rut gon 65/85
Rut gon phan so 51/85
\(\frac{51}{85}=\frac{51:17}{85:17}=\frac{3}{5}\)
\(\frac{51}{85}=\frac{51:17}{85:17}=\frac{3}{5}\)
Rut gon phan so 39/65
Ta có:\(\frac{39}{65}=\frac{39:13}{65:13}=\frac{3}{5}\)
Vậy phân số \(\frac{39}{65}\) rút gọn được \(\frac{3}{5}\)
Phan so toi gian la 3/5 nha ban
15/65
rut gon
\(\frac{15}{65}=\frac{3\times5}{5\times13}=\frac{3}{13}\)
Rut gon phan so
85-17+34/51 -102
\(\frac{85-17+34}{51-102}\)
\(=\frac{17\left(5-1+2\right)}{51\left(1-2\right)}\)
\(=\frac{17.6}{51.\left(-1\right)}\)
\(=\frac{1.6}{3.\left(-1\right)}\)
\(=\frac{1.2}{1.\left(-1\right)}\)
\(=\frac{2}{-1}\)
\(=-2\)
rut gon phan so
65 phan 91 =
1414 phan 1919 =
65/91=5/7
1414/1919=14/19
ai k mik mik k lại
\(\frac{65}{91}=\frac{65:13}{91:13}=\frac{5}{7}\)
\(\frac{1414}{1919}=\frac{1414:101}{1919:101}=\frac{14}{19}\)
\(\frac{65}{91}=\frac{5}{7}\); \(\frac{1414}{1919}=\frac{14}{19}\)
rut gon roi tinh: (84/144-225/60-169/65):(3/2-64/48-96/42)
84/144 = 7/12 225/60 = 15/4 169/65 = 13/5
64/48 = 4/3 96/42 = 16/7
( 7/12 - 15/4 - 13/5 ) : ( 3/2 - 4/3 - 16/7 )
= -173/30 : -89/42
= 1221/445
84/144 = 7/12;225/60 = 15/4;169/65 = 13/5;64/48 = 4/3;96/42 = 16/7
( 7/12 - 15/4 - 13/5 ) : ( 3/2 - 4/3 - 16/7 )
= -173/30 : -89/42
= 1221/445
rut gon phan so 6539
65 : 13 = 5 ; 39 : 13 = 3 . Phân số tối giản là 5/3
65 phần 39 rút gọn ta được 5 phần 3 cùng chia cho 13
rut gon cac phan so duoi day
12 ,45 ,30 ,25 ,12
16 ,54 ,65 ,75 ,1000
\(\frac{12}{16}=\frac{3}{4}\)
\(\frac{45}{54}=\frac{5}{6}\)
\(\frac{30}{65}=\frac{6}{13}\)
\(\frac{25}{75}=\frac{1}{3}\)
\(\frac{12}{1000}=\frac{3}{250}\)
Rut gon phan so:
2^23 x 45^25 x 13^22 x 35^16/9^26 x 65^22 x 28^17 x 25^9
lam on giup mk dc ko ?
\(\frac{2^{23}\cdot45^{25}\cdot13^{22}\cdot35^{16}}{9^{26}\cdot65^{22}\cdot28^{17}\cdot25^9}=\frac{2^{23}\cdot5^{25}\cdot3^{50}\cdot13^{22}\cdot5^{16}\cdot7^{16}}{3^{52}\cdot5^{22}\cdot13^{22}\cdot7^{17}\cdot2^{54}\cdot5^{18}}=\frac{2^{23}\cdot3^{50}\cdot5^{31}\cdot7^{16}\cdot13^{22}}{2^{54}\cdot3^{52}\cdot5^{22}\cdot7^{17}\cdot13^{22}}=\frac{5^9}{2^{31}\cdot3^2\cdot7}\)