suy ra hai truong hop

1 : x-2011=x-2012

suy ra x-x=2011-2012(loai)

2 : x-2011=-(x-2012)

suy ra : x-2011=-x+2012                                

2x=2011+2012

2x=4023

x=2011.5

kho..................lam............................tich,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,minh..........................troi........................ret............................wa.................ung ho minh.................hu....................hu..............hu................hat..............hat....................s

Cau a biet lam roi de lam cau b cho:

Ta thay:tong 2 so hang do la tong 2 so tu nhien lien tiep nen se la so le (*) ma 2012 la so chan(trai voi "*")

=>Khong ton tai so nguyen x thoa man

Vay khong ton tai so nguyen x thoa man

/x-2011/ = x - 2012

<=>  x -2011 = x-2012 (1) hoặc  x-2011= - (x-2012)  (2)

từ (1) =>  x-2011 = x-2012

<=>            x-x   =  -2012+2011

<=>              0x  =  -1  (vô lí)

từ (2) =>  x-2011 = - ( x-2012)

 <=>        x-2011 =  -x + 2012

<=>           x+x   = 2012 + 2011

<=>             2x   =4023

<=>               x   =2011,5

a) \(\frac{x+4}{2009}+1+\frac{x+3}{2010}+1=\frac{x+2}{2011}+1+\frac{x+1}{2012}\)

\(\frac{x+4+2009}{2009}+\frac{x+3+2010}{2010}=\frac{x+2+2011}{2011}+\frac{x+2+2012}{2012}\)

\(\frac{x+2013}{2009}+\frac{x+2013}{2010}-\frac{x+2013}{2011}-\frac{x+2013}{2012}=0\)

\(\left(x+2013\right).\left(\frac{1}{2009}+\frac{1}{2010}-\frac{1}{2011}-\frac{1}{2012}\right)=0\)    (1)

Vì \(\left(\frac{1}{2009}+\frac{1}{2010}-\frac{1}{2011}-\frac{1}{2012}\right)\ne0\)

Nên biểu thức (1) xảy ra khi \(x+2013=0\)

\(x=-2013\)

b) \(\left(x-2011\right)\left(\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}-\frac{1}{2013}-\frac{1}{2014}\right)=0\)  (2)

Vì \(\left(\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}-\frac{1}{2013}-\frac{1}{2014}\right)\ne0\)

Nên biểu thức (2) xảy ra khi \(x-2011=0\)

\(x=2011\)

a, Đ/k x-2012>=0 suy ra x>=2012

|x-2011|=\(\orbr{\begin{cases}x-2012\\2012-x\end{cases}}\)

TH1:x-2011=x-2012

suy ra 0=4023(loại vì mất x)

TH2: x-2011=2012-x

suy ra 2x=4023

suy ra x=2011,5

Vậy..........

k o  b i ế t  n h a

Hoàng Khôi Phong ( ɻɛɑm ʙáo cáo ) ko nói linh tinh mk sẽ tặng bạn một vé báo cáo siêu vip nhé=)))

(x + 4)/2010 + (x+3)/2011 = (x+2)/2012 + (x+1)/2013 

<=> [(x + 4)/2010 + 1] + [(x+3)/2011 + 1] = [(x+2)/2012 + 1] + [(x+1)/2013 + 1] 

<=> (x + 2014)/2010 + (x + 2014)/2011 = (x + 2014)/2012 + (x + 2014)/2013 

<=> (x + 2014)/2010 + (x + 2014)/2011 - (x + 2014)/2012 - (x + 2014)/2013 = 0 

<=> (x + 2014).(1/2010 + 1/2011 - 1/2012 - 1/2013) = 0 

Ta thấy (1/2010 + 1/2011 - 1/2012 - 1/2013) ≠ 0 

Vậy suy ra x = -2014

đúng ko các bạn 

chac the