\(\dfrac{989898}{454545}-\dfrac{31313131}{15151515}=\dfrac{98\cdot10101}{45\cdot10101}-\dfrac{31\cdot1010101}{15\cdot1010101}\\ =\dfrac{98}{45}-\dfrac{31}{15}=\dfrac{98-31\cdot3}{45}=\dfrac{5}{45}=\dfrac{1}{9}\)

\(\dfrac{1}{9}\)

98-9+98988+989898x99=98-9+98988+97999902=89+98988+97999920=98098997

191919/282828

Ta có : 191919/282828 = \(\frac{191919:10101}{282828:10101}=\frac{19}{28}\)

Vậy đáp án là : 19/28

k cho tớ nha bn

191919/282828=\(\frac{191919:10101}{282828:10101}=\frac{19}{28}\)

191919/282828=19/28

Gọi A=\(\frac{989898.89-898989.98}{2^3+3^4+...+2014^{2015}}\)

A=\(\frac{98.10001.89-89.10001.98}{2^3+3^4+...+2014^{2015}}\)

A=\(\frac{98.89.\left(10001-10001\right)}{2^3+3^4+...+2014^{2015}}\)

A=\(\frac{98.89.0}{2^3+3^4+...+2014^{2015}}\)

A=\(\frac{0}{2^3+3^4+...+2014^{2015}}\)

A=0

k cho mình nha!

\(\frac{989898.89-898989.98}{2^3+3^4+4^5+...+2014^{2015}}\)\(=\frac{10101.98.89-10101.89.98}{2^3+3^4+4^5+...+2014^{2015}}\)\(=\frac{0}{2^3+3^4+4^5+...+2014^{2015}}\)

                                                                                                                    \(=0\)

Mình đang cần gấp.Giúp mình với. 

a=\(\frac{1}{9}\)

c=\(\frac{3069}{500}\)

= 98/45-31/15

=1/9

30303/474747=(10101x3)/(10101x47)=3/47

mấy câu sau tương tự nha e tách 10101 ra

Trả lời: 

\(\frac{303030}{474747}=\frac{303030:10101}{474747:10101}=\frac{30}{47}\)                                          \(\frac{212121}{353535}=\frac{212121:10101}{353535:10101}=\frac{21}{35}\)                       

 \(\frac{676767}{656565}=\frac{676767:10101}{656565:10101}=\frac{67}{65}\)                                      \(\frac{323232}{989898}=\frac{323232:10101}{989898:10101}=\frac{32}{98}\)

lạy bạn. nó chưa phải phân số tối giản + sai câu đầu