= 1x2 + 3x2x2 + 5x3x2 + 7x4x2 + 9x5x2 + 11x6x2 + 13x7x2 + 15x8x2

=1x2 + 6x2 + 15 x2 + 28x2 + 45x2 + 66x2 + 91x2 + 120x2

=2 x ( 1+6+15+28+45+66+91+120)

= 2 x 370

=740

=

1x2+3x4+5x6+7x8+9x10+11x12+13x14+15x16

=1x2+3x2x2+5x3x2+7x4x2+9x5x2+11x6x2+13x7x2+15x8x2

=1x2+6x2+15x2+28x2+45x2+66x2+91x2+120x2

= 2x(1+6+15+28+45+66+91+120)

=2x370

=740

1x2 + 3X4 + 5x6 + 7x8 + 9x10 + 11x12 + 13x14 +15x16

=1x2 + 3x2x2 + 5x3x2 + 7x4x2 + 9x5x2 + 11x6x2 + 13x7x2 + 15x8x2

=1x2 + 6x2 + 15x2 + 28x2 + 45x2 + 66x2 + 91x2 + 120x2

=2 x ( 1+6+15+28+45+66+91+120)

= 2x 370

=740

\(\frac{5}{10.11}+\frac{5}{11.12}+\frac{5}{12.13}+....+\frac{5}{49.50}\)

\(=5.\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+.....+\frac{1}{49.50}\right)\)

\(=5.\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+....+\frac{1}{49}-\frac{1}{50}\right)\)

\(=5.\left(\frac{1}{10}-\frac{1}{50}\right)\)

\(=5.\frac{2}{25}\)

\(=\frac{2}{5}\)

5/10 x 11 + 5/11 x 12 + 5/12 x 13 + .... + 5/49 x 50

= 5/10 - 5/11 + 5/11 - 5/12 + 5/12 - 5/13 + ....... + 5/49 - 5/50

= 5/10 - 5/50

= 2/5

=2/5 nha bn

\(\frac{5}{11x12}+\frac{5}{12x13}+...+\frac{5}{98x99}\)

=\(\frac{5}{11}-\frac{5}{12}+\frac{5}{12}-\frac{5}{13}+...+\frac{5}{98}-\frac{5}{99}\)

=\(\frac{5}{11}-\frac{5}{99}\)

=\(\frac{40}{99}\)

Cái cuối bỏ 1 số 0 thì đúng hơn nha bạn

\(\frac{5}{11.12}+\frac{5}{12.13}+\frac{5}{13.14}+...+\frac{5}{98.99}\)

\(=5\left(\frac{1}{11.12}+\frac{1}{12.13}+\frac{1}{13.14}+...+\frac{1}{98.99}\right)\)

\(=5\left(\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{98}-\frac{1}{99}\right)\)

\(=5\left(\frac{1}{11}-\frac{1}{99}\right)\)

\(=5.\frac{8}{99}\)

\(=\frac{40}{99}\)

\(=5\left(\frac{1}{11.12}+\frac{1}{12.13}+\frac{1}{13.14}+...+\frac{1}{98.99}\right)\)

\(=5\left(\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{98}-\frac{1}{99}\right)\)

\(=5\left(\frac{1}{11}-\frac{1}{99}\right)=5.\frac{8}{99}=\frac{40}{99}\)

3747744

bằng 470 

ko có đâu mình ko rễ bị lừa :))

trả lời:

=470

hok tốt nhé

tk mk nhé

\(\frac{1}{11x12}+\frac{1}{12x13}+...+\frac{1}{98x99}\)= \(\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+.....+\frac{1}{98}-\frac{1}{99}\)

                                                                       = \(\frac{1}{11}-\frac{1}{99}\)

                                                                        =   \(\frac{8}{99}\)

Học tốt !

\(\frac{1}{11\times12}+\frac{1}{12\times13}+\frac{1}{13\times14}+...+\frac{1}{97\times98}+\frac{1}{98\times99}\)

\(=\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{97}-\frac{1}{98}+\frac{1}{98}-\frac{1}{99}\)

\(=\frac{1}{11}-\frac{1}{99}\)

\(=\frac{8}{99}\)

\(=\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+.....+\frac{1}{98}-\frac{1}{99}\)

\(=\frac{1}{11}-\frac{1}{99}\)

\(=\frac{9}{99}-\frac{1}{99}\)

\(=\frac{8}{99}\)

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