Đề sai rồi bạn!!!
 

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\(=>1-\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)

\(=>\frac{43}{8}+x-\frac{173}{24}=1\)

\(=>\frac{43}{8}+x=\frac{197}{24}\)

\(=>x=\frac{17}{6}\)

=>  1 - (43/8+x-173/24) = 0

=>  43/8 + x - 173/24 = 1

=>  43/8 + x = 197/24

=>  x = 17/6

k nha

1-(43/8+x-173/24):50/3=0

(x-11/6):50/3=2

x-11/6=100/3

x=211/6

\(2-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(\left(x-\frac{11}{6}\right)\cdot\frac{3}{50}=2\)

\(\Rightarrow x-\frac{11}{6}=\frac{100}{3}\)

\(\Rightarrow x=\frac{211}{6}\)

\(2-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(2-\left(x+\frac{11}{6}\right):\frac{50}{3}=0\)

\(2-\frac{3}{50}x-\frac{11}{100}=0\)

\(\frac{3}{50}x=\frac{189}{100}\)

\(x=\frac{63}{2}\)

17/6 à

\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=2\)

\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{100}{3}\)

\(\Rightarrow x-\frac{11}{6}=\frac{100}{3}\)

\(\Rightarrow x=\frac{211}{6}\)

a) \(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\Leftrightarrow\frac{11}{15}x=-\frac{2}{5}\Leftrightarrow x=-\frac{6}{11}\)

b) \(\Leftrightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right).-\frac{3}{50}=1\Leftrightarrow\frac{-11}{6}+x=-\frac{50}{3}\Leftrightarrow x=-\frac{37}{2}\)

em bit lam rui