a)E=1+3+6+...+4950

  2E=1.2+3.2+6.2+...+4950.2

  2E=2+6+12+...+9900

Ta có: Xét D=1.2+3.2+6.2+...+4950.2

               3D=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100

                3D=99.100.101

                  D=333300

Thay D vào E ta được 2E=333300 => E=166650

b)B=1+3+6+12+...+9900

  2B=1.2+3.2+6.2+12.2+...+9900.2

   2B=2+6+12+24+...+19800

Ta có xét A=1.2+3.2+6.2+12.2+...+9900.2

              3A=1.2.3+3.2.6-1.2.3+...100.2.3

              3A=98.100.102

              A=33320

            ta thay A vào B; 2B=33320=>B=16660

=(4950-1) cgia cho 2 +1=................................

Các bạn nhớ ủng hộ cho nhất sông núi  nhé

Cảm ơn bạn

A = 1 . 2 + 2 . 3 + 3 . 4 + ... + 99 .100

3 . A = 1. 2 . 3 + 2 . 3 . 3 + 3 . 4 . 3 + ... + 99 . 100 . 3

3 . A = 1 . 2 . 3 + 2 . 3 . ( 4 - 1 ) + 3 . 4 . ( 5 - 2 ) + ... + 99 . 100 . ( 1001 - 998 )

3 . A = 1 . 2 . 3 + 2 . 3 . 4 - 1 . 2 . 3 + 3 . 4 . 5 - 2 . 3 . 4 + ... + 99 . 100 . 1001 - 998 . 99 . 100

3 . A = 99 . ( 100 . 10 )

A = ( 99 . 100 . 10 ) : 3

A = 33000

\(A=\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+...+\frac{9901}{9900}=\left(1+\frac{1}{2.3}\right)+\left(1+\frac{1}{3.4}\right)+\left(1+\frac{1}{4.5}\right)+...+\left(1+\frac{1}{99.100}\right)\)\(=\left(1+1+1+...+1\right)+\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\right)\)

\(=98+\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\right)=98+\left(\frac{1}{2}-\frac{1}{100}\right)\)

\(=98+\frac{49}{100}=98\frac{49}{100}\)

cái này tính cái gì thế

ko hiểu

thiếu đề rồi

a. 5/12+(7/59+7/12)

=5/12+497/708

=66/59

b.(7/30+5/16)+(1/16-7/30)

=131/240+(-41/240)

=3/8

a)  \(\frac{5}{12}+\left(\frac{7}{59}+\frac{7}{12}\right)\)

\(=\frac{5}{12}+\frac{7}{59}+\frac{7}{12}\)

\(=\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{7}{59}\)

\(=1\frac{7}{59}\)

b)  \(\left(\frac{7}{30}+\frac{5}{16}\right)+\left(\frac{1}{16}-\frac{7}{30}\right)\)

\(=\frac{7}{30}+\frac{5}{16}+\frac{1}{16}-\frac{7}{30}\)

\(=\frac{6}{16}=\frac{3}{8}\)

c)  \(\frac{3}{5.9}+\frac{3}{9.13}+\frac{3}{13.17}+...+\frac{3}{2013.2017}\)

\(=\frac{3}{4}\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+...+\frac{1}{2013}-\frac{1}{2017}\right)\)

\(=\frac{3}{4}\left(\frac{1}{5}-\frac{1}{2017}\right)\)

\(=\frac{1509}{10085}\)