Tim x biet :
a,12-91+1/5-9/8.x=30
b,45+8-64.x=73
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bai 1 tim x biet
a) x+a =12
b)a-x=-8
c25-x=a
d)a-x-a=7
bai 2 tim x biet
a) -18-x=30
b)-25+x=-2 +9
c) -45-(x-1)=56
2)
a)-18-x=30\(\Rightarrow\)x=-18-30=-48
b)-25+x=-2+9\(\Rightarrow\)-25+x=7\(\Rightarrow\)x=7-(-25)=7+25=32
c)-45-(x-1)=56\(\Rightarrow\)x-1=-45-56=-101\(\Rightarrow\)x=-101+1=-100
1)
73+36+968+914+3032
=
=
=
341*67+341*16+659*83
=
=
=
2) tìm x
3636:(12*x-91)=36
(X:23+45)*67=8911
(x-7/8)-15/64=3/4
73+36+968+914+3032
=73+(36+914)+(968+3032)
=73+950+4000
=5023
1) ( mk khong viet lai de dau nhe! )
a)= 73 + ( 36 + 914 ) + ( 968 + 3032 )
= 73 + 950 + 4000
= 1023 + 4000
= 5023
b)=314 x ( 67 + 16) + 659 x 83
= 314 x 83 + 659 x 83
= ( 314 + 659 ) x 83
= 973 x 83
= 80759
1) 73+36+968+914+3032
=(36+914)+(968+3032)+73
=950+4000+73
=5023
341×67+341×16+659×83
=341×(67+16)+659×83
=341×83+659×83
=(341+659)×83
=1000×83
=83000
2)3636÷(12×x-91)=36
<=>12×x-91=3636÷36
<=>12×x-91=101
<=>12×x=101+91
<=>12×x=192
<=>x=192÷12
<=>x=16
Vậy x=16
(x÷23+45)×67=8911
<=>x÷23+45=8911÷67
<=>x÷23+45=133
<=>x÷23=133-45
<=>x÷23=88
<=>x=2024
Vậy x= 2024
(x-7/8)-15/64=3/4
<=>x-7/8=3/4+15/64
<=>x-7/8=63/64
<=>x=63/64+7/8
<=>x=119/64
Vậy x=119/64
Hok tốt
k mk nha
tim x biet 55/8 <x <64/9
quy đồng 55/8=495/72
64/9=512/72
các số trên là 496,497,498,...,511
Bài 5.Tìm x N, sao cho:
a)3636 : (12x –91) = 36
b)(x : 23 + 45) . 67 = 8911
c)[(6x –39) : 7]. 4 = 12
d)(3x –24). 73= 2. 74
e)x(x –10) = 0
f)(x+ 1). (x –2) = 0
g)(9 –x)3= 64
h)3x= 81
i)2 . 3x= 10 . 312+ 8 . 312
j)(19x + 2.52) : 14 = (13 -8)2-42
\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)
TIM SO NGUYEN x , BIET :
a) 3636 : ( 12x - 91) = 36 b) ( x : 23 + 45 ) . 67 = 8911
c) ( 19x + 2.52 ) : 14 = ( 13 - 8 ) 2 - 4 d) -12 . ( x- 5 ) + 7(3 -x ) = 5
a. 3636 : (12x - 91) = 36
=> 12x - 91 = 3636 : 36
=> 12x - 91 = 101
=> 12x = 101 + 91
=> 12x = 192
=> x = 192 : 12
=> x = 16
b. (x : 23 + 45). 67 = 8911
=> x : 23 + 45 = 8911 : 67
=> x : 23 + 45 = 133
=> x : 23 = 133 - 45
=> x : 23 = 88
=> x = 88 . 23
=> x = 2024
c. (19x + 2.52) : 14 = (13 - 8)2 - 4
=> (19x + 2.25) : 14 = 52 - 4
=> (19x + 50) : 14 = 25 - 4
=> (19x + 50) : 14 = 21
=> 19x + 50 = 21. 14
=> 19x + 50 = 294
=> 19x = 294 - 50
=> 19x = 244
=> x = 244 : 19
=> x = 244/19 (Xem lại đề)
d. -12 .(x - 5) + 7.(3 - x) = 5
=> -12x + 60 + 21 - 7x = 5
=> -19x + 81 = 5
=> -19x = 5 - 81
=> -19x = -76
=> x = -76 : (-19)
=> x = 4
tim so tu nhien x biet 55/8<x<64/9
Ta có:
\(\frac{55}{8}=6\frac{7}{8}\) < x < \(\frac{64}{9}=7\frac{1}{9}\)
=> 6 < \(6\frac{7}{8}\) < x = 7 < \(7\frac{1}{9}\)
Vậy x = 7.
Ta có : \(\frac{55}{8}=6\frac{7}{8}\); \(\frac{64}{9}=7\frac{1}{9}\) => x = 7
tim so tu nhien x biet 55/8 < x < 64/9
Tìm số tự nhiên x biết 55/8 < x < 64/9
1. tinh :
a) 15/8 + 3/4 - 5/12
b) 11/24 x 12/33 + 5/6
c) 15/8 + 7/24 : 5/8
2 . tim x, biet :
a) x + 5/8 : 3/4 = 17/9
b) x - 5/9 x 18/15 = 1/3
c) x x7/8 - 5/8 = 13/24
d) X x1/7 + X x 1/4 + X x 1/4 =18
giup mik nhanh nha. mik can gap lam
a)15/8+3/4-5/12
=45+18-10/24
=53/24
b)11/24.12/33+5/6
=11.12/12.2.11.3+5/6
=1/6+5/6
=6/6=1
c)15/8+7/24:5/8
=15/8+7/24.8/5
=15/8+7.8/3.8.5
=15/8+7/15
=đề sai, nếu đúng thì như này
=8/15+7/15
=15/15=1
2. Tim x tren y biet
a. x/y + 4/5 = 8/6
b. x/y - 4/5 = 2/3
c. 5/8 * x/y = 5/12
d. x/y : 2/9 = 3/8