c1) 121

c2) 3600

c1) x = 11 x 11 = 121

c2) a

a) \(85\times16+16\times15\)

\(=16\times\left(85+15\right)\)

\(=16\times100=1600\)

b) \(\left(\dfrac{3}{7}\times\dfrac{11}{15}+\dfrac{3}{7}\times\dfrac{4}{15}\right):\left(4+2\dfrac{6}{11}-\dfrac{6}{11}\right)\)

\(=\left[\dfrac{3}{7}\times\left(\dfrac{11}{15}+\dfrac{4}{15}\right)\right]:\left(4+\dfrac{28}{11}-\dfrac{6}{11}\right)\)

\(=\dfrac{3}{7}\times1:\left(4+2\right)\)

\(=\dfrac{3}{7}:6\)

\(=\dfrac{3}{7}\times\dfrac{1}{6}=\dfrac{3}{42}=\dfrac{1}{14}\)

c) \(x+\left(x+3\right)+\left(x+6\right)+...+\left(x+102\right)=1855\)

\(\Rightarrow35x+\left(3+6+...+102\right)=1855\)

\(\Rightarrow35x+\left(102+3\right)\times34:2=1855\)

\(\Rightarrow35x+1785=1855\)

\(\Rightarrow35x=1855-1785\)

\(\Rightarrow35x=70\)

\(\Rightarrow x=70:35\)

\(\Rightarrow x=2\)

Vậy...

\(#Tmiamm\)

a) 85 x 16 + 16 x 15

= 16 x (85 + 15)

= 16 x 100

= 1600.

b) \(\left(\dfrac{3}{7}\times\dfrac{11}{15}+\dfrac{3}{7}\times\dfrac{4}{15}\right):\left(4+2\dfrac{6}{11}-\dfrac{6}{11}\right)\)

\(=\left[\dfrac{3}{7}\times\left(\dfrac{11}{15}+\dfrac{4}{15}\right)\right]:\left(4+\dfrac{28}{11}-\dfrac{6}{11}\right)\)

\(=\left(\dfrac{3}{7}\times\dfrac{15}{15}\right):\left(4+\dfrac{22}{11}\right)\)

\(=\left(\dfrac{3}{7}\times1\right):\left(4+2\right)\)

\(=\dfrac{3}{7}:6\)

\(=\dfrac{3}{7}\times\dfrac{1}{6}=\dfrac{3}{42}=\dfrac{1}{14}\)

(C) có tâm I(−1;2), bán kính R = 4. (C’) có tâm I′(10; −5), bán kính R’ = 4. Vậy ( C ′ )   =   T v → ( C ) ,   v →   =   I I ' →   =   ( 11 ;   − 7 ) .

mình ko đáng cái j linh tinh hết đây là các bài toán mà mình ko giải đc

b. (x-7)^x+1-(x-7)^x+11=0

(x-7)^x+1.[1-(x-7)¹⁰]=0

=> (x-7)^x+1=0 hoặc 1-(x-7)¹⁰=0

• (x-7)^x+1= 0 => x-7=0 => x=7

• 1-(x-7)¹⁰=0=> (x-7)¹⁰=1=>x-7=1 hoặc x-7=-1 => x=8 hoặc x=6

Vậy x thuộc {6;7;8}

lớp mấy đấy

150-{10²-(14-11)².2007⁰}​

=150-(10²-3².2007⁰)

=150-(100-9-1)

=150-90

=60

7⁰]

= 60