tim x biet x^2=100
Tim x biet : ( x + 1 ) + ( x + 2 ) + ... + ( x + 100 ) = 5750
( x + 1 ) + ( x + 2 ) + ... + ( x + 100 ) = 5750
x + 1 + x + 2 + ... + x + 100 = 5750
( x + x + ... + x ) + ( 1 + 2 + ... + 100 ) = 5750
Số số hạng là : ( 100 - 1 ) : 1 + 1 = 100 ( số )
Tổng là : ( 100 + 1 ) x 100 : 2 = 5050
=> 100a + 5050 = 5750
=> 100a = 700
=> a = 7
Tim x biet : ( x + 1 ) + ( x + 2 ) + ... + ( x + 100 ) = 5750
x . 100 + ( 1 + 2 + ... + 100) = 5750
x . 100 + 101 . 100 : 2 = 5750
x . 100 + 101 . 50 = 5750
x . 100 + 5050 = 5750
x . 100 = 700 => x = 7
Ta có: ( x+1) + (x+2) + (x+3) +...+ ( x+100) = 5750
<=> ( x + x + x + ...... + x ) + (1 + 2 + 3 + ..... + 100) = 5750
<=> 100x + 5050 = 5750
=> 100x = 5750 - 5050
=> 100x = 700
=> x = 700 : 100
=> x = 7
tim x biet (x+1)+(x+2)+(x+3)+...+(x+100) =570
\((x+1)+(x+2)+(x+3)+...+(x+100)=570\)
\(\Rightarrow(x+x+x+...+x)+(1+2+3+...+100)=570\)
\(\Rightarrow100x+\frac{(1+100)\cdot100}{2}=570\)
\(\Rightarrow100x+5050=570\)
\(\Rightarrow100x=570-5050\)
\(\Rightarrow100x=-4480\)
\(\Rightarrow x=-44,8\)
P/S : Làm bừa :> Hoq chắc
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=570\)
\(\left(x+x+x+...+x\right)+\left(1+2+...+100\right)=570\)
\(100x+5050=570\)
\(100x=-4480\)
\(x=-44,8\)
T sửa đề =)))
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
\(\left(x+x+...+x\right)+\left(1+2+...+100\right)=5750\)
\(100x+5050=5750\)
\(100x=700\)
\(x=7\)
tim x biet : (x+1)+(x+2)+(x+3)+...+(x+100)=5550
=> (x+1+x+100) x 100 : 2 = 5550
=> (2x+101) x 100 = 5550 x 2 = 11100
=> 2x+101 = 11100 + 100 = 111
=> 2x = 111-101 = 10
=> x = 10 : 2 = 5
k mk nha
(x+1)+(x+2)+(x+3)+...+(x+100)=5550
=> (x+x+x+...+x)+...+(1+2+3+...+100)=5550
=> 100x+5050=5550
100x=5550-5050
100x=500
x=500:100
x=5
Tim x biet (x+1)+(x+2)+(x+3)........+(x+100)=5750
=100.x + (1+2+3+....+100 )
=100.x +100.101/2
=>100x +101 + 50 =5750
100x =5750 -5050 =700
=>700 :100 = 7
Vậy X = 7
[x+1]+[x+2]+...+[x+100]=5750
[1+2+...+100].x=5750
Số các số hạng:
(100-1):1+1=100 số
=>có 100 thừa số x
Tổng trên là:
(1+100)x100:2=5050
=>x.100=5750-5050
=>x.100=700
=>x=700:100
=>x=7
Vậy x = 7
Ta có: (x + 1) + (x + 2) +...+ (x + 100) = 5750
=> (x + x + x +...... +x) + (1 + 2 + 3 + 4 + ... + 100) = 5750
=> 100x + 5050 = 5750
=> 100x = 5750 - 5050
=> 100x = 700
=> x = 700 : 100
=> x = 7
Tim X, biet: X x 2 + X x 3 + X x 4 + X = 100
X x 2 + X x 3 + X x 4 + X = 100
X x 2 + X x 3 + X x 4 + X x 1 = 100
X x (2+3+4+1)=100
X x 10=100
X =100:10
X=10
>>>>>Ai không hiểu chỗ nào trong đáp án của mình thì hỏi mình nhé!
\(x\times2+x\times3+x\times4+x=100\)
\(\Leftrightarrow x\times2+x\times3+x\times4+x\times1=100\)
\(\Leftrightarrow x\times\left(2+3+4+1\right)=100\)
\(\Leftrightarrow x\times10=100\)
\(\Leftrightarrow x=100\div10\)
\(\Leftrightarrow x=10\)
Vậy x = 10.
tim x biet (x+1)+(x+2)+(x+3)+⋯+(x+100)=5750
(x+1)+(x+2)+(x+3)+....+(x+100)=5750
100x+(1+2+3+...+100)=5750
100x+5050=5750
100x=5750-5050
100x=700
x=700:100
x=7
<=>(x+x+x..+x)+(1+2+...+100)=5750
=>100x+5050=5750
=>100x=700
=>x=700:100
=>x=7
Ta có:
(x+1)+(x+2)+(x+3)+...+(x+100)=(x*100)+(1+2+3+...+100)=5750
Ta có từ 1 đến 100 có số số hạng là:
(100-1):1+1=100(số số hạng)
Tổng từ 1 đến 100 là:
(100+1)*100:2=5050
x*100 bằng là:
5750-5050=700
x bằng là:
700/100=7
Tim x biet (x + 2) + (x + 4) + (x + 6) + ... + (x + 100) = 2700
(x+2)+(x+4)+(x+6)+...+(x+100) = 2700
=> 50x + (2+4+6+...+100) = 2700
=> 50x + 2550 = 2700
=> 50x = 2700 - 2550
=> 50x = 150
=> x = 3
(x+2)+(x+4)+(x+6)+...+(x+100)=2700
>50x+(2+4+6+...+100) =2700
>50x+2550 =2700
>50x =2700-2550
> 50x =150
> x =150:50
>x =3
Vậy X=3 thì (x+2)+(x+4)+(x+6)+...+(x+100) =2700
tim x biet ;100(x-3).(x-2)=1
100(x-3).(x-2) = 1
=> 100(x-3).(x-2) = 1000
=> (x - 3)(x - 2) = 0
=> x - 3 = 0 => x = 3
hoặc x - 2 = 0 => x = 2
Vậy x = 3; x = 2
Tim x ,biet :100:2 nhan {x+1]=25
50 x {x+1} = 25
{x+1} = 50 : 2
{x+1} = 2
x = 2-1=1
\(\frac{100}{2}\left(x+1\right)=25\)
\(=>50\left(x+1\right)=25\)
\(=>x+1=\frac{25}{50}\)
\(=>x+1=\frac{1}{2}\)
\(=>x=\frac{1}{2}-1\)
\(=>x=-\frac{1}{2}\)
100 : 2 . ( x + 1 ) = 25
=> 50 . ( x + 1 ) = 25
=> x + 1 = 25 : 50
=> x + 1 = 0,5
=> x = 0,5 - 1
=> x = - 0,5
Vậy x = - 0,5