1+1+1+1+1+1+12+123=
H24
Những câu hỏi liên quan
(1/99+12/999+123/9999).(1/2-1/3-1/6)
Chỉ cần tính 1/2-1/3-1/6=6/12-4/12-2/+2=0/12=0
Suy ra (1/99+12/999+123/9999).(1/2-1/3-1/6)=(1/99+12/999+123/9999).0=0
Vậy kết quả là 0.
mk nha
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(1/99+12/999-123/9999).(1/2-1/3-1/6)
(1/99+12/999-123/9999).(1/2-1/3-1/6)
=(9/407-123/9999).0
=0
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(1/99+12/999+123/999).(1/2-1/3-1/6)
( 1/99 + 12/999 + 123/999 ) . ( 1/2 - 1/3 - 1/6 )
= ( 1/99 + 12/999 + 123/999 ) . 0
= 0 nha bn
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(1/99+12/999-123/9999).(1/2-1/3-1/6)
5 6545454ffffffffffg6j544gfs46jh5d641bmc3
q=(1/99+12/999+123/999)*(1/2-1/3-1/6)
q = (1/99+12/999+123/999)*(1/2-1/3-1/6)
= (1/99+12/999+123/999) * 0
= 0
Q=(1/99+12/999-123/9999).(1/2-1/3-1/6)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)0=0\)
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Q= (1/99+12/999+123/999)(1/2-1/3-1/6)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\))
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0=0\)
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Q = (1/99 + 12/999 + 123/999) x (1/2 - 1/3 - 1/6)
Q=(1/99+12/999+123/999)x(1/6-1/6)
Q=(1/99+12/999+123/999)x0
Q=0
học tốt!
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( 1/99 + 12/999 - 123/9999) x (1/2 - 1/3 - 1/6)