7+3+100+100
\(\left(\frac{75}{100}-\frac{60}{100}+\frac{3}{7}+\frac{3}{11}\right)+\left(\frac{275}{100}-\frac{220}{100}+\frac{11}{7}+\frac{11}{13}\right)\)
\(\left(\frac{75}{100}-\frac{60}{100}+\frac{3}{7}+\frac{3}{11}\right)+\left(\frac{275}{100}-\frac{220}{100}+\frac{11}{7}+\frac{11}{13}\right)\)\(=\frac{1311}{1540}+5\frac{331}{420}\)\(=6\frac{211}{330}\)
HỌC TỐT!!!
\(\left(\frac{75}{100}-\frac{60}{100}+\frac{3}{7}+\frac{3}{11}\right)+\left(\frac{275}{100}-\frac{220}{100}+\frac{11}{7}+\frac{11}{13}\right)\)
\(=\frac{3}{20}+\frac{3}{7}+\frac{3}{11}+\frac{11}{20}+\frac{11}{7}+\frac{11}{13}\)
\(=\frac{14}{20}+\frac{14}{7}+\frac{160}{143}=\frac{3231}{715}+\frac{14}{7}=\frac{4661}{715}\)
Đúng ghi Đ, sai ghi S
a) \(\dfrac{3}{10}< 0,3\) .......
\(\dfrac{3}{10}=0,3\) .......
b)\(\dfrac{135}{100}=1,35\) ....
\(\dfrac{135}{100}>1,35\) ........
c) 1\(\dfrac{7}{100}>1,7\) ......
1\(\dfrac{7}{100}< 1,7\)
B=1/7+2/7^2+3/7^3+...+100/7^100. Chứng minh B ko phải là số nguyên
ad em cố gắng giải nhh giùm mik , mik cần gấp mai đi học
7/10= ; 7/100=; 6 38/100=; 2014/1000=; 3/2=; 2/5=; 5/8=; 1 1/4=; 6 38/100=; 600/38=
\(\dfrac{7}{10}=0,7;\dfrac{7}{100}=0,07;6\dfrac{38}{100}=6,38;\dfrac{2014}{1000}=2,014;\dfrac{3}{2}=1,5;\dfrac{2}{5}=0,4;\dfrac{5}{8}=0,625;1\dfrac{1}{4}=1,25;6\dfrac{38}{100}=6,38\)
Tính A=(36-36/7^100) : (1/7 + 1/7^2 + 1/7^3 + ... + 1/7^100)
so sánh
P=\(\dfrac{1+7^2+7^3+...+7^{100}}{1+7^2+7^3+...+7^{99}}\)
Q=\(\dfrac{1+9^2+9^3+...+9^{100}}{1+9^2+9^3+...+9^{99}}\)
CMR \(\frac{1}{7}+\frac{2}{7^2}+\frac{3}{7^3}+...+\frac{100}{7^{100}}< \frac{7}{36}\)
b, tinh
(36 - 36/76^100 ) : (1/7 + 1/7^2 +1/7^3 + ... +1/7^100)
(1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+8+...+100+100).(89.2)
2.(1+2+3+4+.....+100).(89.2)
2.5050.89.2
2(5050.89)
=898900
(1+1+2+2+3+3+4+4+5+5+6+6+...+100+100)* (89 *2 )
=(1+100)+(1+100)+(2+99)+...+(54+57)+(55+56)+(55+56)*187
=101+101+101+...+101+101+101*187
=101*100*187
=10100*187=1888700
2(1+2+3+...+100).89.2=2.5050.89.2=1797800