Câu hỏi của linh phạm - Toán lớp 6 - Học toán với OnlineMath

Alớn hơn nhé

a lớn hơn

a lớn hơn nha bạn k nha 

a) \(\frac{2005.2007-1}{2004+2005.2006}=\frac{\left(2014+1\right).2007-1}{2004+2005.2006}=\frac{2004+2005.2007-1}{2004+2005-2006}=\frac{2004+2005.2006}{2004+2005.2006}=1\)

Ta có:
N=\(\dfrac{2003+2004}{2004+2005}\)=\(\dfrac{2003}{2004+2005}\)+\(\dfrac{2004}{2004+2005}\)
Ta thấy:
\(\dfrac{2003}{2004+2005}\)<\(\dfrac{2003}{2004}\)(1)

\(\dfrac{2004}{2004+2005}\)<\(\dfrac{2004}{2005}\)(2)
Từ (1) và (2) --> M=\(\dfrac{2003}{2004}\)+\(\dfrac{2004}{2005}\)>\(\dfrac{2003}{2004+2005}\)+\(\dfrac{2004}{2004+2005}\)=N
Vậy  M>N

=

Đề đúng :  So sánh :   \(\frac{2003}{2004}+\frac{2004}{2005}+\frac{2005}{2006}\)với 3 

Ta có : 

\(\frac{2003}{2004}< \frac{2004}{2004}=1\)

\(\frac{2004}{2005}< \frac{2005}{2005}=1\)

\(\frac{2005}{2006}< \frac{2006}{2006}=1\)

\(\Rightarrow\frac{2003}{2004}+\frac{2004}{2005}+\frac{2005}{2006}< 1+1+1\)

\(\Rightarrow\frac{2003}{2004}+\frac{2004}{2005}+\frac{2005}{2003}< 3\)

Chúc bạn học tốt !!! 

minh lan dau tien vao trang web nay nen khong biet nhieu

2003/2004 + 2004/2005 + 2005/2003

= 1 - 1/2004 + 1 - 1/2005 + 1 + 1/2003 + 1/2003

=(1+1+1)-(1/2004 - 1/2003 + 1/2005 - 1/2003)

= 3 - (1/2004 - 1/2003 + 1/2005 - 1/2003)

Vì 1/2004 < 1/2003 ; 1/2005 < 1/2003

=>1/2004 - 1/2003 + 1/2005 - 1/2003 < 0

=> 3 - (...) > 3

Vậy. ...

K mình nha 

\(B=\frac{2003+2004}{2004+2005}=\frac{2003}{2004+2005}+\frac{2004}{2004+2005}\)

Ta có: \(\frac{2003}{2004}>\frac{2003}{2004+2005}\)

          \(\frac{2004}{2005}>\frac{2004}{2004+2005}\)

\(\frac{2003}{2004}+\frac{2004}{2005}>\frac{2003+2004}{2004+2005}\)

\(A>B\)

Vậy A>B

đáp án là A>B

chúc bn hok tốt!

                                 \(\text{ Bài giải}\)

\(A=\frac{2003}{2004}+\frac{2004}{2005}=0,999500998 + 0,999501247=1.99900225\)

\(B=\frac{2003+2004}{2004+2005}=\frac{4007}{4009}=0,999501122\)

\(\text{Vì : }1,99900224>0,999501122\text{ nên }A>B\)

        \(\text{Vậy : }A>B\)