tim x: 720:[41-(2x-5)]=23.5
giúp mih bài này nhé
c) 720 : [41 – (2x + 5)] = 40
giúp làm bài này với ạ:D
\(\text{720 : [41−(2x−5)] = 40720:[41−(2x−5)]=40}\)
\(\text{⇔41−(2x−5)=720:40}\)
\(\text{⇔ 41−2x+5=18}\)
\(\text{⇒ 46 −2x=18}\)
\(\text{⇔2x=28}\)
\(\text{⇔x=14}\)
720:[41−(2x−5)] = 40720:[41−(2x−5)]=40
41−(2x−5)=720:40
41−2x+5=18
46 −2x=18
2x= 46
2x=46-18
2x=28
x=14
vậy x=14
tim x
720:[41-(2x-5)]=23.5
720 : [ 41 - ( 2x-5)] = 2^3 .5
=> 720 :[ 41- (2x-5)] = 40
=> 41 - (2x-5) = 18
=> 2x -5 = 23
=> 2x = 28
=> x=14
tim x
a, ( 2x - 4 ) ^ 3 = 8
b, 720 / [ 41 - ( 2x - 5 ) ] = 2^3 * 5
(2x - 4)3 = 8
(2x - 4)3 = 23
2x - 4 = 2
2x = 2 + 4
2x = 6
x = 6 : 2
x = 3
\(\frac{720}{41-\left(2x-5\right)}=2^3\times5\)
\(\frac{720}{41-2x+5}=8\times5\)
\(46-2x=\frac{720}{40}\)
\(2x=46-18\)
2x = 28
x = 28 : 2
x = 14
Bài 2 (1,5 điểm): Tìm x
a) 9(x + 28) = 0 b) 720 : [41 – (2x – 5)] = 23.5
9. (x + 28) = 0
x + 28 = 0: 9
x + 28 = 0
x = 0 – 28
x = -28
Vậy x = -28.
720:[41-(2x-5)]=23.5
720:[41-(2x-5)]=8.5
720:[41-(2x-5)]=40
41-(2x-5)=720:40
41-(2x-5)=18
2x-5=41-18
2x-5=23
2x=23+5
2x=28
x=28:2
x=14
Vậy x=14
b) 720:[41 -(2x-5)]= 8 . 5
720:[41-(2x-5)]=40
[41-(2x-5)]=720 : 40
[41-(2x-5)]=18
2x-5=41-18
2x-5=23
2x=23+5
2x=28
x=28:2
x=14
Vậy x=14
chắc vại ;-;
tim x thuoc z
1)26-|x+9|=-13
2)|x+7|-13=25
tim x biet
1)123-3.(x+4)=23
2)720:[41-(2x-5)]=23.5
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
Tìm x biết
c ( 3x^2 -6 ) - 43 = 5^3
d) 3x + 2x ( 2^3 . 5 - 3^2 . 4 ) + 5^2 = 4^4
e) 720 : [ 41 - ( 2x - 5 ) ] = 2^3 . 5
Giúp mình gải 3 bài này đi mình cho 1 like, chiều nay nộp rồi!!
c ( 3x2 -6 ) - 43 = 53
( 3x2 -6 ) - 43 = 125
3x2 -6=125+43
3x2 -6=168
3x2=168+6
3x2=174
x2=174:3
x2=58(đề sai)
d) 3x + 2x ( 23 . 5 - 32 . 4 ) + 52 = 44
3x + 2x ( 8 . 5 - 9 . 4 ) + 25 = 256
3x + 2x.4 + 25 = 256
3x + 2x.4=256-25
3x + 2x.4=231
(3+2).x.4=231
5x.4=231
5x=231:4
5x=57,75
x=57,75:5
x=11,55
e) 720 : [ 41 - ( 2x - 5 ) ] = 23 . 5
720 : [ 41 - ( 2x - 5 ) ] =40
41 - ( 2x - 5 )=720:40
41 - ( 2x - 5 )=18
2x - 5=41-18
2x - 5=23
2x=23+5
2x=28
x=28:2
x=14
1.tim x
a) ( 17x-25):8+65=81
b) 720 :[41-(2x-5)]=8.5
c) 231-(x-6)=1339:13
\(a.\left(17x-25\right)\div8+65=81\)
\(\left(17x-25\right):8=81-65\)
\(\left(17x-25\right):8=16\)
\(17x-25=16\times8\)
\(17x-25=128\)
\(17x=128+25\)
\(17x=153\)
\(x=153\div17\)
\(x=9.\)
\(b.720\div\left[41-\left(2x-5\right)\right]=8\times5\)
\(720\div\left[41-\left(2x-5\right)\right]=40\)
\(\left[41-\left(2x-5\right)\right]=720\div40\)
\(\left[41-\left(2x-5\right)\right]=18\)
\(2x-5=41-18\)
\(2x-5=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28\div2\)
\(x=14.\)
\(c.231-\left(x-6\right)=1339\div13\)
\(231-\left(x-6\right)=103\)
\(x-6=231-103\)
\(x-6=128\)
\(x=128+6\)
\(x=134.\)
a) => ( 17x-25 ) : 8 = 16 => ( 17x -25 ) = 128 => 17x = 103 = >x = 103/7
Tim x
720÷[41-(2×x-5)]=120
720 : [ 41 - ( 2 x x -5 ) =120
41 - ( 2 x x - 5 ) = 720 : 120
41 - ( 2 x \(x\) -5 ) =6
2 x \(x\) -5 = 41 - 6
2 x \(x\) - 5 = 35
2 x \(x\) = 35+5
2 x \(x\)=40
\(x\) = 40 : 2 = 20
Vậy x = 20
Ủng hộ nhé ^^
720 : [ 41 - ( 2 x X - 5 ) ] = 120
41 - ( 2 x X - 5 ) = 720 : 120
41 - ( 2 x X - 5 ) = 6
2 x X - 5 = 41 - 6
2 x X - 5 = 35
2 x X = 35 - 5
2 x X = 30
X = 30 : 2
X = 15
Học tốt nhé bạn !
720÷[41-(2×x-5)]=120
41-(2.x-5)=720:120
41-(2.x-5)=6
2.x-5=41-6
2.x-5=35
2.x=35+5
2.x=40
x=40:2
x=20
Vậy.............................................