2332< 2333=(23)111=8111

3223>3222=(32)111=9111

mà 8<9

=> 2332<3223

đúng tk cho mik

Ta có: 2³³² = 2³³⁰⁺² = 2³³⁰ .2² = (2³)¹¹⁰.4= 8¹¹⁰ . 4

          3²²³ = 3²²⁰⁺³ = 3²²⁰ . 3³ =(3²)¹¹⁰ . 27=9¹¹⁰ . 27

Vì 8<9 , 4<27  => 8¹¹⁰< 9¹¹⁰

                       => 8¹¹⁰ . 4 < 9¹¹⁰ . 27

                       => 2³³² < 3²²³

Ta có:2³³²<2³³³= (2³)¹¹¹ =8¹¹¹

           3²²³>3²²²= (3²)¹¹¹ =9¹¹¹

Vì 8¹¹¹<9¹¹¹nên

2³³²<8¹¹¹<9¹¹¹<3²²³   => 2³³²< 3²²³

Vậy 2³³²< 3²²³ .

2³³²< 2³³³=(2³)¹¹¹=8¹¹¹

3²²³>3²²²=(3²)¹¹¹=9¹¹¹

mà 8<9

=> 2³³²<3²²³

2^332 < 2^333 =  (2^3)^111 = 8^111 < 9^111 = (3^2)^111 = 3^222 < 3^223

Có : 3²²³>3²²²=(3²)¹¹¹=9¹¹¹(1)

2³³²<2³³³=(2³)¹¹¹=8¹¹¹(2)

Từ (1);(2)

=> 3²²³>2³³²

Vì:

\(3^{223}>3^{222}=\left(3^2\right)^{111}=9^{111}\)

\(2^{332}< 2^{333}=\left(2^3\right)^{111}=8^{111}\)

\(\Rightarrow3^{223}>2^{332}\)

Có 3^223 >3^222=(3^2)^111=9^111

2^332<2^333=(2^3)^111=8^111

mà 9^111 > 8^111

suy ra 3^223 >2^332

Dấu ^ la luy thừa nha

2³³²=(2³)¹¹⁰x2²=8¹¹⁰x4

3²²³=(3²)¹¹⁰x3³=9¹¹⁰x27

Vì 9¹¹⁰x27 > 8¹¹⁰x4 =>2³³² < 3²²³

có thì giải làm gì mất công hả

2³³² < 2³³³ = (2³)¹¹¹ = 8¹¹¹

3²²³ > 3²²² = (3²)¹¹¹ = 9¹¹¹

Vì 8¹¹¹ < 9¹¹¹ => 2³³² < 3²²³