?!

:))

Spam ko zui đâu cj:)

a) \(6⋮\left(x-1\right)\left(đkxđ:x\ne1;x\inℕ\right)\)

\(\Rightarrow x-1\in U\left(6\right)=\left\{1;2;3;6\right\}\)

\(\Rightarrow x\in\left\{2;3;4;7\right\}\)

b) \(14⋮\left(2x+3\right)\left(đkxđ:x\ne-\dfrac{3}{2};x\inℕ\right)\)

\(\Rightarrow2x+3\in U\left(14\right)=\left\{1;2;7;14\right\}\)

\(\Rightarrow x\in\left\{-1;-\dfrac{1}{2};2;\dfrac{9}{2}\right\}\)

\(\Rightarrow x\in\left\{-2\right\}\)

\(a,6⋮\left(x-1\right)\\ \Rightarrow\left(x-1\right)\inƯ\left(6\right)=\left\{\pm1;\pm2;\pm3;\pm6\right\}\\ Ta.có:x-1=-6\Rightarrow x=-5\left(loại\right)\\ x-1=-3\Rightarrow x=-2\left(loại\right)\\ x-1=-2\Rightarrow x=-1\left(loại\right)\\ x-1=-1\Rightarrow x=0\left(nhận\right)\\ x-1=1\Rightarrow x=2\left(nhận\right)\\ x-1=2\Rightarrow x=3\left(nhận\right)\\ x-1=3\Rightarrow x=4\left(nhận\right)\\ x-1=6\Rightarrow x=7\left(nhận\right)\\ Vậy:x\in\left\{0;2;3;4;7\right\}\)

\(\text{1) -5x - (-3)= 13}\)

\(\Rightarrow-5x=10\)

\(x=10:-5\)

\(x=-2\)

\(\text{2) |x-3| - 7= 13}\)

\(\Rightarrow|x-3|=20\)

\(\Rightarrow\orbr{\begin{cases}x-3=20\\x-3=-20\end{cases}\Leftrightarrow\orbr{\begin{cases}x=23\\x=-17\end{cases}}}\)

\(\text{3) 17- (43 - |x|)= 45}\)

\(\Rightarrow43-|x|=-28\)

\(|x|=71\)

\(\Rightarrow\orbr{\begin{cases}x=71\\x=-71\end{cases}}\)

\(\text{5) (x-2).(x+15)= 0}\)

\(\Rightarrow\orbr{\begin{cases}x-2=0\\x+15=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-15\end{cases}}}\)

4,\(\text{4) (x-3).(x-5) < 0}\)\(\left(x-3\right).\left(x-5\right)< 0\)

\(\Rightarrow\left(x-3\right)\)và \(\left(x-5\right)\)trái dấu

Mà \(\left(x-3\right)>\left(x-5\right)\Rightarrow\left(x-3\right)>0\)và \(\left(x-5\right)< 0\)

\(+,x-3>0\Rightarrow x>3\)

\(+,x-5< 0\Rightarrow x< 5\)

\(\Rightarrow3< x< 5\)

\(\)Mà \(x\in Z\)

\(\Rightarrow x=4\)

học tốt

1<=>-5x+3=13

<=>-5x=10

<=>x=-2

2<=>|x-3|=20

th1:x-3=20

<=>x=23

th2:x-3=-20

<=>x=-17

3,<=>17-43+|x|=45

<=>|x|=71

th1:x=71

th2:x=-71

4<=>x-3<0                  x-5>0

<=>x<3                       x>5(loại vì ko có số naod vừa lớn hơn 5 và nhỏ hơn 3)

<=>x-3>0                   x-5<0

<=>x>3                      x<5

=>3<x<5

5,<=>x-2=0                  x+15=0

<=>x=2                       x=-15

https://www.youtube.com/channel/UCb2H-q6FmW61PgcsL1OGPfw ủng hộ bạn t:))

1) -5x- (-3)= 13

=>-5x +3= 13   => -5x = 10  => x = 10: (-5)   => x =-2

2) |x-3|- 7=  13

=>|x-3|= 20  =>  \(\orbr{\begin{cases}x-3=20\\x-3=-20\end{cases}}\Rightarrow\orbr{\begin{cases}x=20+3\\x=3-20\end{cases}}\Rightarrow\orbr{\begin{cases}x=23\\x=-17\end{cases}}\)

4)

 \(17-\left(43-\left|x\right|\right)=45\\ \Rightarrow43-\left|x\right|=-28\Rightarrow\left|x\right|=71\Rightarrow\orbr{\begin{cases}x=71\\x=-71\end{cases}}\)

5)\(\left(x-2\right).\left(x+15\right)=0\Rightarrow\orbr{\begin{cases}x-2=0\\x+15=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-15\end{cases}}\)

`a,MSC:45`

`7/9=(7xx5)/(9xx5)=35/45`

`2/5=(2xx9)/(5xx9)=18/35`

`b,MSC:21`

`6/7=(6xx3)/(7xx3)=18/21`

`17/21` giữ nguyên

`c,MSC:36`

`2/3=(2xx12)/(3xx12)=24/36`

`1/4=(1xx9)/(4xx9)=9/36`

`5/9=(5xx4)/(9xx4)=20/36`

\(a,\dfrac{7}{9}=\dfrac{7.5}{9.5}=\dfrac{35}{45}\\\dfrac{2}{5}=\dfrac{2.9}{5.9}=\dfrac{18}{45}\\ b,\dfrac{6}{7}=\dfrac{6.3}{7.3}=\dfrac{18}{21}\\ \dfrac{17}{21}giữnguyên\\ c,\dfrac{2}{3}=\dfrac{2.12}{3.12}=\dfrac{24}{36}\\ \dfrac{1}{4}=\dfrac{1.9}{4.9}=\dfrac{9}{36}\\ \dfrac{5}{9}=\dfrac{5.4}{9.4}=\dfrac{20}{36}\)

\(\left(x-1\right).\left(y-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\y-2=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0+1\\x=0+2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=2\end{cases}}\)

\(b,\left(2.x-1\right).\left(3y-6\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2.x-1=0\\3.y-6=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=1\\3y=6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\y=2\end{cases}}}\)

a) ( x-1 ) . ( y-2 ) = 0

=> x-1=0 hoặc y-2=0

+> x-1=0

x=0+1

x=1

+>y-2=0

y=0+2

y=2

Vậy x=1 ; y=2

 b) (2.x -1) . (3.y-6) =0

=> 2x-1=0 hoặc 3y-6=0

=> 2x-1=0

2x=0+1

2x=1

x=1:1

x=1/2

+>3y-6=0

3y=0+6

3y=6

y=6:3

y=2

Vậy x=1/2 , y = 2

\(\left(x-1\right).\left(y-2\right)=0\)

\(=>\orbr{\begin{cases}x-1=0\\y-2=0\end{cases}}\)

\(=>\orbr{\begin{cases}x=1\\y=2\end{cases}}\)

Vậy....

a ) 13/20

B)

C..........................................................

minh dang tính

lấy máy tính mà bấm

trả lời kiểu gì vậy hả bạn lê thế trung

Th1    x-5/3 < 1/3    suy ra x < 1/3 + 5/3  (câu b)

x<2

th2      x-5/3< -1/3    suy ra x < -1/3+5/3

x<4/3