`A=1/2.3+1/3.4+...+1/99.100`

`=1/2-1/3+1/3-1/4+...+1/99-1/100`

`=1/2-1/100`

`=50/100-1/100`

`=49/100`

1/2 + 1/3 + 1/4 + 1/5 + 100

= 30/60 + 20/60 + 15/60 + 12/60 + 100

= 77/60 +100

= 385/300 + 300/300

= 685/300

= 137/100

a)   \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).\left(1-\frac{1}{5}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}\)

\(=\frac{1}{5}\)

b)   \(\left(1-\frac{3}{4}\right).\left(1-\frac{3}{7}\right).\left(1-\frac{3}{10}\right)........\left(1-\frac{3}{97}\right).\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.......\frac{94}{97}.\frac{97}{100}\)

\(=\frac{1}{100}\)

a) B= 1 + 3 + 7 + 9 +...+ 99

= ( 1 + 99 ) + ( 97 + 3 ) + ( 95 + 5 ) + ( 93 + 7 ) + ( 91 + 9 ) + ( 89 + 11 ) + ... ,

(Tổng cộng có 25 cặp có tổng là 100.)
= 25 x 100.
B = 2500.

b,    C = 1+4+7+10+..............+100

Số số hạng là : 

(100-1) : 3 + 1 = 34 (số)

C = (100+1) x 34 : 2 

C = 101 x 34  : 2

C = 3434 : 2

C = 1717

a) 3A=1.2.3 + 2.3.3 + 3.4.3 +... + n.(n+1).3

=1.2.(3-0) + 2.3.(4-1) + ... + n.(n+1).[(n+2)-(n-1)]

=[1.2.3+ 2.3.4 + ...+ (n-1).n.(n+1)+ n.(n+1)(n+2)] - [0.1.2+ 1.2.3 +...+(n-1).n.(n+1)] 

=n.(n+1).(n+2) 

=>S=[n.(n+1).(n+2)] /3

b)

Nhân 4 vào hai vế ta được:

4A = 4.[1.2.3 + 2.3.4 + 3.4.5 + … + (n – 1).n.(n + 1)]

4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + … + (n – 1).n.(n + 1).4

4A = 1.2.3.4 + 2.3.4.(5 – 1) + 3.4.5.(6 – 2) + … + (n – 1).n.(n + 1).[(n + 2) – (n – 2)]

4A = 1.2.3.4 + 2.3.4.5 – 1.2.3.4 + 3.4.5.6 – 2.3.4.5 + … + (n – 1).n(n + 1).(n + 2) – (n – 2).(n – 1).n.(n + 1)

4A = (n – 1).n(n + 1).(n + 2)

A = (n – 1).n(n + 1).(n + 2) : 4.

3A=1.2.3 + 2.3.3 + 3.4.3 +... + n.(n+1).3

=1.2.(3-0) + 2.3.(4-1) + ... + n.(n+1).[(n+2)-(n-1)]

=[1.2.3+ 2.3.4 + ...+ (n-1).n.(n+1)+ n.(n+1)(n+2)] - [0.1.2+ 1.2.3 +...+(n-1).n.(n+1)] 

=n.(n+1).(n+2) 

=>S=[n.(n+1).(n+2)] /3

làm được mình cho,thanks