\(B=\left(1,6\cdot0,4\right)^2-\dfrac{57}{4}+\dfrac{7}{5}-\dfrac{7}{4}=\dfrac{256}{625}-16+\dfrac{7}{5}=-\dfrac{8869}{625}\)

d)\(\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{97.99}\) 

\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{97}-\frac{1}{99}\)

\(=\frac{1}{3}-\frac{1}{99}\)

\(=\frac{32}{99}\)

a)   11/4x(-0,4)x-1,6x11/4

     = -1,1 x-1,6x11/4

    = 1,76x11/4

    = 4,48

b)    6/19x-7/11+6/19x-4/19x-4/11+13/19

     = -42/209+96/3971+13/19

     = -702/3971+13/19

     = 2015/3971

c)     2/5x3/7+-3/7x3/5+3/7

      = 3/7x(2/5+3/5+1)

      = 3/7x(1+1)

      = 3/7x2

      = 6/7

d)      2/3x5+2x5/7+2/7x9+....+2/97x99

      = 1/3-1/5+1/5-1/7+1/7-1/9+......+1/97-1/99

      = 1/3-1/99

      = 32/99

d)=1/3-1/5+1/5-1/7+....+1/97-1/99

=1/3-1/99

=32/99

1.

a)Tỉ số phần trăm của 25 và 49 là: 25 : 49 = 0,5102.... x 100 = 51,02...%

Tỉ số phần trăm của 1,6 và 30 là: 1,6 : 30 = 0,5333.... x 100 = 53,333..%

Tỉ số phần trăm của 0,4 và 3,2 là: 0,4 : 3,2 = 0,125 x 100 = 12,5%

1)     \(-1,6:\left(1+\frac{8}{12}\right)\)

  \(=-1,6:\left(1+\frac{2}{3}\right)\)

     \(=-1,6:1-1,6:\frac{2}{3}\)

       \(=-1,6+\frac{-1,6.3}{2}\)

          \(=-1,6-2,4\)

         \(=4\)

2)    \(\frac{3}{8}-\frac{4}{5}-\frac{-17}{40}\)

      \(=\frac{15-32+17}{40}\)

          =0

3)   \(\frac{3}{4}-\frac{16}{32}+\frac{4}{-3}\)

\(=\frac{3}{4}-\frac{2}{4}+\frac{-4}{3}\)

\(=\frac{9-6-16}{12}\)

\(=\frac{-13}{12}\)

4)  \(\frac{-4}{7}+\frac{2}{3}.\frac{-9}{14}\)  

\(=\frac{-4}{7}+\frac{-3}{7}=-1\)

5)   \(2\frac{3}{4}-\left(\frac{1}{7}+1\frac{3}{4}\right)\)

\(=\frac{11}{4}-\left(\frac{1}{7}+\frac{7}{4}\right)\)

\(=\frac{11}{4}-\frac{4+49}{28}\)

\(=\frac{11}{4}-\frac{53}{28}\)

\(=\frac{77-53}{28}=\frac{24}{28}=\frac{6}{7}\)

6)   \(8\frac{2}{7}-\left(3\frac{4}{9}+4\frac{2}{7}\right)\)

\(=\frac{58}{7}-\left(\frac{31}{9}+\frac{30}{7}\right)=\frac{522-217+270}{63}\)

\(=\frac{575}{63}\)

a) 3+15+35+63           = 116

18+90+210+378            378

=58/189

a) \(\frac{1.3+3.5+5.7+7.9}{3.6+9.10+15.14+21.18}\)

= \(\frac{1.3+3.5+5.7+7.9}{1.3.2.3+3.5.2.3+5.7.2.3+7.9.2.3}\)

= \(\frac{1.3+3.5+5.7+7.9}{1.3.6+3.5.6+5.7.6+7.9.6}\)

= \(\frac{1.3+3.5+5.7+7.9}{6.\left(1.3+3.5+5.7+7.9\right)}=\frac{1}{6}\)

Dấu "." là dấu nhân cấp 2 

b)  \(\frac{1.2+2.3+3.4+4.5}{3.6+6.9+9.12+12.15}\)

= \(\frac{1.2+2.3+3.4+4.5}{1.2.3.3+2.3.3.3+3.4.3.3+4.5.3.3}\)

