\(\frac{1}{2.4.6}+\frac{1}{4.6.8}+...+\frac{1}{96.98.100}\)
\(\frac{1}{2.4.6}+\frac{1}{4.6.8}+...+\frac{1}{96.98.100}\)
\(\frac{1}{1+2}+\frac{1}{1+2+3}+...+\frac{1}{1+2+...+50}\)
3k cho ai trả lời đúng 2 câu này ^^
1/2.4.6 +1/4.6.8+1/6.8.10+1/8.10.12+1/10.12 .14+..1/96.98.100
Tính E bằng biểu thức sau:
1/2.4.6 + 1/4.6.8 + .... + 1 / 96.98.100
Tính E bằng biểu thức sau:
1/2.4.6 + 1/4.6.8 + .... + 1 / 96.98.100
1
2.4.6
+ 1
4.6.8
+...+1
96.98.100
tính nhanh B= 2.4.6+4.6.8+......+96.98.100
Ta có :
B = 2 . 4 . 6 + 4 . 6 .8 + ......+ 96 .98 .100
B.8 = 2 . 4 . 6 . 8 + 4. 6 . 8 .( 1 0 - 2) +........+96 . 98 . 100 . ( 102 - 94 )
8B = 2 . 4 . 6 .8 + 4. 6 .8 . 10 - 2 . 4 . 6 . 8 +......+ 96 . 98 . 100. 102 - 94 . 96 . 98 . 100
8B = 96 . 98 . 100 . 102
B = 96 . 98 . 100 .1 02 : 8
B = 12 . 98 . 100. 102
Thách ai là người giỏi nhất giải được bài toán này trong mười phút:
Tính tổng:K=1/2.4.6+1/4.6.8+...+1/96.98.100
S=4/1.3.5+4/3.5.7+...+4/95.97.99
Bài này ai giải ra nhanh nhất mình sẽ tick cho nè:
Tính tổng:a)S=4/1.3.5+4/3.5.7+...+4/95.97.99
b) K=1/2.4.6+1/4.6.8+....+1/96.98.100
tôi mới lên lớp 5 thôi nên ko có biết !!!
sorry nha
\(A=\frac{2}{2.4.6}+\frac{2}{4.6.8}+\frac{2}{6.8.10}+\frac{2}{8.10.12}\)
\(A=\frac{2}{2.4.6}+\frac{2}{4.6.8}+\frac{2}{6.8.10}+\frac{2}{8.10.12}\)
\(A=\frac{2}{48}+\frac{2}{192}+\frac{2}{480}+\frac{2}{960}\)
\(A=\frac{1}{24}+\frac{1}{96}+\frac{1}{240}+\frac{1}{480}\)
\(A=\frac{20}{480}+\frac{5}{480}+\frac{2}{480}+\frac{1}{480}\)
\(A=\frac{7}{120}\)
A = \(\dfrac{2}{2.4.6}\) + \(\dfrac{2}{4.6.8}\) + \(\dfrac{2}{6.8.10}\) + \(\dfrac{2}{8.10.12}\)
A = \(\dfrac{2}{2}\).(\(\dfrac{2}{2.4.6}\) + \(\dfrac{2}{4.6.8}\) + \(\dfrac{2}{6.8.10}\) + \(\dfrac{2}{8.10.12}\))
A = \(\dfrac{1}{2}\).(\(\dfrac{2.2}{2.4.6}\) + \(\dfrac{2.2}{4.6.8}\) + \(\dfrac{2.2}{6.8.10}+\dfrac{2.2}{8.10.12}\))
A = \(\dfrac{1}{2}\).( \(\dfrac{4}{2.4.6}+\dfrac{4}{4.6.8}+\dfrac{4}{6.8.10}+\dfrac{4}{8.10.12}\))
A = \(\dfrac{1}{2}\).(\(\dfrac{1}{2.4}\) - \(\dfrac{1}{4.6}\) +\(\dfrac{1}{4.6}\) - \(\dfrac{1}{6.8}\) + \(\dfrac{1}{6.8}\) - \(\dfrac{1}{8.10}\) + \(\dfrac{1}{8.10}\) - \(\dfrac{1}{10.12}\))
A = \(\dfrac{1}{2}\).(\(\dfrac{1}{2.4}\) - \(\dfrac{1}{10.12}\))
A = \(\dfrac{1}{2}\).(\(\dfrac{1}{8}-\dfrac{1}{120}\))
A = \(\dfrac{1}{2}\).\(\dfrac{7}{60}\)
A = \(\dfrac{7}{120}\)