\(\left(\frac{1}{4,5-1}-\frac{1}{7,5-2}\right):\frac{40}{77}\)
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\(\left(\frac{1}{4.5-1}-\frac{1}{7.5-2}\right):\frac{40}{77}\)
\(\left(\frac{1}{4\cdot5-1}-\frac{1}{7\cdot5-2}\right)\text{ : }\frac{40}{77}\)
\(=\left(\frac{1}{19}-\frac{1}{32}\right)\text{ : }\frac{40}{77}\)
\(=\frac{13}{608}\text{ : }\frac{40}{77}\)
\(=\frac{1001}{24320}\)
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1. tính nhanh :
\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{20}{31}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
2. Tính A = \(\left(\frac{7777}{8585}-\frac{77}{85}+\frac{7777}{16362}-\frac{77}{162}\right).\frac{123498766}{987661234}\)
Câu 1 có vế sau = 0
Câu 2 có vế trước = 0
Một biểu thức nhân với 0 thì = 0, nên:
=> kết quả hai bài đều = 0
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\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5
\)
=> \(\left(\frac{1}{4}x+\frac{5}{6}x-\frac{3}{8}x\right)-\left(1+2+1\right)=4,5\)
=>\(\frac{17}{24}x-4=4,5\)
=> \(\frac{17}{24}x=8,5\)
=> \(x=8,5:\frac{17}{24}\)
=> \(x=12\)
\(m=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(\frac{7}{3}+\frac{7}{2}\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}:\left(-\frac{43}{42}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}\cdot\left(-\frac{42}{43}\right)+\frac{15}{2}\)
\(M=\frac{35}{1}\cdot\left(-\frac{7}{43}\right)+\frac{15}{2}=-\frac{245}{43}+\frac{15}{2}=\frac{155}{86}\)
\(m=\left(\frac{7}{3}+3,5\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+7,5\)
\(m=\frac{35}{6}:-\frac{25}{6}+7,5\)
\(m=\frac{35}{6}.-\frac{6}{25}+7,5\)
\(m=-\frac{7}{5}+7,5\)
\(m=\frac{61}{10}\)
Bài 1: Tính a) left(frac{11}{12}:frac{44}{16}right)cdotleft(frac{-1}{3}+frac{1}{2}right) b) frac{left(-5^2right)cdotleft(-5right)^3cdot16}{5^4cdotleft(-2right)^4} c) 7,5:left(frac{-5}{3}right)+2frac{1}{2}:left(frac{-5}{3}right)d) left(frac{-1}{2}+frac{1}{3}right)cdotfrac{4}{5}+left(frac{2}{3}+frac{1}{2}right):frac{4}{5}
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Bài 1: Tính a) \(\left(\frac{11}{12}:\frac{44}{16}\right)\cdot\left(\frac{-1}{3}+\frac{1}{2}\right)\) b) \(\frac{\left(-5^2\right)\cdot\left(-5\right)^3\cdot16}{5^4\cdot\left(-2\right)^4}\) c) \(7,5:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\)d) \(\left(\frac{-1}{2}+\frac{1}{3}\right)\cdot\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right):\frac{4}{5}\)
a) \(\left(\frac{11}{12}:\frac{44}{16}\right).\left(\frac{-1}{3}+\frac{1}{2}\right)\) \(=\left(\frac{11}{12}.\frac{16}{44}\right).\left(\frac{-2}{6}+\frac{3}{6}\right)\) \(=\frac{1}{3}.\frac{1}{6}\) \(=\frac{1}{18}\)
b) \(\frac{\left(-5\right)^2.\left(-5\right)^3.16}{5^4.\left(-2\right)^4}\) \(=\frac{\left(-5\right)^5.2^4}{5^4.\left(-2\right)^4}\) \(=5\) (Có sửa đề lại, nếu có sai thì ib mình sửa lại nhé!)
c) \(7,5:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\) \(=\frac{15}{2}.\left(\frac{-3}{5}\right)+\frac{5}{2}.\left(\frac{-3}{5}\right)\) \(=\frac{-3}{5}.\left(\frac{15}{2}+\frac{5}{2}\right)\)
\(=\frac{-3}{5}.10\) \(=-6\)
d) \(\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right):\frac{5}{4}\) \(=\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right).\frac{4}{5}\)
\(=\frac{4}{5}.\left(\frac{-1}{2}+\frac{1}{3}+\frac{2}{3}+\frac{1}{2}\right)\) \(=\frac{4}{5}.\left(\frac{0}{2}+1\right)\) \(=\frac{4}{5}.1=\frac{4}{5}\)
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a) (1112:4416).(−13+12)(1112:4416).(−13+12) =(1112.1644).(−26+36)=(1112.1644).(−26+36) =13.16=13.16 =118=118
b) (−5)2.(−5)3.1654.(−2)4(−5)2.(−5)3.1654.(−2)4 =(−5)5.2454.(−2)4=(−5)5.2454.(−2)4 =5=
c) 7,5:(−53)+212:(−53)7,5:(−53)+212:(−53) =152.(−35)+52.(−35)=152.(−35)+52.(−35) =−35.(152+52)=−35.(152+52)
=−35.10=−35.10 =−6=−6
d) (−12+13).45+(23+12):54(−12+13).45+(23+12):54 =(−12+13).45+(23+12).45=(−12+13).45+(23+12).45
=45.(−12+13+23+12)=45.(−12+13+23+12) =45.(02+1)=45.(02+1) =45.1=45
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A=
\(\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(A=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(A=\left(\frac{7}{3}+3,5\right):\left(\frac{-25}{6}+\frac{22}{7}\right)+7,5\)
\(A=\frac{35}{6}:\frac{-43}{42}+7,5\)
\(A=\frac{-245}{43}+7,5\)
\(A=\frac{155}{86}\)
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Tính:
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
Bài 3: Thực hiện phép tính a) \(\left(\frac{2}{5}\right)^{^2}+5\frac{1}{2}:\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\) b) \(\left(\frac{2}{5}\right)^{^2}+5\frac{1}{2}:\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\)
Bài 3 :
\(a,\left(\frac{2}{5}\right)^2+5\frac{1}{2}:\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\)
\(=\frac{4}{25}+\frac{11}{2}:\frac{5}{2}+\frac{8}{\left(-4\right)}\)
\(=\frac{4}{25}+\frac{11}{5}-2\)
\(=\frac{59}{25}-2\)
\(=\frac{9}{25}\)
b, Giống câu a
Học tốt
\(A=-\frac{1}{2}\left(17,5-7,5\right)-\frac{2015}{2016}\left(2018-2\right)\)
=> \(A=-\frac{1}{2}\left(10\right)-\frac{2015}{2016}\left(2016\right)=-5-2015=-2020\)
Trả lời :
- 2 bn kia ở trong câu hỏi này có ai làm đúng đâu.
- Chúc bạn học tốt !
- Tk cho mk nha !