A = 1X2 +2x3 +...+ 2016x2107

3A = 1x2x3 + 2x3x3 + ...+ 2016x2017x3

3A = 1x2x(3-0) + 2x3x(4-1) + ... + 2016x2017x(2018-1)

3A = 1x2x3 - 1x2x0 +2x3x4 -1x2x3 +...+ 2016x2017x2018 - 2016x2017x2015

Ta loại trừ còn

3A = 2016x2017x2018 - 1x2x0

3A = 2016x2017x2018

A = 2016 x2017 x2018 : 3

A = 1x2 +2x3 +3x4 +...+ 2016 x 2017

3A = 1x2x3 + 2x3x3 +...+2016 x 2017 x3

3A = 1x2x(3-0) + 2x3x(4-1) +...+ 2016x2017x(2018-2015)

\(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{2015\times2016}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2015}-\frac{1}{2016}\)

\(=1-\frac{1}{2016}=\frac{2015}{2016}\)

\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{2015\cdot2016}+\frac{1}{2016\cdot2017}\)

\(\frac{2-1}{1\cdot2}+\frac{3-2}{2\cdot3}+\frac{4-3}{3\cdot4}+...+\frac{2016-2015}{2015\cdot2016}+\frac{2017-2016}{2016\cdot2017}\)

\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2015}-\frac{1}{2016}+\frac{1}{2016}-\frac{1}{2017}\)(làm gọn một chút)

\(1-\frac{1}{2017}=\frac{2016}{2017}\)

Gọi B = 1x2 + 2 x 3 + 3 x 4 + ... + 2016 x2017

    3B = 3 x ( 1x2 + 2x3 + 3x4 + ... + 2016x2017)

         = 1x2x3 + 2x3x3 + 3x4x3 + ... + 2016x2017x3 )

         = 1x2x3 + 2x3x( 4-1) + 3x4x( 5 -2 ) + ... + 2016x2017x( 2018 - 2015)

         = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + ... + 2016x2017x2018 - 2015x2016x2017

         = 2016 x2017 x2018

      B = 672 x2017 x2018

Mà A = \(\frac{672x2017x2018}{2017x2018}\)

         =  672

Vậy A = 672

ai làm nhanh mik cho

mik cho

haizzz đáng tiếc tôi muốn ns là:  ko bao f và đừng mong chờ OK

ai làm dc mik cho

Đéo hiểu 

ai trả lời dc mik cho

ai giai ho mik đi'=))

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