so sanh N= -7/10^2005 + -15/10^2006 va M= -15/10^2005 + -7/10^2006
NT
Những câu hỏi liên quan
so sanh N= -7/102005+ -152006 va M= -15/102005+-7/102006
so sanh N= -7/102005+ -152006 va M= -15/102005+-7/102006
So sanh ko qua quy dong A=-7/10^2005+-15/10^2006 va B=-15/10^2005+-7/10^2006
so sanh M = -7/ 102005 + -15/ 102006 va N = -15/ 102005 + -7/102006
\(y=\frac{ }{x^2+\sqrt{x}}\)
so sanh khong qua quy dong A=-7/102005+-15/102006;B=-15/102005+-7/102006
So sánh
N=-7/10^2005+-15/10^2006
M=-15/10^2005+-7/10^2006
So sanh : A = -7/10^2005 + -15/10^2006
B = -15/10^2005 + -7/10^2006
So sánh;
N=-7/10^2005 + -15/10^2006
M=-15/10^2005 + -7/10^2005
so sánh : N=\(\frac{-7}{10^{2005}}+\frac{-15}{10^{2006}}vàM=\frac{-15}{10^{2005}}+\frac{-7}{10^{2006}}\)
Xét N ta có :
N = \(\frac{-7}{10^{2005}}\)+ \(\frac{-15}{10^{2006}}\)
N = \(\frac{-7}{10^{2005}}\)+ \(\frac{-7}{10^{2006}}\)+\(\frac{-8}{10^{2006}}\)
Xét M ta có :
M = \(\frac{-15}{10^{2005}}\)+\(\frac{-7}{10^{2006}}\)
M = \(\frac{-8}{10^{2005}}\)+\(\frac{-7}{10^{2005}}\)+ \(\frac{-7}{10^{2006}}\)
Vì \(\frac{-8}{10^{2006}}\)< \(\frac{-8}{10^{2005}}\) => N < M
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ta có:M-N=\(\dfrac{-15}{10^{2005}}-\dfrac{-7}{10^{2005}}+\dfrac{-7}{10^{2006}}-\dfrac{-15}{10^{2006}}\)
=\(\dfrac{-8}{10^{2015}}\)+\(\dfrac{8}{10^{2016}}\)=8(\(\dfrac{1}{10^{2006}}-\dfrac{1}{10^{2005}}\))
Ta có:102006>102005<=>\(\dfrac{1}{10^{2006}}< \dfrac{1}{10^{2005}}\)
<=>\(\dfrac{1}{10^{2006}}-\dfrac{1}{10^{2005}}< 0\)
=>M-N<0 hay N>M
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