Tính nhanh hả bạn

tính nhanh dễ ẹc

=1.7 * ( 2.3 + 3.7 + 3 : 0.01 )

=1.7 * 0,1

=0.17

a, (-17)  + 21 + 79 + 17

= (-17 + 17) + (21 + 79)

= 0 + 100

= 100

b, 40 + 22 + (-16)  + (-44)

= 40 + {(-16) + (-44} + 22

= 40 - 60 + 22

= - 20 + 22

= 2 

c, (-12) + (-47) + (-28) + 47

=  - (12 + 28) + (-47 + 47)

= - 40 + 0
= - 40

d, (- 5) + (-3) + 35 + (-17)

= (-5 + 35) - (3 + 17)

=  30 - 20

=  10 

e, 21.23 - 3.7.(-17)

= 21.23 + 21.17

= 21.(23 + 17)

= 21. 40

= 840 

3.7x3.8+8.3x3.7-0.4x3.7x5=1523.142

cho mình nha

=3,7*(3,8+8,3-0,4*5) = 3,7*10,1=37,37

= 37.37

a, 2 x 4 x 8 x 0,5 x 0,125 x 0,25 x ( 0,4321 + 0,5679 )

= ( 2 x 0,5 ) x ( 4 x 0,25 ) x ( 0,125 x 8 ) x ( 0,4321 + 0,5679 )

= 1 x 1 x 1 x ( 0,4321 + 0,5679 )

= 1 x ( 0,4321 + 0,5679 ) 

= 1 x 1 = 1

b, 3,7 x 3,8 + 8,3 x 3,7 - 0,4 x 3,7 x 5

= 3,7 x ( 3,8 + 8,3 ) - ( 0,4 x 5 ) x 3,7

= 3,7 x 12,1 - 2 x 3,7

= 3,7 x ( 12,1 - 2 )

= 3,7 x 10,1 = 37,37

Ta có :

\(\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^6+3.7^{15}}\)

\(=\dfrac{5.7^6\left(3.7^9-19.7^8\right)}{7^6\left(1+3.7^9\right)}\)

\(=\dfrac{5.7^8\left(3.7-19\right)}{1+3.7^9}\)

\(=\dfrac{5.7^8.2}{1+3.7^9}\)

\(=\dfrac{10.7^8}{1+3.7^8.7}\)

\(=\dfrac{10.7^8}{1+7^8.21}\)

a) \(D=\left(2\dfrac{2}{15}\times\dfrac{9}{17}\times\dfrac{3}{32}\right)\div\left(-\dfrac{3}{17}\right)\)

\(D=\dfrac{32}{15}\times\dfrac{9}{17}\times\dfrac{3}{32}\times\dfrac{-17}{3}\)

\(D=\dfrac{-3}{5}\)

b) \(\dfrac{1}{2}-\dfrac{1}{3\times7}-\dfrac{1}{7\times11}-\dfrac{1}{11\times15}-\dfrac{1}{15\times19}-\dfrac{1}{19\times23}-\dfrac{1}{23\times27}\)

\(=\dfrac{1}{2}-\left(\dfrac{1}{3\times7}+\dfrac{1}{7\times11}+\dfrac{1}{11\times15}+\dfrac{1}{15\times19}+\dfrac{1}{19\times23}+\dfrac{1}{23\times25}\right)\)

\(=\dfrac{1}{2}-\left[\dfrac{1}{4}\left(\dfrac{4}{3\times7}+\dfrac{4}{7\times11}+\dfrac{4}{11\times15}+\dfrac{4}{15\times19}+\dfrac{4}{19\times23}+\dfrac{4}{23\times27}\right)\right]\)

\(=\dfrac{1}{2}-\left[\dfrac{1}{4}\left(\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{15}+\dfrac{1}{15}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{23}+\dfrac{1}{23}-\dfrac{1}{27}\right)\right]\)

\(=\dfrac{1}{2}-\left[\dfrac{1}{4}\left(\dfrac{1}{3}-\dfrac{1}{27}\right)\right]\)

\(=\dfrac{1}{2}-\left[\dfrac{1}{4}\left(\dfrac{9-1}{27}\right)\right]\)

\(=\dfrac{1}{2}-\dfrac{1}{4}\times\dfrac{8}{27}\)

\(=\dfrac{1}{2}-\dfrac{2}{27}\)

\(=.....\)

Đó đến đây bn tự lm nốt. Câu c bn lm tương tự.

Mình cho bn dạng này, nếu bn chưa biết (để lm câu c)

\(\dfrac{x}{y\left(y+x\right)}=\dfrac{x}{y}-\dfrac{x}{y+x}\)

Chúc bn học tốt