rut gon bieu thuc sau -4+{x-15}+3
TA
Những câu hỏi liên quan
rut gon bieu thuc 3^6*45^4-3^10*15^3/27^4*25^3+45^6
rut gon bieu thuc (5√3+3√5)÷15
rut gon bieu thuc sau:
(x+5)^3-15x(x+10)
Cho bieu thuc:
P=\(\frac{1}{\sqrt{x}+2}-\frac{5}{x-\sqrt{x}-6}-\frac{\sqrt{x}-2}{3-\sqrt{x}}\)
a. Rut gon bieu thuc P
b.Tim GTLN cua P sau khi rut gon
đk: x>=0; x khác 3
a) \(P=\frac{\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}-\frac{5}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}+\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\sqrt{x}-3}=\frac{\sqrt{x}-3-5+x-4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}=\frac{x+\sqrt{x}-12}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}\)
\(P=\frac{\left(\sqrt{x}+4\right)\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}=\frac{\sqrt{x}+4}{\sqrt{x}+2}\)
b) \(P=\frac{\sqrt{x}+2+2}{\sqrt{x}+2}=1+\frac{2}{\sqrt{x}+2}\)
ta có: \(x\ge0\Rightarrow\sqrt{x}\ge0\Leftrightarrow\sqrt{x}+2\ge2\Leftrightarrow\frac{2}{\sqrt{x}+2}\le1\Leftrightarrow1+\frac{2}{\sqrt{x}+2}\le2\Rightarrow MaxP=2\Rightarrow x=0\)
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Rut gon cacc bieu thuc sau : ( 4x - 3 ).( x - 5 ) - 2x ( 2x- 11)
\(\left(4x-3\right).\left(x-5\right)-2x\left(2x-11\right)\)
=\(4x^2-20x-3x+15-\left(4x^2-22x\right)\)
\(=4x^2-20x-3x+15-4x^2+22x\)
\(=-x+15\)
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rut gon bieu thuc sau : 4^2.25^2+32.125/2^3.5^2
cho bieu thuc A = /x-1/ + 3x-7
a. rut gon bieu thuc
b. tinh A khi x=3;x=-5
Rut gon bieu thuc sau
(15√200 - 3√450 + 2√50) : √10
Minh can sieu nhanh ma phai dung, Thanks truoc nha!!
=15√20 -3√45+2√5
=15\(\sqrt{4x5}\)-3\(\sqrt{9x5}\)+2√5
=30√5 -9√5+2√5
=23√5
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\(\left(15\sqrt{200}-3\sqrt{450}+2\sqrt{50}\right):\sqrt{10}\) =\(\left(150\sqrt{2}-45\sqrt{2}+10\sqrt{2}\right):\sqrt{10}\)
=\(115\sqrt{2}:\sqrt{10}\)
chắc vậy
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Rut gon bieu thuc sau
3(2*2+1)(2*4+1)(2*8+1)(2*16+1)