Ta có

y+30%.y=-1,3

=>y+0,3.y=-1,3

=>y.(1+0,3)=-1,3

=>y.1,3=-1,3

=>y=-1,3:1,3

=>y=-1

Ai tích mình mình tích lại cho

y+30%.y=-1,3

=>y+0,3.y=-1,3

=>y.(1+0,3)=-1,3

=>y.1,3=-1,3

=>y=-1,3:1,3

=>y=-1

y+30%y=-1,3

100%y+30%y=-1,3

130%y=-1,3

130/100*x=-1,3

x             =-1,3:130/100

x              =-1

không chắc đâu nha!

a)y+30%y=1,3

<=>1,3y=1,3

<=>y=1.

b)y+25%y=1/2

<=>1,25y=1/2

<=>y=0,4

Lời giải:

a. $y+30\text{%}y=-1,3$

$y+0,3y=-1,3$

$y(1+0,3)=-1,3$

$y.1,3=-1,3$

$y=(-1,3):1,3=-1$

b.

$y-25\text{%}y=\frac{1}{2}$

$y-0,25y=0,5$

$y(1-0,25)=0,5$

$y.0,75=0,5$

$y=0,5:0,75=\frac{2}{3}$

c.

\(3+\frac{1}{3}y+16+\frac{3}{4}=-13,25\)

$\frac{1}{3}y+19,75=-13,25$
$\frac{1}{3}y=-13,25-19,75=-33$
$y=-33:\frac{1}{3}=-99$

y=-1,3/(1+30%) tự tính :v

y= 1/2 : (1-25%) tự tính :3

sao 1+30% vay bn

a,y+30%y=-1,3

  y+3/10y=-1,3

y(1+3/10)=-1,3

y(10/10+3/10)=-1,3

13/10y=-13/10

y=-13/10:13/10

y=-1

Vậy y=-1

b,y-25%y=1/2

y-1/4y=1/2

y(1-1/4)=1/2

y(4/4-1/4)=1/2

3/4y=1/2

y=1/2:3/4

y=3/8

Vậy y=3/8

a/ y + 30%y = -1,3  

   => y + \(\frac{3}{10}\)y = -1,3

   => \(\frac{13}{10}\)y = -1,3

   => y = -1

b/ y - 25%.y = \(\frac{1}{2}\)

   => y - \(\frac{1}{4}\)y = \(\frac{1}{2}\)

   => \(\frac{3}{4}\)y = \(\frac{1}{2}\)  => y = \(\frac{2}{3}\)

a)\(y+30\%y=-1,3\)

\(y\frac{130}{100}=\left(-\frac{130}{100}\right)\)

\(y=\left(-\frac{130}{100}\right):\frac{130}{100}\)

\(y=-1\)

b)\(y-25\%y=\frac{1}{2}\)

\(y\frac{75}{100}=\frac{50}{100}\)

\(y=\frac{50}{100}:\frac{75}{100}\)

\(y=\frac{2}{3}\)