2 . 25 ) : 14 = 25 - 16
<=> ( 19x + 50 ) : 14 = 9
<=> 19x + 50 = 9 . 14
<=> 19x + 50 = 126
<=> 19x = 126 - 50
<=> 19x = 76
<=> x = 76 : 19
<=> x = 4
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2Tìm X:
a.(19x+2.5^2):14=(13-8)^2-4^2
b.2.3^x=10.3^12+8.27^4
c.{x^2-[6^2-(8^2-9.7)^3-7.5]^3-5.3}^3=1
d.60-3(x-2)=51
e.4x-20=2^5:2^2
{ x2 - [ 62 - ( 82 - 9.7)3 - 7.5]3 - 5.3 }3 = 1
{ x2 + [ 36 - (64 - 63)3 - 35]3 - 15}3 = 1
[ x2 - ( 36 - 13 - 35 ) - 15 ]3 = 1
[ x2 - ( 36 - 1 - 35 ) - 15]3 = 1
[ x2 - ( 35 - 35 ) - 15]3 = 1
[ x2 - 0 - 15]3 = 1
( x2 - 15 )3 = 1
<=> ( x2 - 15)3 = 13
=> x2 - 15 = 1
<=> x2 = 16
=> x = 4
(19x+2.52):14=(13-18)2.42
2.3x=10.312+8.274
Tìm x biết:
a) (19x + 2.52) : 14 = (13 - 8)2 - 42
b) 2.3x = 10.312 + 8.274
Ai có câu trả lời rõ ràng và sớm nhất mình sẽ chọn nha
a) (19x+2.5^2):14=(13-8)^2-4^2
(19x+2.25):14=25-16
(19x+2.25):14=9
19x+2.25=126
19x+50=126
19x=76
x=4
b)2.3^x=10.3^12+8.27^4
2.3^x=10.3^12+8.(3^3)^4
2.3^x=3^12(10+8)
2.3^x=3^12.18
3^x=3^14
=>x=14
a) <=> (19x+50)=14.(52-42)=14.9=126
=> 19x=126-50=76
=> x=76/19=4
ĐS: x=4
b) 2.3x=10.312+8.312=312(10+8)=18.312=2.32.312
<=> 2.3x=2.314 <=> 3x=314
=> x=14
Đs: x=14
a) (19x+2.5^2):14=(13-8)^2-4^2
(19x+2.25):14=25-16
(19x+2.25):14=9
19x+2.25=126
19x+50=126
19x=76
x=4
b)2.3^x=10.3^12+8.27^4
2.3^x=10.3^12+8.(3^3)^4
2.3^x=3^12(10+8)
2.3^x=3^12.18
3^x=3^14
=>x=14
a)(19x+2.52)/14=(18-8)2-42
b)2.3x=10.312+8.274