[ X 1 cong ] cong [ X 2 cong ] cong[ X3 cong] CONG .............. CONG 20 = 750
A] X-1,25x4= 2,5 b] [ X CONG 1 ] CONG [ X CONG 2] CONG [ X CONG 3 CONG ] .............. CONG [ X CONG 20] = 750 C ] [ X CONG 1] CONG [X CONG 2 ] CONG [ X CONG 3 ] CONG ........... CONG [ X CONG 10] = 175
a) Ta có: X-1,25x4= 2,5
=)X-1,25= 2,5:4= 0,625
=)X= 0,625+1,25= 1,875
Vậy X= 1,875
b) Ta có: (X+1)+(X+2)+(X+3)+...+(X+20) = 750
=)X+1+X+2+X+3+...+X+20(20 chữ số X) = 750
=)20X+(1+2+3+...+20) = 750
=)20X+[(1+20)+(2+19)+...+(10+11)] = 750 (10 cặp số hạng)
=)20X+(21+21+21+...+21) = 750
=)20X+21x10 = 750
=)20X+210 = 750
=)20X = 750-210 = 540
=)X = 540:20 = 27
Vậy X = 27
Câu C bạn nhìn phần B rồi tự nghĩ nha. Luời quá rồi
[ 2 CONG X ] CONG [ 4 CONG X ] CONG [ 6 CONG X ] CONG .......................... CONG [ 52 CONG X ] = 780
( 2 + x ) + ( 4 + x ) + ( 6 + x ) + ... + ( 52 + x ) = 780
2 + x + 4 + x + 6 + x + ... + 52 + x =780 ( đây là bước phá ngoặc )
( 2 + 4 + 6 + ... + 52 ) + ( x + x + x + ... + x ) ( có 26 số x) = 780
702 + 26.x = 780
26.x = 780 - 702 ( dấu chấm là dấu nhân nhé
26.x = 78
x = 78 : 26
x = 3
Vậy x = 3
( cho mình 1 t i c k nhé :))
1 CONG 3 CONG 5 CONG .........CONG [ 2 x X CONG 1] = 169
ai tra loi giup mk voi
x cong 1 cong x cong 2 cong ...x cong 100 bang 5050
x+1+x+2+x+3+...+x+100=5050
x+(1+2+3+...+100) =5050
x+5050 =5050
x =5050-5050
x =0
Vậy x= 0
x + 1 + x + 2 + x + 3 + x + .....+ 100
= x + 5050 = 5050
=> x = 5050 - 5050
x = 0
tim z,y,z thoa
can x cong can tat ca y tru 1 cong can tat ca z tru 2 bang 1 phan 2 ( x cong y cong z)
tim GTN cua B bang 1 phan x tru can x cong 1
tim x thuoc z de can x cong 1 phan can 3 tru 3 la so nguyen
tinh tong T bang 1 phan can 1 cong can 2 cong 1 phan can 2 cong can 3 cong ... cong den 1 phan can 99 cong can 100
C] [ X-1/2 ] CHIA [ 1/2 CONG 1/6 CONG 1/12 CONG 1/20 ] = 1/3
c) \(\frac{x-\frac{1}{2}}{\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}}=\frac{1}{3}\)
Đặt \(S=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\)
\(S=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}\)
\(S=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{4}-\frac{1}{5}\)
\(S=1-\frac{1}{5}=\frac{4}{5}\)
Do đó \(\frac{x-\frac{1}{2}}{S}=\frac{1}{3}\)
=> \(x-\frac{1}{2}=\frac{1}{3}S=\frac{1}{3}\cdot\frac{4}{5}=\frac{4}{15}\)
=> \(x=\frac{4}{15}+\frac{1}{2}=\frac{23}{30}\)
1 CONG 3 CONG 5 CONG CONG .......... CONG [ 2x X CONG 1] =169
ko đưa câu hỏi linh tinh lên diễn đàn
MK DAU CO DUA CAU HOI LINH TINH
what???????????????
1 CONG 2 CONG 3 CONG ........... CONG X = 210
1 + 2 + 3 + ... + x = 210
=> x.(x + 1) : 2 = 210
=> x.(x + 1) = 420
=> x.(x + 1) = 20.21
=> x = 20
1 CONG 3 CONG 5 CONG ............... CONG [ 2x X 1] CONG 169
gì thế
CAU HOI CHU GI NUA
MK DUNG MAY TINH KHONG CO DAU NEN PHAI LAM THE