\(\left(2,8.x-32\right):\frac{2}{3}=90\)

\(2,8.x-32=90.\frac{2}{3}\)

\(2,8.x-32=60\)

\(2,8.x=60+32\)

\(2,8.x=92\)

\(x=92:2,8\)

\(x=\frac{230}{7}\)

\(\left(2,8:x-32\right):\frac{2}{3}=-90\)

\(2,8:x-32=\left(-90\right).\frac{2}{3}\)

\(2,8:x-32=-60\)

\(2,8:x=-28\)

\(x=\left(-28\right):2,8\)

\(x=-10\)

\(4-\left|x-2012\right|=\left(-2\right)^2\)

\(4-\left|x-2012\right|=-4\)

\(\left|x-2012\right|=8\)

\(\Rightarrow\orbr{\begin{cases}\left|x-2012\right|=8\\\left|x-2012\right|=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=2020\\x=2004\end{cases}}}\)

(2,8 . x - 32) : 2/3 = -90

(2,8 . x - 32) = -90 x 2/3

(2,8 . x - 32) = -60

2,8 . x = -60 + 32

2,8 . x = -28

x = -28 : 2,8

x = -10

`(2,8 . x - 32) : 2/3 = -90`

`(2,8 . x - 32) = -90 xx (-2/3)`

`2,8 . x = 60 + 32`

`2,8 . x = 92`

`x = 92 : 2,8`

`x = 92/2,8`

\(\left(2,8\cdot x-32\right):\dfrac{2}{3}=-90\)

\(\left(\dfrac{14}{5}\cdot x-32\right):\dfrac{2}{3}=-90\)

\(\dfrac{14}{5}\cdot x-32=\left(-90\right)\cdot\dfrac{2}{3}\)

\(\dfrac{14}{5}\cdot x-32=-60\)

\(\dfrac{14}{5}\cdot x=\left(-60\right)+32\)

\(\dfrac{14}{5}\cdot x=-28\)

        \(x=\left(-28\right):\dfrac{14}{5}\)

        \(x=\left(-28\right)\cdot\dfrac{5}{14}\)

        \(x=-10\)

`a)(4,5-2x)*1 4/7=11/14`

`=>(4,5-2x)*11/7=11/14`

`=>4,5-2x=1/2`

`=>2x=4,5-0,5=4`

`=>x=2`

Vậy `x=2`

`b)(2,8x-32):2/3=-90`

`=>2,8x-32=-90*2/3=-60`

`=>2,8x=-28`

`=>x=-10`

Vậy `x=-10`

Tìm x, biết:

(2,8.x-32):2/3=90

=>(2,8.x-32)  =90.2/3

=>2,8.x-32     =60

=>2,8.x          =60+32

=>x                =92:2,8

=>x                =

Í mà đề sai rồi, xem lại giúp mk nha !

K viết lại đề là:

2,8 x X - 32 = 90 x \(\frac{2}{3}\)

2,8 x X - 32 = \(\frac{180}{3}=60\)

2,8 x X = 60 + 32

2,8 x X = 92

x = 92 : 2,8

x = gần 32 bn nhé, có thể viết thành phân số  nếu bn muốn\(\frac{920}{28}=\frac{230}{7}\)

Hội con 🐄 chúc bạn học tốt!!!

( 2,8x - 32 ) : 2/3 = 90

( 2,8x - 32 ) = 90 . 2/3

( 2,8x - 32 ) = 60

 2,8x = 60 + 32

2,8x = 92

x = 92 : 2,8 

x = 32,8571...

( 2,8x - 32 ) : 2/3 = -90

 2,8x - 32           = -90.2/3

 2,8x - 32           = -60

 2.8x                  = -60+32

 2.8x                  = -28

     x                   = -10 

a) (2,8 . x -32) : 2/3 = -90

=>(2,8x-32):2/3=-90

=>21/5x-48=-90

=>21/5x=-42

=>x=-10

vậy x=-10

\(\left(5+\frac{4}{7}\right):x=13\)

\(\frac{39}{7}:x=13\)

\(x=\frac{39}{7}:13\)

\(x=\frac{3}{7}\)

\(\left[5+\frac{4}{7}\right]:x=13\)

\(\Rightarrow\left[\frac{5\cdot7+4}{7}\right]:x=13\)

\(\Rightarrow\frac{39}{7}:x=13\)

\(\Rightarrow x=\frac{39}{7}:13=\frac{39}{7}\cdot\frac{1}{13}=\frac{3}{7}\cdot\frac{1}{1}=\frac{3}{7}\)

\(\left[2,8\cdot x+32\right]:\frac{2}{3}=90\)

\(\Rightarrow\left[2,8\cdot x+32\right]=90\cdot\frac{2}{3}\)

\(\Rightarrow\left[2,8\cdot x+32\right]=60\)

\(\Rightarrow2,8\cdot x+32=60\)

\(\Rightarrow2,8\cdot x=60-32\)

\(\Rightarrow2,8\cdot x=28\)

Đến đây dễ rồi :v

\(\left(2,8.x+32\right):\frac{2}{3}=90\)

\(2,8.x+32=90.\frac{2}{3}\)

\(2,8.x+32=60\)

\(2,8.x=60-32\)

\(2,8.x=28\)

\(x=28:2,8\)

\(x=10\)