\(\frac{4y}{3}+\frac{2y}{3}+8y=150\)

\(\frac{6y}{3}+8y=150\)

\(2y+8y=150\)

\(10y=150\)

\(y=15\)

vậy \(y=15\)

 y x (4/3+2/3+8)=150

 y x 10 = 150

 y = 150 : 10 = 15

k mk nha

\(y:3.4+y:3.2+y.8=150\)

\(\frac{4y}{3}+\frac{2y}{3}+8y=150\)

\(\frac{6y}{3}+8y=150\)

\(2y+8y=150\)

\(10y=150\)

\(y=15\)

a) 2y - 12y = 0

\(\Rightarrow\) y ( 2-12) = 0

\(\Rightarrow\) y . (-10) =0 

\(\Rightarrow\) y = 0 : (-10) = 0

b) (y-7)(y-8) = 0

\(\Rightarrow\orbr{\begin{cases}y-7=0\\y-8=0\end{cases}\Rightarrow\orbr{\begin{cases}y=0+7\\y=0+8\end{cases}\Rightarrow}\orbr{\begin{cases}y=7\\y=8\end{cases}}}\)

c) x + x.2+x.3+x.4+...+x.10 = 165

\(\Rightarrow\) x ( 1+2+3+.....+8+9+10) = 165

\(\Rightarrow\)x . \(\frac{\left(1+10\right).10}{2}\)=165

\(\Rightarrow\) x . 55 = 165

\(\Rightarrow x=\frac{165}{55}=3\)

Can you k for me ,Lê Thị Kim Chi!

a) \(2y-12y=0\)

\(\Leftrightarrow-10y=0\)

\(\Leftrightarrow y=0:\left(-10\right)\)

\(\Leftrightarrow y=0\)

b) \(\left(y-7\right)\left(y-8\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}y-7=0\\y-8=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}y=0+7\\y=0+8\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}y=7\\y=8\end{cases}}\)

c) \(x+x.2+x.3+......+x.10=165\)

\(\Leftrightarrow x.\left(1+2+3+.....+10\right)=165\)

\(\Leftrightarrow x.55=165\)

\(\Leftrightarrow x=165:55\)

\(\Leftrightarrow x=3\)

bài 1 : a,ta có 3/x-1 =4/y-2=5/z-3 =>  x-1/3=y-2/4=z-3/5 

áp dụng .... => x-1+y-2+z-3 / 3+4+5 = x+y+z-1-2-3/3+4+5 = 12/12=1

do x-1/3 = 1 => x-1 = 3 => x= 4 ( tìm y,z tương tự

Bài 1: 

a) Ta có: 3/x - 1 = 4/y - 2 = 5/z - 3 => x - 1/3 = y - 2/4 = z - 3/5 áp dụng ... =>x - 1 + y - 2 + z - 3/3 + 4 + 5 = x + y + z - 1 - 2 - 3/3 + 4 + 5 = 12/12 = 1 do x - 1/3 = 1 => x - 1 = 3 => x = 4 ( tìm y, z tương tự )

cũng dễ thôi

Bài 1:

a) \(=\dfrac{8}{15}\left(\dfrac{7}{13}+\dfrac{6}{13}\right)=\dfrac{8}{15}.1=\dfrac{8}{15}\)

b) \(=\dfrac{3.3-7-2.4}{12}=-\dfrac{6}{12}=-\dfrac{1}{2}\)

Bài 2:

 \(\dfrac{x}{2,7}=-\dfrac{2}{3,6}\Rightarrow x=\dfrac{\left(-2\right).2,7}{3,6}\Rightarrow x=-\dfrac{3}{2}\)

Bài 3:

\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=-\dfrac{21}{7}=-3\)

\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).2=-6\\y=\left(-3\right).5=-10\end{matrix}\right.\)

 y : 3 . 4 + y : 3 . 2 + y . 8 = 150

4/3y + 2/3y + 8y = 150

10y = 150

y = 150 : 10

y = 15

y : 3 x 4 + y : 3 x 2 + y x 8 = 150

y x 1/12 + y x 1/6 + y x 8   = 150

y x ( 1/12 + 1/6 + 8 )          = 150

y x 8.25                              = 150

y                                         = 150 : 8.25

y                                         = 18,(18)

1.\(\frac{x}{y}=\frac{2}{3}\Rightarrow\frac{x}{2}=\frac{y}{3}\Rightarrow\hept{\begin{cases}\frac{x}{2}.\frac{y}{3}=\frac{54}{6}=9\\\frac{x}{2}.\frac{y}{3}=\left(\frac{x}{2}\right)^2=\left(\frac{y}{3}\right)^2\end{cases}\Rightarrow\left(\frac{x}{2}\right)^2}=\left(\frac{y}{3}\right)^2=9\Rightarrow\orbr{\begin{cases}\frac{x}{2}=\frac{y}{3}=3\\\frac{x}{2}=\frac{y}{3}=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=6;y=9\\x=-6;y=-9\end{cases}}}\)

2.\(x:y:z=3:8:5\Rightarrow\frac{x}{3}=\frac{y}{8}=\frac{z}{5}=\frac{3x}{9}=\frac{2z}{10}=\frac{3x+y-2z}{9+8-10}=\frac{14}{7}=2\Rightarrow\hept{\begin{cases}x=2.3=6\\y=2.8=16\\z=2.5=10\end{cases}}\)

`7/2 : y= 3/8 + 5/4`

`=> 7/2 : y= 3/8 +10/8`

`=> 7/2 : y=13/8`

`=> y= 7/2 : 13/8`

`=> y= 7/2 xx 8/13`

`=> y= 28/13`

\(\dfrac{7}{2}:y=\dfrac{3}{8}+\dfrac{5}{4}\)
\(\dfrac{7}{2}:y=\dfrac{13}{8}\)
\(y=\dfrac{7}{2}:\dfrac{13}{8}\)
\(y=\dfrac{7}{2}\times\dfrac{8}{13}\)
\(y=\dfrac{28}{13}\)

A) x/y-3/8=1                  x/y-3/8=1/2                          B)4/9:x/y=1                                                    4/9:x/y=2/3 

x/y=1+3/8                     x/y=1/2+3/8                                   x/y=4/9:1                                                    x/y=4/9:2/3

x/y=8/8+3/8                  x/y=4/8+3/8                                   x/y=4/9                                                       x/y=2/3

x/y=11/8                       x/y=7/8

a   x/y=1 và 1/2+3/8

x/y=15/8

b   x/y=4/9:1 và 2/3

x/y=4/15

Ủa cái này đâu phải tiếng việt?