(-1).(-1)2.(-1)3.....(-1)2010.(-1)2011
NC
Những câu hỏi liên quan
ai đó giúp mk với mk xin chân thành cảm ơn! a=(2010+2010/2+2009/3+2008/4+...+1/2011/ 1/2+1/3+...+1/2011) / (1/2+1/3+1/4+1/5+...+1/2009+1/2010+1/2011)
Cho P = 1/2 + 1/3 +1/4 +...+1/2011 + 1/2012
Q = 1/2011 + 2/2010 + 3/2009 +...+ 2009/3 + 2010/2 + 2011/1
Cho A=1/2+1/3+1/4+...+1/2011+1/2012
B=2011/1+2010/2+2009/3+...+2/2010+1/2011
Tính A/B
Ta có \(B=\left(\frac{2010}{2}+1\right)+\left(\frac{2009}{3}+1\right)+...+\left(\frac{2}{2010}+1\right)+\left(\frac{1}{2011}+1\right)+1\)
\(B=\frac{2012}{2}+\frac{2012}{3}+...+\frac{2012}{2010}+\frac{2012}{2011}+\frac{2012}{2012}\)
\(B=2012.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}\right)\)
B=2012.A
=>A/B=1/2012
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Xem thêm câu trả lời
1. Cho A= 1/2 + 1/3 + 1/4 + ... + 1/2011 + 1/ 2012 và B= 2011/1 + 2010/2 + 2009/3 + ...+ 2/2010 + 1/2011
Tính: B/A { Giúp mik nhé ths }
a) 2010/1+2009/2+2008/3+ ... +1/2010+2010 : 1+1/2+1/3+ ... +1/2010=
b) 1/2011+1/2010+1/2009+ ... +1/3+1/2 : 2010/1+2009/2+2008/3+ ... +1/2010=
A=( 1 -1/2010) (1 - 2/2010) ( 1- 3/2010) ... ( 1- 2011/2010) = ?
tinh nhanh
(1-1/2010).(1-2/2010).(1-3/2010).......(1-2011/2010)
\(\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{2010}\right).\left(1-\frac{3}{2010}\right)...\left(1-\frac{2011}{2010}\right)\)
\(=\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{1010}\right).\left(1-\frac{3}{2010}\right)....\left(1-\frac{2010}{2010}\right).\left(1-\frac{2011}{2010}\right)\)
\(=\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{2010}\right).\left(1-\frac{3}{2010}\right)...\left(1-1\right).\left(1-\frac{2011}{2010}\right)\)
\(=\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{2010}\right).\left(1-\frac{3}{2010}\right)...0.\left(1-\frac{2011}{2010}\right)\)
\(=0\)
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Tính tích
A=(1-1/2010).(1-2/2010).(1-3/2010). ... .(1-2011/2010)
A= (1-1/2010) x (1- 2/2010) x (1- 3/2010) x.... x( 1- 2011/2010) =?
Vì ta có 1 - 1/2010 = 0/2010 = 0 nên suy ra biểu thức A = 0
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A=\(\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{2010}\right)...\left(1-\frac{2010}{2010}\right)\left(1-\frac{2011}{2010}\right)\)
A=\(\frac{2009}{2010}.\frac{2008}{2010}...0.\frac{-1}{2010}\)
A=0
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Tính tích ; A= (1-1/2010).(1-2/2010).(1-3/2010)...(1-2011/2010)
Ta có:\(1-\frac{2010}{2010}=1-1=0\)
Tích A= (1-1/2010).(1-2/2010).(1-3/2010)....(1-2011/2010) chứa thừa số \(1-\frac{2010}{2010}=0\)
Vậy tích A=(1-1/2010).(1-2/2010).(1-3/2010)....(1-2011/2010)=0(Vì có chứa thừa số 0)
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Ta có \(1-\frac{2010}{2010}=1-1=0\)
Mà \(A=\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{2010}\right).\left(1-\frac{3}{2010}\right)...\left(1-\frac{2010}{2010}\right).\left(1-\frac{2011}{2010}\right)\)
Nên \(A=...0\)\(=0\)
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