\(\frac{x+16}{35}\)= \(\frac{x}{7}\)
\(\frac{x}{7}=\frac{x+16}{35}\)
Tìm x?
\(\frac{x}{7}=\frac{5x}{35}=\frac{x+16}{35}\)=> 5x = x + 16 => 4x = 16 => x = 16 : 4 = 4
Tìm x:
a) \(\frac{x}{7}\) = \(\frac{x+16}{35}\)
b) \(\frac{2-x}{16}\) = \(\frac{-4}{x-2}\)
c) \(\frac{14}{x}\) = \(\frac{x-1}{4}\)
\(a.\frac{x}{7}=\frac{x+16}{35}\)
\(\Rightarrow35x=7\left(x+16\right)\)
\(\Rightarrow35x=7x+112\)
\(\Rightarrow35x-7x=112\)
\(\Rightarrow28x=112\)
\(\Rightarrow x=112:28\)
\(\Rightarrow x=4\)
\(b.\frac{2-x}{16}=\frac{-4}{x-2}\)
\(\Rightarrow\frac{-\left(x-2\right)}{16}=\frac{-4}{x-2}\)
\(\Rightarrow\frac{x-2}{16}=\frac{4}{x-2}\)
\(\Rightarrow\left(x-2\right)^2=4.16\)
\(\Rightarrow\left(x-2\right)^2=64\)
\(\Rightarrow\left(x-2\right)^2=\left(\pm8\right)^2\)
\(\Rightarrow x-2=8\) hoặc \(x-2=-8\)
+) Nếu \(x-2=8\)
\(\Rightarrow x=8+2\)
\(\Rightarrow x=10\)
+) Nếu \(x-2=-8\)
\(\Rightarrow x=-8+2\)
\(\Rightarrow x=-6\)
Vậy \(x=10;x=-6\)
a) \(\frac{x}{7}=\frac{x+16}{35}\)
\(\Rightarrow35.x=7.\left(x+16\right)\)
\(\Rightarrow35.x=7.x+7.16\)
\(\Rightarrow35x=7x+112\)
\(\Rightarrow35x-7x=112\)
\(\Rightarrow28x=112\)
\(\Rightarrow x=4\)
Vậy .............
a) \(\frac{x}{7}=\frac{x+16}{35}\)
\(\Rightarrow\) x.35 = 7.(x + 16)
x.35 = 7x + 7.16
x.35 = 7x + 112
x.35 - 7x = 112
x.(35 - 7) = 112
x.28 = 112
x = 112 : 28
x = 4
b), c) tương tự
tìm số nguyên x , biết:
a,\(\frac{x}{5}=\frac{x+6}{15}\)
b.\(\frac{x+10}{27}=\frac{x}{9}\)
c,\(\frac{x+16}{35}=\frac{x}{7}\)
a) Ta có: \(\frac{x}{5}=\frac{x+6}{15}\Rightarrow15x=5\left(x+6\right)\)
\(\Rightarrow15x=5x+30\)
\(\Rightarrow10x=30\)
=> x = 3
Vậy x = 3
b) \(\frac{x+10}{27}=\frac{x}{9}\Rightarrow9\left(x+10\right)=27x\)
\(\Rightarrow9x+90=27x\)
\(\Rightarrow18x=90\)
=> x = 5
Vậy x = 5
c) \(\frac{x+16}{35}=\frac{x}{7}\Rightarrow7\left(x+16\right)=35x\)
\(\Rightarrow7x+112=35x\)
\(\Rightarrow28x=112\)
=>x = 4
Vậy x = 4
NĂM MỚI AN LÀNH
ai làm nhanh mk sẽ cho và tặng quà nha nhớ để lại địa chỉ qua tết mk sẽ gửi
Tìm x biết:
a)\(\frac{2}{3}.\left(x-\frac{3}{8}\right)-x-\left(-\frac{7}{8}+\frac{2}{3}\right)=\left(\frac{-3}{4}\right)^3:1\frac{11}{16}\)
b)\(-\frac{7}{8}+\frac{7}{8}:\left(\frac{2}{3}-x\right)+\frac{5}{6}:\left(-1\frac{11}{35}\right)=\left(0,8\right)^2\)
Tìm x:\(\frac{x}{7}=\frac{x+16}{35}\)
( x-2)\(^2\)=25
\(\frac{x}{7}=\frac{x+16}{35}\Leftrightarrow35x=7\left(x+16\right)\)
\(\Leftrightarrow35x-7x=112\)
\(\Leftrightarrow28x=112\Leftrightarrow x=4\)
\(\left(x-2\right)^2=25\Leftrightarrow x-2=5\)
\(\Leftrightarrow x=7\)
Hay tim cac gia tri x nguyen de hai phan so sau bang nhau:\(\frac{x}{7}\),\(\frac{x+16}{35}\)
Ta có : \(\frac{x}{7}\)=\(\frac{x+16}{35}\)<=> 35x=7(x+16)
