(2.x-3)^3-13=112
5x+3-13=112
\(5^{x+3}\)=112+13
\(5^{x+3}\)=125
\(5^{x+3}\)=\(5^3\)
x+3=3
x=3-3
x=0
5x+3 -13 =112
Có: 5x+3 -13 =112
\(\Rightarrow\)5\(^{^{x+3}}\)=112+13=125
\(\Rightarrow\)5\(^{^{x+3}}\)= 5\(^3\)
\(\Rightarrow\)x+3=3
\(\Rightarrow\)x=0
Ta có : \(5^{x+3}-13=112\)
\(\Rightarrow5^{x+3}=125=5^3\)
\(\Rightarrow x+3=3\)
\(\Rightarrow x=3-3=0\)
Vậy x = 0
=> 5x+3=112+13
=> 5x+3=125
Ta có 125= 53
=> 5x+3 =53
=> x+3=3
=>x=0
1) –45 + 5.(–2x) = 95
2) x.(12 + x).(71 – x) = 0
3) (x – 11).(x + 12).(–x – 13) = 0
4) |2.x – 15| = 7
5) –2.|x + 32| = –112
Giải các phương trình sau:
a) x + 1 3 − 5 = 1 ; b) 10 x − 3 + 1 4 = 5 %
c) 3 − 4 x − 3 = − 5 + 4 x − 3 d) 3 x − 11 2 − 7 3 = 1 3 x − 11 .
A =( 2/39 −1/15 −2/153 : 1/34 +3/20 −3/26) :( 1+2/71 −5/121: 65/121 −26/71 −13 )
B = ( 112/13.20 +112/20.27 +112/27.34 +...+112/62.69 ) :( −5/9.13 −7/9.25 −13/19.25 −31/19.69 )
mấy cái dấu / hay : là thay cho phân số
Tìm số nguyên x, biết
a, 123 - 5 ( x + 4 ) = 38
b, ( 3x - 24 ) . 73 = 2 . 74
c, 5x+3 - 13 = 112
a, 123 - 5 ( x + 4 ) = 38
=> 5(x+4)=123-38
=> 5(x+4)=85
=> x+4=85:5
=>x+4=17
=>x=17-4
=>x=13
b, ( 3x - 24 ) . 73 = 2 . 74
=> (3x-16).343=4802
=> 3x-16=4802:343
=>3x-16=14
=>3x=14+16
=>3x=30
=>x=30:3
=>x=10
c, 5x+3 - 13 = 112
=> 5x+3=112+13
=>5x+3=125
=> 5x+3=53
=> x+3=3
=>x=3-3
=>x=0
1)Tinh
a)\(A=\left(\frac{112}{13.20}+\frac{112}{20.27}\frac{112}{27.34}+...+\frac{112}{62.69}\right):\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.15}-\frac{31}{19.69}\right)\)
b)\(B=\frac{2.2012}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+2012}}\)
X x 14-13 x 2= 112:76
x.14-13.2=112:76
x.14-26=36
x.14=36+26
x.14=62
x=62/14=31/7
vậy x=31/7
\(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\) =?
\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{37.34}+....+\frac{112}{62.69}\right):\left(\frac{5}{9.13}-\frac{7}{19.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)=?