tim x biet 2678:[462-2(x-6)]=13
câu b
2678 : [ 462 - 2 x ( x - 6 )]=13
2678:[462-2.(x-6)]=13
<=>462-2.(x-6)=2678:13
<=>462-2.(x-6)=206
<=>2.(x-6)=462-206
<=>2.(x-6)=256
<=>x-6=128
<=>x=134
k mik
Ta có: 462-2.(x-6)=206
2.(x-6)=256
x-6=128
x=134
Vậy x=134
(2x-25):85
2678:(462-2.(x-6))=13
(2x-33).95=(-9)7
72:(4x-3)=23
2(x+1)=32
giup mk minh tick cho
tim y biet [2/11*13+2/13*15+2/15*17+2/17*19+2/19*21]*462-y=19
Tim x biet a,2:(x-1)=9 b,156-(x+61)=82 c,13+(x-1)=6
a) 2 : (x - 1) = 9
x - 1 = 2 : 9
x - 1 = \(\frac{2}{9}\)
x = \(\frac{2}{9}+1\)
x = \(\frac{11}{9}\)
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 13 + (x - 1) = 6
x - 1 = 6 - 13
x - 1 = -7
x = -7 + 1
x = -6
giup voi
tim x biet
2/3x^2-5x+2 + 13/3x^2+x+2 = 6/x
tim so tu nhien x ,biet :a/2x-13=23.32 b/231-(x-6)=1339:13
a) \(2x-13=2^3.3^2\)
=> \(2x-13=8.9=27\)
=> \(2x=27-13=14\)
=> \(x=7\)
b) \(231-\left(x-6\right)=1339:13=103\)
=> \(x-6=231-103=128\)
=> \(x=6+218=224\)
tim so nguyen x biet rang 13/3.(1/6-1/2)<x<2/3.(1/3-1/2/-3/4)
tim x biet \(|6-2x|+|x-13|=0\)
Vì GTTĐ luôn lớn hơn hoặc bằng 0, mà theo đề bài
=> 6 - 2x = 0 và x - 13 = 0
2x = 6 x = 13
x = 3
Vậy,................
|6-2x|+|x-13|=0
=>6-2x=0 hoặc x-13=0
6-2x=0 ; x-13=0
=>2x=6-0=6 =>x=13
=>x=6:2=3
vậy x thuộc {3;13}
tim so tu nhien x biet
a) 2.x -138=23.32
b)231-(x-6)=1339:13
a) \(2x-138=2^3.3^2\)
\(\Rightarrow2x-138=72\)
\(\Rightarrow2x=210\)
\(\Rightarrow x=105\)
b) \(231-\left(x-6\right)=1339:13\)
\(\Rightarrow231-\left(x-6\right)=103\)
\(\Rightarrow x-6=110\)
\(\Rightarrow x=116\)
a) \(2.x-138=2^3.3^2\)
\(2.x-138=8.9\)
\(2.x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=210:2\)
\(x=105\)
\(231-\left(x-6\right)=1339:13\)
\(231-\left(x-6\right)=103\)
\(x-6=231-103\)
\(x-6=128\)
\(x=128+6\)
\(x=134\)
\(2x-138=2^3.3^2\)
\(2x-138=8.9\)
\(2x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=210:2\)
\(x=105\)
b)\(231-\left(x-6\right)=1339:13\)
\(231-\left(x-6\right)=103\)
\(\left(x-6\right)=231-103\)
\(\left(x-6\right)=128\)
\(x=128+6\)
\(x=134\)
T mk nhé bạn ^...^ ^_^