<=>35x=7x+112
<=>35x-7x=112
<=>28x =112
<=> x = 4
Giải phương trình
a) \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}+\frac{x+1}{3}=x+\frac{7}{12}\)
b) \(\frac{1}{x^2+4x+3}+\frac{1}{x^2+8x+15}+\frac{1}{x^2+12x+35}=\frac{3}{16}\)
a) \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}+\frac{x+1}{3}=x+\frac{7}{12}\)
\(\frac{3.3\left(2x+1\right)}{12}-\frac{2\left(5x+3\right)}{12}+\frac{4\left(x+1\right)}{12}=\frac{12x+7}{12}\)
\(18x+9-10x-6+4x+4=12x+7\)
\(0x=0\) ( vô số nghiệm )
Vậy x \(\in\)R
b) ĐKXĐ : x \(\ne\)-1;-3;-5;-7
\(\frac{1}{x^2+4x+3}+\frac{1}{x^2+8x+15}+\frac{1}{x^2+12x+35}=\frac{3}{16}\)
\(\frac{1}{\left(x+1\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+5\right)}+\frac{1}{\left(x+5\right)\left(x+7\right)}=\frac{3}{16}\)
\(\frac{1}{2}\left(\frac{1}{x+1}-\frac{1}{x+3}+\frac{1}{x+3}-\frac{1}{x+5}+\frac{1}{x+5}-\frac{1}{x+7}\right)=\frac{3}{16}\)
\(\frac{1}{x+1}-\frac{1}{x+7}=\frac{3}{8}\)
\(\left(x+1\right)\left(x+7\right)=16\)
Ta thấy x+1 và x+7 là 2 số cách nhau 6 đơn vị . Mà x + 1 < x + 7
\(\Rightarrow\)\(\hept{\begin{cases}x+1=2\\x+7=8\end{cases}\Rightarrow x=1}\)
hoặc \(\hept{\begin{cases}x+1=-2\\x+7=-8\end{cases}}\Rightarrow\hept{\begin{cases}x=-3\\x=-15\end{cases}}\)( loại )
Vậy x = 1
\(3,2.\frac{15}{16}-\left(75\%+\frac{2}{7}\right):\left(-1\frac{1}{28}\right)\)
\(\left(0,25+12,5-\frac{5}{16}\right):\left[12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right]\)
\(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(14,5-\frac{8}{9}:\left(35-34\frac{8}{9}\right).\frac{9}{8}\)
\(1\frac{1}{15}-\left(\frac{1}{15}+\frac{4}{9}:\frac{-2}{3}-\frac{28}{16}.\frac{6}{35}\right)-\frac{3}{10}\)
Tìm x
\(\left(4,5-2x\right)\left(-3\frac{2}{3}\right)=\frac{11}{15}\)
\(\backslash34-x\backslash=\left(-3\right)^4\)
\(\left(4x^2-1\right)\left(\text{\x}\backslash-\frac{2}{3}\right)=0\)
\(\frac{3}{5}x-\frac{1}{2}\)\(x=\frac{-7}{20}\)
\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)
\(=3-\left(-1\right)\)
\(=4\)
b) \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)
\(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)
\(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)
\(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)
\(=\frac{199}{16}:\left(12-2\right)\)
\(=\frac{199}{16}:10\)
\(=\frac{199}{160}\)
c) \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)
\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)
\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)
nhớ làm giúp mình nhá mai mình phải đi học r :<
Hãy tìm các giá trị nguyên của x để 2 phân số sau bằng nhau: \(\frac{x}{7}\)và \(\frac{x+16}{35}\)