7,5*x+(-1,5)*x+11=-13,6
\(\dfrac{7,5+1,5+\dfrac{5}{4}+\dfrac{5}{11}}{10,5+2,1+\dfrac{7}{4}+\dfrac{7}{11}}\)+ x =\(\dfrac{6}{7}\)
\(\dfrac{7,5+1,5+\dfrac{5}{4}+\dfrac{5}{11}}{10,5+2,1+\dfrac{7}{4}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{9+\dfrac{5}{4}+\dfrac{5}{11}}{\dfrac{63}{5}+\dfrac{7}{4}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{36}{4}+\dfrac{5}{4}+\dfrac{5}{11}}{\dfrac{252}{20}+\dfrac{35}{20}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{41}{4}+\dfrac{5}{11}}{\dfrac{287}{20}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{451}{44}+\dfrac{20}{44}}{\dfrac{3157}{220}+\dfrac{140}{220}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{471}{44}}{\dfrac{3297}{220}}+x=\dfrac{6}{7}\)
\(\dfrac{5}{7}+x=\dfrac{6}{7}\)
\(x=\dfrac{6}{7}-\dfrac{5}{7}\)
\(x=\dfrac{1}{7}\)
Tìm x
(x + 12,8) + (x + 13,6) + (x + 14,4) + ( x - 11,3) + (x - 12,1) + ( x - 12,9) =1,5 x 3
X x 1,5 + X x 7,5 + x =11,6
X x (1,5 + 7,5) = 11,6
X x 9 = 11,6
X = 1,28
X x(1,5+7,5+1)=11,6
Xx10=11,6
X=11,6:10
X=1,16
X x (1,5 + 7,5) = 11,6
X x 9 = 11,6
X = 1,28
37,5 . 8,5 - 7,5 x 3,4 - 6,6 . 7,5 + 1,5 .37.5
\(37,5.8,5-7,5.3,4-6,6.7,5+1,5.37,5\)
\(=(37,5.8,5+1,5.37,5)-(7,5.3,4+6,6.7,5)\)
\(=37,5.\left(8,5+1,5\right)-7,5\left(3,4+6,6\right)\)
\(=37,5.10-7,5.10=10.\left(37,5-7,5\right)=10.30=300\)
= (37,5.8,5 + 15 . 37,5 )-(7,5 . 3.4 + 6,6 .7,5)
= 37,5(8,5 + 15) - 7,5 (3,4 +6,6 )
=881,25 - 75 = 806,25
X x 1,5 + X + X x 7,5 = 59,8
X x 1,5 +X +X x7,5=59,8
X x (1,5+1+7,5)=59,5
X x 10=59,5
X=59,5 : 10 =5,95
Tìm X
a) X x 1,5 - 5,61 = 6,45 b) 89 : X + 51,5 : X = 62,5 c) 748 : ( X - 31,72 ) = 13,6
\(x\cdot1,5-5,61=6,45\)
\(x\cdot1,5=12,06\)
\(x=8,04\)
\(89:x+51,5:x=62,5\)
\(\left(89+51,5\right):x=62,5\)
\(140,5:x=62,5\)
\(x=2,248\)
\(748:\left(x-31,72\right)=13,6\)
\(x-31,72=55\)
\(x=86,72\)
Tìm x biết /x-1,5/=7,5-/2x-3/
/x-1,5/=7,5-/2x-3/ tim x
2,5-x=1,3
x-3,5=7,5
(x-1,5)-2,5=0
1,6-(x-0,2)=0
A=(3,7- -x)+2,5
B=(x+1,5)-4,5
a,2,5-x=1,3
x=2,5-1,3
x=1,2
b,x-3,5=7,5
x=7.5+3,5
x=11
c,(x-1,5)-2,5=0
x-1,5=2,5
x=2,5+1,5
x=4
d,1,6-(x-0,2)=0
x-0,2=1,6
x=1,6+0,2
x=1,8
A=(3,7- -x)+2,5
vì 2,5>=0 với mọi x
=> x=-1,2
B= (x+1,5)-4,5
Vì -4,5<=0 với mọi x
=> x=-6
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