chung to rang 1 phan a =1 phan a+1 + 1 phan a nhan (a+1)
DK
Những câu hỏi liên quan
Tim phan so a/b>1,biet rang khi lay tu so cong voi 2 va mau so nhan voi 2 thi duoc phan so moi bang phan so a/b.
Ta có :
\(\frac{a+2}{2b}=\frac{a}{b}\)
\(\Rightarrow\left(a+2\right).b=a.2b\)
\(\Rightarrow a+2=2a\)
\(\Rightarrow2a-a=2\)
\(\Rightarrow a=2\)
Mà : \(\frac{a}{b}>1\)
\(\Rightarrow a>b\) ; \(b\) khác \(0\) và \(b\in\) N*
\(\Rightarrow\) \(b=1\)
Vậy \(\frac{a}{b}=\frac{2}{1}\)
Bai 1 Tim x
A) x nhan 4 phan 5 = 1 phan 2 nhan 1 phan 3
B ) x : 2 phan 5 = 2phan 3 + 1 phan 2
Tinh tong bang phuong phap khu lien tiep:
a/ Chung to rang 1/a - 1/a + m = m/a.(a+m)
b/ Tach cac phan so sau thanh hieu cua 2 phan so co tu bang 1:
4/5.9 ; 10/21.31 ; 7/19.26 ; 8/25.33 ; 9/15.24
chung to rang 12n+1 phan 30n+2 la phan so toi gian
Cho A bang 1 phan 11 cong 1 phan 12 cong 1 phan 13 cong......cong 1 phan 39 cong 1 phan 40
Chung minh A lon hon 3 phan 4
Ta có 1/11; 1/12; 1/13;...; 1/39 > 1/40
\(\Rightarrow\) A = 1/11 + 1/12 + 1/13 +...+ 1/39 +1/40 > 1/40 + 1/40 + 1/40 +...+ 1/40 + 1/40(có 30 số hạng)
A > 30/40
Mà 30/40 =3/4 nên A >3/4
Vậy A > 3/4
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Cho A=1/2^2+1/3^2+1/4^2+.......+1/20^2 .Chung to rang A<1
Cho A=1/2^2+1/3^2+1/4^2+........+1/20^2 .Chung minh A<1
Chu thich / La phan so
^ la mu
\(Ta\)có :
\(\frac{1}{2^2}< \frac{1}{1.2};\frac{1}{3^2}< \frac{1}{2.3};...;\frac{1}{20^2}< \frac{1}{19.20}\)
\(\Rightarrow\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{20^2}< \frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{19.20}\)
\(\Rightarrow A< 1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{19}-\frac{1}{20}\)
\(\Rightarrow A< 1-\frac{1}{20}< 1\left(Đpcm\right)\)
Chúc bạn học tốt !!!
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chung to rang phan so 2n+1/3n+2 la phan so toi gian
Gọi \(d\in\left(2n+1;3n+2\right)\)
\(\Rightarrow\hept{\begin{cases}2n+1⋮d\\3n+2⋮d\end{cases}\Rightarrow\hept{\begin{cases}6n+3⋮d\\6n+4⋮d\end{cases}\Rightarrow1⋮}d\Rightarrow d=1}\)
\(\Rightarrowđpcm\)
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cho a=1 phan 5 + 1phan 6 +1 phan 7 +1 phan 8 + 1 phan 9 .so sanh avoi 1
cac ban nho yich ro rang cho minh nha
Chung to rang voi gia tri tim duoc cua n o cau a thi p bang phan so p= n+4^2n-1 (n khong bang -2)hoac bang phan so n mu 3^ n+2 ( n khong bang -2)