\(3x^3-14x^2+4x+3\)

\(=\left(3x^3-15x^2+9x\right)+\left(x^2-5x+3\right)\)

\(=3x\left(x^2-5x+3\right)+\left(x^2-5x+3\right)\)

\(=\left(3x+1\right)\left(x^2-5x+3\right)\)

3x^3 - 14x^2 + 4x + 3
= (3x^3+x^2) - 15^2- 5x+ 9x+ 3
= x^2(3x+1)- 5x(3x+1)+ 3(3x+1)
= (x^2- 5x+ 3)(3x+1)

\(x^4-6x^3+12x^2-14x+3\) 

= \(x^4-4x^3+x^2-2x^3+8x^2-2x+3x^2-12x+3\) 

= \(x^2\left(x^2-4x+1\right)-2x\left(x^2-4x+1\right)+3\left(x^2-4x+1\right)\) 

= \(\left(x^2-4x+1\right)\left(x^2-2x+3\right)\)

\(=x^4-4x^3+x^2-2x^3+8x^2-2x+3x^2-12x+3\)

\(=x^2\left(x^2-4x-1\right)-2x\left(x^2-4x-1\right)+3\left(x^2-4x+1\right)\)

\(=\left(x^2-2x+3\right)\left(x^2-4x-1\right)\)

=\(\left(x^2-2x+3\right)\left(x^2-4x+1\right)\)

x⁴-6x³+12x²-14x+3 = (x² - 4x + 1) (x² - 2x + 3) 

x⁴-6x³+12x²-14x+3=x⁴-2x³+3x²-4x³+8x²-12x+x²-2x+3

=x²(x²-2x+3)-4x(x²-2x+3)+(x²-2x+3)

=(x²-2x+3)(x²-4x+1)

a) ( x 2  – 4x + 1)( x 2  – 2x + 3).

b) ( x 2  + 5x – 1)( x 2  + x – 1).

a)\(x^5-x=x\left(x^4-1\right)=x\left(x^2-1\right)\left(x^2+1\right)=x\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\)

b)\(3x^2+5x-2=3x^2+6x-x-2=3x\left(x+2\right)-\left(x+2\right)=\left(3x-1\right)\left(x+2\right)\)

c)\(4x^3+14x^2+6x=2x\left(2x^2+7x+3\right)=2x\left(2x^2+6x+x+3\right)\)

\(=2x\left[2x\left(x+3\right)+\left(x+3\right)\right]=2x\left(x+3\right)\left(2x+1\right)\)

\(x^5-x=x\left(x^4-1\right)\)

\(=x\left(x^2-1\right)\left(x^2+1\right)\)

\(=x\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\)

12x² hay 12x

3x² + 10x +3

=> 3x² + 9x +x +3

=> (3x² +x )+ ( 9x +3)

=> x(3x +1) +3( 3x+1)

=>(3x+1) (x+3)

Tự làm tiếp nhé

a, ta có: 3x^2 +10x+3= 3x^2 + 9x +x +3 = 3x(x+3)+(x+3)=(x+3)+(3x+1)

2 câu còn lại đang trong qtrinhf suy nghĩ

a) \(3x^2+10x+3=3x^2+9x+x+3\)

\(=3x\left(x+3\right)+\left(x+3\right)\)

\(=\left(x+3\right)\left(3x+1\right)\)

b)\(5x^2+14x-3=5x^2+15x-x-3\)

\(=5x\left(x+3\right)-\left(x+3\right)\)

\(=\left(5x-1\right)\left(x+3\right)\)

c)\(6x^2+7x-3=6x^2+9x-2x-3\)

\(=3x\left(2x+3\right)-\left(2x+3\right)\)

\(=\left(3x-1\right)\left(2x+3\right)\)