Ta có ; \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)

\(=\frac{-7}{25}.1-\frac{18}{25}\)

\(=\frac{-7}{25}-\frac{18}{25}=\frac{-25}{25}=-1\)

mk ko ghi lại đầu bài nhé

=-7/25.(11/13+2/13)-18/25

=-7/25.1-18/25

=-7/25-18/25

=-25/25

=-1  

~ chúc bạn học toots~ k mk nha

Thanks mina-san nhiều ~!♥ Arigatou gozaimatsu~

Giải:

\(-\dfrac{7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}+2018\dfrac{7}{25}\)

\(=-\dfrac{7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}+2018+\dfrac{7}{25}\)

\(=-\dfrac{7}{25}.\left(\dfrac{11}{13}+\dfrac{2}{13}\right)+2018+\dfrac{7}{25}\)

\(=-\dfrac{7}{25}.1+2018+\dfrac{7}{25}\)

\(=-\dfrac{7}{25}+2018+\dfrac{7}{25}\)

\(=2018\)

Vậy ...

\(a,\dfrac{\left(-11\right).3+7.\left(-11\right)}{\left(-15\right).22}=\dfrac{\left(-11\right).\left(3+7\right)}{\left(-15\right).22}=\dfrac{-11.10}{-15.22}=\dfrac{-11.2.5}{-11.3.5+2.11}=\dfrac{-1}{-3}=\dfrac{1}{3}\\ \dfrac{25.11}{15.37-15.48}\\ =\dfrac{5.5.11}{15.\left(37-48\right)}=\dfrac{5.5.11}{15.\left(-11\right)}=\dfrac{5.5.11}{3.5.\left(-11\right)}=\dfrac{5}{-3}=-\dfrac{5}{3}\\ \dfrac{-2.3.5^2}{3^2.5^3}=\dfrac{-2}{3.5}=-\dfrac{2}{15}\)

Câu cuối là dấu âm ở giữa phân số nhé

\(\dfrac{\left(-11\right).3+7.\left(-11\right)}{\left(-15\right).22}=\dfrac{-33+\left(-77\right)}{-330}=\dfrac{-110}{-330}=\dfrac{110}{330}=\dfrac{1}{3}\)

\(\dfrac{25.11}{15.37-15.48}=\dfrac{275}{15.\left(37-48\right)}=\dfrac{275}{15.\left(-11\right)}=\dfrac{275}{-165}=-\dfrac{5}{3}\)

\(\dfrac{-2.3.5^2}{3^2.5^3}=\dfrac{-2}{3.5}=-\dfrac{2}{15}\)

\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}=5:\frac{1}{7}=35\)

Bạn vào fx gõ cho rõ ra được không?

\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)

\(=\frac{5^{21}.\left(2.5-9\right)}{5^{20}}:\frac{5.7^{14}\left(3.7-19\right)}{7^{15}\left(7+3\right)}\)

\(=5:\frac{5.2}{7.10}\)

\(=5:\frac{1}{7}\)

\(=35\)

gì ghi ra

\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\\ =\frac{5^{21}.\left(10-9\right)}{5^{20}}.\frac{7^{15}.\left(7+3\right)}{5.7^{14}.\left(21-19\right)}\\ =5.\frac{70}{10}\\ =5.7\\ =35\)

\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)

\(=\frac{5^{20}\left(2.5^2-9.5\right)}{5^{20}}:\frac{5.7^{14}\left(3.7-19\right)}{7^{14}\left(7^2+3.7\right)}\)

\(=\left(50-45\right):\frac{5\left(21-19\right)}{49+21}\)

\(=5.\frac{70}{10}=35\)