= \(\frac{1.2+2.3+3.4+4.5}{1.2.9+2.3.9+3.4.9+4.5.9}\)

= \(\frac{1.2+2.3+3.4+4.5}{9.\left(1.2+2.3+3.4+4.5\right)}=\frac{1}{9}\)

Dấu "." là dấu nhân cấp 2 

c) \(\frac{0,3+\frac{3}{7}+\frac{3}{11}}{0,4+\frac{4}{7}+\frac{4}{11}}\)= \(\frac{\frac{3}{10}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{10}+\frac{4}{7}+\frac{4}{11}}\)= \(\frac{3.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)

a) \(\frac{1.3+3.5+5.7+7.9}{3.6+9.10+15.14+21.18}=\frac{1.3+3.5+5.7+7.9}{1.3.2.3+3.3.5.3+3.5+2.7+3.7+3.9}=\frac{1.3+3.5+5.7+7.9}{2.3\left(1.3+3.5+5.7+7.9\right)}=\frac{1}{6}\)

b)\(\frac{1.2+2.3+3.4+4.5}{3.6+6.9+9.12+12.15}\)

Con này làm tương tự như con a

c) \(\frac{\frac{3}{10}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{10}+\frac{4}{7}+\frac{4}{11}}=\frac{3.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)

Chúc học tốt

a. \(\dfrac{-2}{3}+\dfrac{-1}{5}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)

= \(\dfrac{-4}{6}+\dfrac{-2}{10}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)

= \(\dfrac{-3}{2}+\dfrac{1}{2}+\dfrac{3}{4}\)

= (-1) + \(\dfrac{3}{4}\)

= \(\dfrac{-4}{4}+\dfrac{3}{4}\)

= \(\dfrac{-1}{4}\)

b; 0,5  + \(\dfrac{1}{3}\) + 0,4 + \(\dfrac{5}{7}\) + \(\dfrac{1}{6}\) - \(\dfrac{4}{35}\)

= (\(\dfrac{1}{3}\)+ \(\dfrac{1}{6}\) + \(\dfrac{1}{2}\)) + (\(\dfrac{5}{7}\)- \(\dfrac{4}{35}\)+ \(\dfrac{2}{5}\))

= ( \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\)) + (\(\dfrac{3}{5}\) + \(\dfrac{2}{5}\))

= 1 + 1 

= 2

c; \(\dfrac{1}{3}\) + \(\dfrac{-1}{5}\) - \(\dfrac{-1}{4}\) - \(\dfrac{7}{9}\)- \(\dfrac{-5}{12}\) + \(\dfrac{-1}{45}\) + \(\dfrac{1}{41}\)

  = (\(\dfrac{1}{3}\) + \(\dfrac{1}{4}\) + \(\dfrac{5}{12}\)) - (\(\dfrac{1}{5}\) + \(\dfrac{7}{9}\) + \(\dfrac{1}{45}\)) + \(\dfrac{1}{41}\)

= (\(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{5}{12}\)) - (\(\dfrac{9}{45}+\dfrac{35}{45}\) + \(\dfrac{1}{45}\)) + \(\dfrac{1}{41}\)

= (\(\dfrac{7}{12}\) + \(\dfrac{5}{12}\)) - (\(\dfrac{44}{45}\) + \(\dfrac{1}{45}\)) + \(\dfrac{1}{41}\)

= 1 - 1 + \(\dfrac{1}{41}\)

= 0 + \(\dfrac{1}{41}\)

= \(\dfrac{1}{41}\)

a) 25 và 40 

    25 : 40 = 0,625 = 62,5

    1,6 và 80 

     1,6 : 80 = 0.02 = 2

     0,4 và 3,2

     0,4 : 3,2 = 0,125  = 12.5

b) Bạn ghi k rõ đề mình không hiểu

Chúc bạn học tốt ^_^

a. 25:40x100=62,5%

   1,6:80x100=2%

   0,4:3,2x100=12,5%

b. 2:3/4x100=266,66%

    3:4/7x100=525%

    18:4/5x100=2250%

    0,3:0,96x100=31,25%

Chúc bn hok tốt nha♥