(3x + 6)² = 0

=> 3x + 6 = 0

=> 3x = -6

=> x = -6 : 3

=> x = -2

Từ : (3x+6)² = 0

=> 3x+6 = 0

=> 3x= -6

=> x = -2

kich minh nha

0,1(6):x=0,(33)

=>[0,1+0,0(6)]:x=33/99=1/3

=>(1/10+1/15):1/3=x

=>1/6.3=x

=>x=3/6=1/2=0,5

nhớ tick nhé

Ta có: \(0,1\left(6\right)=0,1+0,0\left(6\right)=0,1+\frac{1}{10}.0,\left(6\right)=0,1+\frac{1}{10}.6.0,\left(1\right)=0,1+\frac{1}{10}.6.\frac{1}{9}=\frac{1}{6}\)\(0,\left(33\right)=33.0,\left(01\right)=33.\frac{1}{99}=\frac{1}{3}\)

\(\Rightarrow\frac{1}{6}:x=\frac{1}{3}\Rightarrow x=\frac{1}{6}:\frac{1}{3}=\frac{1}{2}\)

\(1,\Leftrightarrow x^2-10x+25=0\Leftrightarrow\left(x-5\right)^2=0\Leftrightarrow x=5\left(B\right)\\ 2,Giống.1\\ 3,=5x^2\left(B\right)\\ 4,x^3=x\Leftrightarrow x^3-x=0\\ \Leftrightarrow x\left(x^2-1\right)=0\\ \Leftrightarrow x\left(x-1\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\\ \Leftrightarrow A\)

18,7:x=3,11(6) mà 3,11(6)=\(\frac{187}{60}\)

nên 18,7:x=\(\frac{187}{60}\)Suy ra x=\(\frac{187}{10}\):\(\frac{187}{60}\)=6

\(\frac{18,7}{x}=3,11\left(6\right)\)

\(\Rightarrow\frac{18,7}{x}=\frac{187}{60}\)

\(\Rightarrow x=\frac{18,7\cdot60}{187}=\frac{187\cdot6}{187}=6\)

\(3^{2x-1}=3^6:3^3\)

\(3^{2x-1}=3^{6-3}\)

\(3^{2x-1}=3^3\)

\(\Rightarrow2x-1=3\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

vậy \(x=2\)

=> 3^2x-1 = 3^3 = 3^3

=> 2x-1 = 3

=> 2x = 3+1 = 4

=> x = 4:2 = 2

k mk nha

3^{2x - 1} = 3⁶ : 3³

3^{2x - 1} = 3³

=> 2x - 1 = 3

    2x = 3 + 1

    2x = 4 

      x = 4 : 2

      x = 2

Vậy x = 2

Đáp án: D

65− 4 x + 2 = 2020 0

65− 4 x + 2 =1

4 x + 2 =65-1

4 x + 2 =64

4 x + 2 =43

x + 2 =3

x =3 - 2

x =1