5x-2√x(2+y)+y^2+1=0
Tim cap so x,y thoa man dieu kien tren
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so cac cap so tu nhien (x;y) thoa man dieu kien: (x+3)(y+2)=20
so cap so nguyen x,y thoa man dieu kien 3/x+y/3=5/6 la ... cap
co tat ca bao nhieu cap so tu nhien(x,y) thoa man dieu kien:(2x+1)(y-3)=10
Ta có : 10 = 2 . 5
Ta có bảng sau :
| \(2x+1\) | \(5\) | \(2\) | \(1\) | \(10\) |
| \(y-3\) | \(2\) | \(5\) | \(10\) | \(1\) |
| \(x\) | \(2\) | \(0\) | \(4,5\) | |
| \(y\) | \(5\) | \(8\) | \(13\) | \(4\) |
→ \(x;y=\left\{\left(2;5\right);\left(0;13\right)\right\}\)
Vậy có tất cả 2 cặp số tự nhiên \(x;y\)
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tim cac so nguyen x,y,z thoa man dieu kien sau
x^2=y-1
y^2=z-1
z^2=x-1
Tim cac cap so thuc (x,y) sao cho x va y thoa man dong thoi 2 dieu kien:x=x2+y2 va y=2xy
1) Tim x biet :
a) \(\frac{2}{3}x-70\frac{10}{11}:\left(\frac{131313}{151515}+\frac{131313}{353535}+\frac{131313}{636363}+\frac{131313}{999999}\right)=-5\)
2) a) Tim cac cap so thuc (x,y) sao cho x,y thoa man dong thoi 2 dieu kien sau:
x=\(x^2+y^2\)va \(y=2xy\)
tim cap so x,y thoa man:
5x-2canx(2+y)+y^2+1=0
Tim cac cap so nguyen thoa man dieu kien :
1/a+b/2=5/8
Tim cac so x va y thoa man dieu kien : 13x2 +4y2 +12xy + 26x + 4y + 26 =0