tìm x biết : x^13=27 x^10
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Tìm x biết
a, 53.(3x + 2 ) :13 = 103:(135: 134)
b, 92.4 - 27 = (x + 350) : x +315
a) 53( 3x + 2 ) : 13 = 103 : ( 135 : 134 )
=> 53( 3x + 2 ) : 13 = 103 : 13
=> 53( 3x + 2 ) = 103 : 13 : 13
=> 53( 3x + 2 ) = 103
=> 3x + 2 = 23
=> 3x + 2 = 8
=> 3x = 6
=> x = 2
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Tìm x biết:
a, x+1/10+x+1/11+x+1/12+x+1/13
b,x+10/20+x+8/22=x+6/24+x+3/27
c,x+7/19+x3/15=x+7/16+x+3/15
Bui Bao Ngoc oi! phan a,la (x+1)/10 hay x+(1/10)?
cac phan khac nua!
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Tìm x biết: x − 1 3 = 27
tìm x biết x-13/87+x-27/73+x-67/33+x-73/27=|1-4|.2019^0+1
tìm x;
10/3.x-27/4=13/4
\(\frac{10}{3}.x-\frac{27}{4}=\frac{13}{4}\)
\(\frac{10}{3}.x=\frac{13}{4}+\frac{27}{4}\)
\(\frac{10}{3}.x=10\)
\(x=10:\frac{10}{3}\)
\(x=3\)
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Tìm x biết:
a) ( 19x + 2 . 5^2 ) : 14 = ( 13 - 8 )^2 - 4^2
b)2 . 3^x = 10 . 3^12 + 8 . 27^4
a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot25\right)\div14=5^2-16\)
\(\left(19x+50\right)\div14=25-16=9\)
\(19x+50=9\cdot14=126\)
\(19x=126-50=76\)
\(x=76\div19=4\)
b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)
\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)
\(2\cdot3^x=18\cdot3^{12}\)
\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)
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a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15
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a.(19x+2×25):14=5^2-16
(19x+50):14=25-16
(19x+50):14=9
(19x+50)=9×14=126
19x+50=126
19x=126-50=76
x=76:19
x=4
b.2×3^x=10×3^12+2^3×3^12
2×3^x=3^12×(10+8)
2×3^x=3^12×18
2×3^x=3^12×3^2×2
2×3^x=3^14×2
Suy ra:3^x=3^14
Hay x=14
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Tinh giá trị biểu thuc \(A=x^2+2016-2017\)
Biết \(x=\frac{\left(27+10\sqrt{2}\right)\sqrt{27-10\sqrt{2}}-\left(27-10\sqrt{2}\right)\sqrt{27+10\sqrt{2}}}{\left(\sqrt{\sqrt{13}-3}+\sqrt{\sqrt{13}+3}\right):\sqrt{\sqrt{13}+3}}\)
Tìm số nguyên x, biết 4 – (27 - 3) = x – (13 - 4).
4 – (27 – 3) = x – (13 – 4)
4 – 27 + 3 = x – 13 + 4 (bỏ ngoặc)
4 – 27 + 3 + 13 – 4 = x (chuyển vế –13 và 4)
–27 + 16 = x
–11 = x.
Vậy x = –11.
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1, tìm x, biết :
a, 3(x+1)+4x=10
b, |x+3|=|5-3x|
c, x+1/10+x+2/9=x+3/8+x+4/7
d, x+1/11+x-12/12+x-27/13=x+12/47-5
nhờ mn giúp mk với ạ!
\(\text{a, 3(x+1)+4x=10}\)
\(\Rightarrow3x+3+4x=10\)
\(\Rightarrow7x+3=10\)
\(\Rightarrow7x=10-3=7\)
\(\Rightarrow x=1\)
c, x+1/10+x+2/9=x+3/8+x+4/7
=> (x+1/10 +1) +(x+2/9 +1)= ( x+3/8 +1) +(x+4/7 +1)
=> x+11/10 + x+11/9 = x+11/8 + x+11/7
...............
a) \(3\left(x+1\right)+4x=10\)
\(\Rightarrow3x+3+4x=10\)
\(\Rightarrow3x+4x=10-3\)
\(\Rightarrow7x=7\)
\(\Rightarrow x=7\)